How do count how many 'A' s in this string using sql stmt?

Question

hi all,
i have a string like 'AAAAARAMAAAAKRISHNAAAA'.
in this ,i want to find out how many 'A's .
how do find out this using select stmt.

Answer 1

(length(s) - nvl(length(replace(s, 'A')), 0)) / length('A')but consider (by modifying the question slightly to "how do count how many 'AA' s in this string using sql stmt? ")
SQL>  select (length('AAAAARAMAAAAKRISHNAAAA') - nvl(length(replace('AAAAARAMAAAAKRISHNAAAA', 'AA')), 0)) / length('AA') x from dual
         X
         6
1 row selected.couldn't I argue that the result should be 10 as e.g. in
SQL>  select * from xmltable('let $str := "AAAAARAMAAAAKRISHNAAAA"
                        let $search := "AA"
                        for $i in 1 to string-length($str)
                          where substring($str, $i, string-length($search)) = $search
                          return substring($str, $i, string-length($search))' columns x varchar2(10) path '.')
X        
AA       
AA       
AA       
AA       
AA       
AA       
AA       
AA       
AA       
AA       
10 rows selected.Matter of definition I suppose .... ;)
btw. regexp_count also yields 6:
SQL>  select regexp_count('AAAAARAMAAAAKRISHNAAAA', 'AA') x from dual
         X
         6
1 row selected.