How do I swap 64-bit and 32-bit floats from little-endian to big-ending

I am trying to read a file that could contain a list of 64-bit floats or 32-bit floats that were written on a PC so they are little-endian.
I need to convert the float values to big-endian so that I can process the values. I know that straight swapping each byte with the adjacent byte doesn't work (especially since their floating point values). I've tried swapping them end for end (i.e., byte 15 from the file becomes byte 0 in my array) and that didn't work either.
I know that if I were to read the little-endian float into the big-endian float type (float or double) that the format is pretty much lost (from little I understand about how floating point values are stored in memory).
So, what I need is a way to read in a series of little-endian floating point values (64-bit and 32-bit) into a big-endian array of floating point values.
Anyone have any ideas on how to do this? Any help would be much appreciated.

A 64-bit double is represented by the sign bit, an 11-bit (biased) exponent
followed by a 52-bit mantissa. Both x86 and SPARC use the exact same
representation for 64-bit double. The only difference is the endianness
when stored to memory, as you observed.
A 32-bit float is represented by the sign bit, an 8-bit (biased) exponent
followed by a 23-bit mantissa. Again, both x86 and SPARC use the exact
same representation for 32-bit float modulo endianness.
As you can see, a 64-bit double is not merely a pair of 32-bit float.
You need to know exactly how the floating-point data was written:
if a 32-bit float was written, you must endian-swap it as a 32-bit float;
if a 64-bit double was written, you must endian-swap it as a 64-bit double.

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[Attachment DebugExtraResults.seq, see below]
Attachments:
DebugExtraResults.seq ‏20 KB

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