How can I get a container to be the same size as all its children

Question

In my TitleWindow, I have two children that size themselves
dynamically.
No problem, TitleWindow also sizes itself to completely show
both children.
Now I have an additional child that I can only position
correctly if I set TitleWindow's layout parameter to absolute.
The third child now positions itself correctly on top of the
first child.
But now TitleWindow is only as big as the first child and I
have to scroll to see the second child.
How can I force TitleWindow to be the size it was when layout
was set to vertical?
Doug

Answer 1

Hi Doug - What exactly are you trying to do? Is the third
child being added dynamically, and you want it added above the
first child? If so, you can use the addChildAt() method when adding
the child to the container. addChildAt() takes an index and the
child object is added at that index and all other children are
reshuffled to maintain the ordering. IE:
<?xml version="1.0" encoding="utf-8"?>
<mx:Application xmlns:mx="
http://www.adobe.com/2006/mxml"
layout="vertical">
<mx:TitleWindow layout="vertical" id="tw">
<mx:Button id="a" />
<mx:Button id="b" click="go();"/>
</mx:TitleWindow>
<mx:Script>
<![CDATA[
private function go():void
var c:Button = new Button();
c.label="new";
tw.addChildAt(c, 0);
]]>
</mx:Script>
</mx:Application>
Does that help, or am I misinterpreting what you're trying to
do?