How Can I create a database?

How can I create a database to store registered members info
(member id, password and other information?) I have the scripts for
member login, member signup, etc.. I understand that I will have to
deploy the database, once it is created, in the same folder where I
have all other scripts (PHP.)
Thank you, in advance.

Hey,
basically you should start with an empty SharePoint 2010 project where you add an List-EventReceiver. This Receiver should point to the url of the list and handle the ItemAdded-Event. In this method you place the code to create the database, for example
with a SQL-Statement.

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thanks.

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Hey,
basically you should start with an empty SharePoint 2010 project where you add an List-EventReceiver. This Receiver should point to the url of the list and handle the ItemAdded-Event. In this method you place the code to create the database, for example
with a SQL-Statement.

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Hi,
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Hi,
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mysql>
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How can I create an csv/excel file using pl/sql and then sending that file to a clients site using pl/sql?
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{message:id=9360007}
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How can i create datasource on apache server for ADF application?

Hi All,
i my use case i have created simple adf application using ADF BC and want to deploy on Apache server 6.x.
So my question is that how can i create Data Source i have goggling and find two different way to do this.
1. write following line of code on apache server conf/Context.xml file.
<Resource name="jdbc/TestDB" auth="Container"
              type="javax.sql.DataSource"
               driverClassName="oracle.jdbc.OracleDriver"
              url="jdbc:oracle:thin:@localhost:dst"
              username="jagrandb" password="jagrantest" maxActive="20" maxIdle="10"
              maxWait="-1"/>
but when i have used this way i got following exception.
org.apache.tomcat.dbcp.dbcp.PoolingDataSource$PoolGuardConnectionWrapper cannot be cast to oracle.jdbc.OracleConnection
check link-
https://forums.oracle.com/thread/2564233
2. write following line of code apache conf/Server.xml file
<GlobalNamingResources>
    
    <Resource name="UserDatabase" auth="Container"
              type="org.apache.catalina.UserDatabase"
              description="User database that can be updated and saved"
              factory="org.apache.catalina.users.MemoryUserDatabaseFactory"
              pathname="conf/tomcat-users.xml" />
<Resource name="jdbc/TestDB" auth="Container"
              type="oracle.jdbc.pool.OracleDataSource"
              description="User database that can be updated and saved"
              driverClassName="oracle.jdbc.driver.OracleDriver"
              factory="oracle.jdbc.pool.OracleDataSourceFactory"
              url="jdbc:oracle:thin:@//172.31.43.207:1521:dst"
              username="jagrandb" password="jagrantest" maxActive="20" maxIdle="10"
              maxWait="-1"   />
</GlobalNamingResources>
and add this line in context.xml file inside <context> tag
<ResourceLink global="jdbc/TestDB" name="jdbc/TestDB" type="oracle.jdbc.pool.OracleDataSource"/>
but when i have run application i have got following error
log-
javax.servlet.jsp.JspException: Unable to get connection, DataSource invalid: "java.sql.SQLException: invalid arguments in call"
at org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.getConnection(QueryTagSupport.java:298)
at org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.doStartTag(QueryTagSupport.java:181)
at org.apache.jsp.test_jsp._jspx_meth_sql_005fquery_005f0(test_jsp.java:110)
at org.apache.jsp.test_jsp._jspService(test_jsp.java:63)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286)
at org.apache.coyote.http11.Http11AprProcessor.process(Http11AprProcessor.java:857)
at org.apache.coyote.http11.Http11AprProtocol$Http11ConnectionHandler.process(Http11AprProtocol.java:565)
at org.apache.tomcat.util.net.AprEndpoint$Worker.run(AprEndpoint.java:1509)
at java.lang.Thread.run(Thread.java:662)
Aug 2, 2013 5:17:21 PM org.apache.catalina.core.StandardWrapperValve invoke
SEVERE: Servlet.service() for servlet jsp threw exception
javax.servlet.jsp.JspException: Unable to get connection, DataSource invalid: "java.sql.SQLException: invalid arguments in call"
at org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.getConnection(QueryTagSupport.java:298)
at org.apache.taglibs.standard.tag.common.sql.QueryTagSupport.doStartTag(QueryTagSupport.java:181)
at org.apache.jsp.test_jsp._jspx_meth_sql_005fquery_005f0(test_jsp.java:110)
at org.apache.jsp.test_jsp._jspService(test_jsp.java:63)
at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374)
at org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:342)
at org.apache.jasper.servlet.JspServlet.service(JspServlet.java:267)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:128)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:286)
at org.apache.coyote.http11.Http11AprProcessor.process(Http11AprProcessor.java:857)
at org.apache.coyote.http11.Http11AprProtocol$Http11ConnectionHandler.process(Http11AprProtocol.java:565)
at org.apache.tomcat.util.net.AprEndpoint$Worker.run(AprEndpoint.java:1509)
at java.lang.Thread.run(Thread.java:662)
so what is the solution how to create datasource on apche server which suitable for adf application?
when i test data source using following code used 1. way as i mentioned above its running fine bt not for second.
<%@ taglib uri="http://java.sun.com/jsp/jstl/sql" prefix="sql" %>
<%@ taglib uri="http://java.sun.com/jsp/jstl/core" prefix="c" %>
<sql:query var="rs" dataSource="jdbc/TestDB">
select empname from pay_emphdr where empcd='JK1306'
</sql:query>
<html>
<head>
    <title>DB Test</title>
</head>
<body>
<h2>Results</h2>
<c:forEach var="row" items="${rs.rows}">
    Foo ${row.empname}<br/>
</c:forEach>
</body>
</html>
please help me. it is very urgent.
thanks in Advance
Manish

Hi Lindalnci
i have already tried this tutorial and in my post i have defined first way to do using this procedure.
in that case i have got following exception as i have mentioned above
org.apache.tomcat.dbcp.dbcp.PoolingDataSource$PoolGuardConnectionWrapper cannot be cast to oracle.jdbc.OracleConnection

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My application will work with Win 95 and 98?
Thanks.

Oracle9i Forms is web-only. Forms 6i is the last release of Forms to have client/server and character mode.
You can test Forms from the Builder by installing iDS. To deploy Forms using iAS follow the documentation. It's all there in the deployment guide.
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How can I create a new entry without using LOV for foreign keys.

Referring to TUHRA sample application based on HR database schema. JDeveloper 10.1.3.0.4
How can I create a new employee without using LOV for the foreign key "job_id".
On the first page I would like to choose the job_title from adf read-only table.
After clicking on the "create new employee button" a creation form appears in which the job_id field is set with previous selection.
Regards M.Winkler
Edited by: user3541283 on 06.10.2008 03:44
Edited by: user3541283 on 06.10.2008 03:50

Hi,
usually the foreign key is only set if the VO you select is dependent from a master. If e.g. you have DepartmentsVO1 that has an EmployeeVO3 as its nested VO, then creating a new instance of employees automatically add the foreign key. If you add EmployeesVO1, which is not dependent to DepartmensVO1, then the foreign key is not set. So if this is the case in THURA (keep in mind that this is not an Oracle demo but a sample used in a book about ADF) then all you need is to take the independent VO when building the new employee form.
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How can i create a new user with only read rights ?

How can i create a new user with only read rights ?

You are asking about a Database User I hope.
You can look into the Oracle 8i Documentation and find various privillages listed.
In particular, you may find:
Chapter 27 Privileges, Roles, and Security Policies
an intresting chapter.
You may want to do this with the various tools included with 8i - including the
Oracle DBA Studio - expand the Security node and you can create USERS and ROLES.
Or use SQL*Plus. To create a
user / password named John / Smith, you would login to SQL*Plus as System/manager (or other) and type in:
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commit;
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depending on your needs.
Please read the documentation.
-John
null

How Can I create a database?

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