How set Image Source with C#

Question

Hi,
In C# I use FileOpenPicker to select the test.jpg, But it can't display the test.jpg.
1. C#
private async void button_addImage_Click(object sender, RoutedEventArgs e)
FileOpenPicker fileOpenPicker = new FileOpenPicker();
//fileOpenPicker.ViewMode = PickerViewMode.List;
fileOpenPicker.ViewMode = PickerViewMode.Thumbnail;
fileOpenPicker.SuggestedStartLocation = PickerLocationId.ComputerFolder;
fileOpenPicker.FileTypeFilter.Add(".jpg");
fileOpenPicker.FileTypeFilter.Add(".jpeg");
fileOpenPicker.FileTypeFilter.Add(".png");
StorageFile file = await fileOpenPicker.PickSingleFileAsync();
if (file != null)
Uri uri = new Uri(file.Path, UriKind.RelativeOrAbsolute);
image_show.Source = new BitmapImage(uri);
button_addImage.Visibility = Visibility.Collapsed;
2. XAML
<Grid Background="Orange" VerticalAlignment="Stretch">
<!-- Source="ms-appx:///Assets/test.jpg" this is OK -->
<Image x:Name="image_show" HorizontalAlignment="Stretch" VerticalAlignment="Stretch" Stretch="Uniform"/> <Button x:Name="button_addImage" Content="+" Click="button_addImage_Click">
</Grid>

Answer 1

Your app doesn't have access to the path the user picked. It needs to use the StorageFile returned from PickSingleFileAsync rather than bypassing it and going directly to the path. I discuss this in more detail in my blog entry at
http://blogs.msdn.com/b/wsdevsol/archive/2012/12/05/stray-from-the-path-stick-to-the-storagefile.aspx .
Open the StorageFile with StorageFile.OpenAsync then pass that stream to
BitmapImage.SetSourceAsync. See the code snippet in the docs for an example.