How is the Login-validation.xml file is called when we do the validation i

Hi ^^,
please forgive me if I am a big long while explaining.
when you are using the struts 2.0 the web.xml has a welcome-file-list. I have put index.html in that list so it pulls up first.
It has the following tag
<ul>
          <li><a href="roseindia/showLoginClientSideValidation.action">Login Application (Client Side Validation)</a></li>
        </ul>so this maps to struts.xml which contains the showLoginClientSideValidation.action tag
<action name="showLoginClientSideValidation">
               <result>/pages/loginClientSideValidation.jsp</result>
        </action>
        <action name="doLoginClientSideValidation" class="net.roseindia.Login">
            <result name="input">/pages/loginClientSideValidation.jsp</result>
               <result name="error">/pages/loginClientSideValidation.jsp</result>
               <result>/pages/Loginsuccess.jsp</result>
        </action>
          this displays the jsp "loginClientSideValidation.jsp"
once you enter the details in the jsp and click submit the control goes to Login.java file as per the mapping in struts.xml given above
This is just a simple java file which contains the execute() method. This method returns success or error.
If success is returned then the Loginsuccess.jsp is invoked
If error is returned then the loginClientSideValidation.jsp is invoked
Well so far so good
I have also understood that to use client side validation you use validate = "true" in loginClientSideValidation.jsp
However what I am not able to understand is how the Login-validation.xml file is being invoked
Any help would be highly appreciated.
thanks and regards,

Hi ^^^,
i found something interesting that I want to share
Validation rules are handled by validators, which must be registered with the ValidatorFactory (using the registerValidator method). The simplest way to do so is to add a file name validators.xml in the root of the classpath (/WEB-INF/classes) that declares all the validators you intend to use.
validators.xml if being defined should be available in the classpath. However this is not necessary, if no custom validator is needed. Webwork will automatically picked up a predefined sets of validators defined in com/opensymphony/xwork/validator/validators/default.xml packaged together in xwork jar file that comes with webwork distribution.
So this is clear that the validators are defined in validators.xml or default.xml
What is still not clear is how is the Login-validation.xml being called by jsp page to do verification and then linking to validators.xml to apply the rules.
However people have been telling me that ----" Struts 2.0 have inbuilt functionalities to validate the Parameters" and that i need to
"Define configuration file *-validation.xml or use annotations
i) className-validation.xml
ii) place this file in the directory where .class file is placed example.Login should have Login-validation.xml
Do you all think is this sufficient for an answer or should my search go on?
thanks and regards,
Prashant
Edited by: pksingh79 on Sep 13, 2008 10:08 AM

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the element (sage) is present or not in the following xml file XPATH expression...
* I have tried by the following expression ,
NodeList result = (NodeList) xpath.evaluate("//*:student/*:sage/text()",xml_dom,XPathConstants.STRING);
System.out.println(result.item(0).getLocalName()); * I want to get the Element sage as String value....
but i am not able to get the element,why that ??? and How to do that ???
MyXML File :
<x:student>
<x:sname>aaa</x:sname>
<x:sage>26</x:sage>
</x:student>
Thanks,
JavaImran

<code>* Thanks for reply....
* </code><code>In </code>
<code>x:student element x represents the namespace...thats why i put *:student in my expression....
"//*[local-name() = 'student']/*[local-name() = 'sage']/text()"* By the above code , i am not able to get the sage as string from
</code> resul.item(0).getLocalName() method.......?
* How to get that as string format ?

When I try to open a file I created in Pages, I get this: "The required index.xml file is missing." This has happened many times and I have forgotten how I've worked around it.

When I try to open a file I created in Pages, I get this: "The required index.xml file is missing."
This has happened many times and I have forgotten how I've worked around it.

That is wrong advice and you appear to have repeated it all over the forum.
All Pages files no matter what version have the same file extension, .pages, despite being radically different formats and that is the problem. The System does not distinguish between them when you double click on the file, it opens the first version of Pages it encounters.
You need to right click on the file and choose the correct App version for the file. Unfortunately there are no clues to tell you which is which.
If you are unhappy with this and the removal of over 100 features plus the problems with transmitting files across devices, servers and different versions of OS X, rate/review Pages 5.5.2 in the App Store.
Peter

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One way to encode "contants" in a WSDL is in a referenced schema, using an enumeration restriction, viz:
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This is my code
I want to set update the values in xml file using transformer..
Any one can help me
This is my Xml file
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<place>
<name>chennai</name>
</place>
Jsp Page
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<%@page pageEncoding="UTF-8"%>
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NodeList nlst = doc.getElementsByTagName("name");
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This example uses JSTL, uncomment the taglib directive above.
To test, display the page like this: index.jsp?sayHello=true&name=Murphy
--%>
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