Hide duplicate row and analytic functions

Question

Hi all,
I have to count how many customers have two particular product on the same area.
Table cols are:
AREA
PRODUCT_CODE (PK)
CUSTOMER_ID (PK)
QTA
The query is:
select distinct area, count(customer_id) over(PARTITION BY area)
from all_products
where product_code in ('BC01007', 'BC01004')
group by area, customer_id
having ( sum(decode(FPP.PRODOTTO_CODE,'BC01007',qta,0)) ) > 0)
and ( sum(decode(FPP.PRODOTTO_CODE,'BC01004',qta,0)) ) > 0);
In SQL*PLUS works fine, but in Oracle Discoverer I can't get distinct results also if I chek "Hide duplicate rows" in Table Layout .
Anybody have another way to get distinct results for analytic function results?
Thanks in advance,
Giuseppe

Answer 1

The query in Disco is exactly that I've post before.
Results are there:
AREA.........................................C1
01704 - AREA VR NORD..............3
01704 - AREA VR NORD..............3
01704 - AREA VR NORD..............3
01705 - AREA VR SUD.................1
02702 - AREA EMILIA NORD........1
If I check "hide duplicate row" in layout option results didn't change.
If I add distinct clause manually in SQL*PLUS the query become:
SELECT distinct o141151.AREA as E141152,COUNT(o141151.CUSTOMER_ID) OVER(PARTITION BY o141151.AREA ) as C_1
FROM BPN.ALL_PRODUCTS o141151
WHERE (o141151.PRODUCT_CODE IN ('BC01006','BC01007','BC01004'))
GROUP BY o141151.AREA,o141151.CUSTOMER_ID
HAVING (( SUM(DECODE(o141151.PRODUCT_CODE,'BC01006',1,0)) ) > 0 AND ( SUM(DECODE(o141151.PRODUCT_CODE,'BC01004',1,0)) ) > 0)
and the results are not duplicate.
AREA.........................................C1
01704 - AREA VR NORD..............3
01705 - AREA VR SUD.................1
02702 - AREA EMILIA NORD........1
There is any other way to force distinct clause in Discoverer?
Thank you
Giuseppe