How seek method works actually??

Question

Hi,
i am not able to understand how seek method works in java.
plz make me clear on this method..
seek(pos)
The position in the file where the next read or write operation will occur.
But it operates entirely different in the following code. only when i put the value as 5 , it prints the value of 7890. if i pass anything other than that, it would return some values which were not written.
import java.io.*;
public class TestIPApp {
public static void main(String args[]) throws IOException {
RandomAccessFile file = new RandomAccessFile("c:\\test.txt", "rw");
file.writeBoolean(true);
file.writeInt(123456);
file.writeInt(7890);
file.writeLong(1000000);
file.writeInt(777);
file.writeFloat(.0001f);
file.seek(9);
System.out.println(file.readInt());
file.close();
}when i open the test.txt file, it contains some junk values. how could i see this txt file in readable format?
plz help me

Answer 1

Pannar wrote:
only when i put the value as 5 , it prints the value of 7890.Makes sense to me. You write a boolean, then an int. Boolean values are written [in one byte|http://java.sun.com/javase/6/docs/api/java/io/RandomAccessFile.html#writeBoolean(boolean)], int values are written [in four bytes|http://java.sun.com/javase/6/docs/api/java/io/RandomAccessFile.html#writeInt(int)]. Positioning the file pointer to the fifth byte gets ready to read the next int value.
In your code, however, you move the pointer to the ninth byte, which is the start of what you wrote as a long value. So, this code...System.out.println(file.readInt());...should be this:System.out.println(file.readLong());
Pannar wrote:how could i see this txt file in readable format? Write text rather than data.
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