How this query can be reduced
Hi all,
I have placed some repeating conditions in many places of the query , Please suggest me to reduce the size of the query .
SELECT (CASE
WHEN prs.rqst_ctgry_lkpcd <> 'AR'
AND prp.x12_code_list_qlfr_lkpcd <> 'HC'
THEN prp.x12_code_list_qlfr_lkpcd
END
) x12_code_list_qlfr_lkpcd,
(CASE
WHEN prs.rqst_ctgry_lkpcd <> 'AR'
AND prp.x12_code_list_qlfr_lkpcd <> 'HC'
THEN (SELECT prcdr_code
FROM PROCEDURE
WHERE procedure_iid = prp.procedure_iid) end) procedure_iid,
(CASE
WHEN prs.rqst_ctgry_lkpcd <> 'AR'
AND prp.x12_code_list_qlfr_lkpcd <> 'HC'
THEN prp.mdfr_code end) mdfr_code, (CASE
WHEN prs.rqst_ctgry_lkpcd <> 'AR'
AND prp.x12_code_list_qlfr_lkpcd <> 'HC'
THEN prp.mdfr2_code end) mdfr2_code,
(CASE
WHEN prs.rqst_ctgry_lkpcd <> 'AR'
AND prp.x12_code_list_qlfr_lkpcd <> 'HC'
THEN prp.mdfr3_code end) mdfr3_code, (CASE
WHEN prs.rqst_ctgry_lkpcd <> 'AR'
AND prp.x12_code_list_qlfr_lkpcd <> 'HC'
THEN prp.mdfr4_code end) mdfr4_code,
(CASE
WHEN prs.rqst_ctgry_lkpcd <> 'AR'
AND prp.x12_code_list_qlfr_lkpcd <> 'HC'
THEN prp.drug_desc end) drug_desc, (CASE
WHEN prs.rqst_ctgry_lkpcd <> 'AR'
AND prp.x12_code_list_qlfr_lkpcd <> 'HC'
THEN prsi.sv308 end) product_service_id,
(CASE
WHEN prs.rqst_ctgry_lkpcd <> 'AR'
AND prp.x12_code_list_qlfr_lkpcd <> 'HC'
THEN
(CASE
WHEN LENGTH (SUBSTR (prpt.rqst_prcdr_amt,
INSTR (prpt.rqst_prcdr_amt, '.', 1, 1),
1
) = 1
THEN prpt.rqst_prcdr_amt || '0'
ELSE prpt.rqst_prcdr_amt || ''
END
) end) rqst_prcdr_amt,
prp.oral_cavity_dsgntn2_cid oral_cavity_dsgntn2_cid,
prp.oral_cavity_dsgntn3_cid oral_cavity_dsgntn3_cid,
prp.oral_cavity_dsgntn4_cid oral_cavity_dsgntn4_cid,
prp.oral_cavity_dsgntn5_cid oral_cavity_dsgntn5_cid,
prp.prosthesis_crown_inlay_code prosthesis_crown_inlay_code,
(CASE
WHEN prs.rqst_ctgry_lkpcd <> 'AR'
AND prp.x12_code_list_qlfr_lkpcd <> 'HC'
THEN prpt.rqst_prcdr_units end) rqst_prcdr_units, prp.remark remark
FROM (SELECT pa_rqst_sid,
MAX (DECODE (meta_data_cid, 9715, data_value, '')) sv308
FROM pa_request_situational
GROUP BY pa_rqst_sid) prsi,
pa_transaction_request ptr,
input_acknwldgmnt ia,
input_batch_file ibf,
pa_request pr,
pa_request_service prs,
pa_request_procedure prp,
pa_rqst_prcdr_transaction prpt
WHERE ptr.input_acknwldgmnt_sid = ia.input_acknwldgmnt_sid
AND ia.input_batch_file_sid = ibf.input_batch_file_sid
AND ptr.pa_trnsctn_rqst_sid = pr.pa_trnsctn_rqst_sid
AND pr.pa_rqst_sid = prs.pa_rqst_sid
AND prs.pa_rqst_srvc_sid = prp.pa_rqst_srvc_sid
AND prp.pa_rqst_prcdr_sid = prpt.pa_rqst_prcdr_sid
AND pr.pa_rqst_sid = prsi.pa_rqst_sid
AND pr.oprtnl_flag = 'A'
AND prs.oprtnl_flag = 'A'
AND ptr.oprtnl_flag = 'A'
AND prp.oprtnl_flag = 'A'
AND prpt.oprtnl_flag = 'A'
AND ibf.original_file_name =?
Thanks,
P Prakash
A few days ago, you were already suggested to use the WITH statement.
Did you try using the WITH statement?
Sybrand Bakker
Senior Oracle DBA
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Can you please explain how this query is fetching the rows?
here is a query to find the top 3 salaries. But the thing is that i am now able to understand how its working to get the correct data :How the data in the alias table P1 and P2 getting compared. Can you please explain in some steps.
SELECT MIN(P1.SAL) FROM PSAL P1, PSAL P2
WHERE P1.SAL >= P2.SAL
GROUP BY P2.SAL
HAVING COUNT (DISTINCT P1.SAL) <=3 ;
here is the data i used :
SQL> select * from psal;
NAME SAL
able 1000
baker 900
charles 900
delta 800
eddy 700
fred 700
george 700
george 700
Regards,
Renu... Please help me in understanding the query.
Your query looks like anything but a Top-N query.
If you run it in steps and analyze the output at the end of each step, then you should be able to understand what it does.
Given below is some brief information on the same:
test@ora>
test@ora> --
test@ora> -- Query 1 - using the non-equi (theta) join
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT p1.sal AS p1_sal, p1.NAME AS p1_name, p2.sal AS p2_sal,
12 p2.NAME AS p2_name
13 FROM psal p1, psal p2
14 WHERE p1.sal >= p2.sal;
P1_SAL P1_NAME P2_SAL P2_NAME
1000 able 1000 able
1000 able 900 baker
1000 able 900 charles
1000 able 800 delta
1000 able 700 eddy
1000 able 700 fred
1000 able 700 george
1000 able 700 george
900 baker 900 baker
900 baker 900 charles
900 baker 800 delta
900 baker 700 eddy
900 baker 700 fred
900 baker 700 george
900 baker 700 george
900 charles 900 baker
900 charles 900 charles
900 charles 800 delta
900 charles 700 eddy
900 charles 700 fred
900 charles 700 george
900 charles 700 george
800 delta 800 delta
800 delta 700 eddy
800 delta 700 fred
800 delta 700 george
800 delta 700 george
700 eddy 700 eddy
700 eddy 700 fred
700 eddy 700 george
700 eddy 700 george
700 fred 700 eddy
700 fred 700 fred
700 fred 700 george
700 fred 700 george
700 george 700 eddy
700 george 700 fred
700 george 700 george
700 george 700 george
700 george 700 eddy
700 george 700 fred
700 george 700 george
700 george 700 george
43 rows selected.
test@ora>
test@ora>This query joins PSAL with itself using a non equi-join. Take each row of PSAL p1 and see how it compares with PSAL p2. You'll see that:
- Row 1 with sal 1000 is >= to all sal values of p2, so it occurs 8 times
- Row 2 with sal 900 is >= to 9 sal values of p2, so it occurs 7 times
- Row 3: 7 times again... and so on.
- So, total no. of rows are: 8 + 7 + 7 + 5 + 4 + 4 + 4 + 4 = 43
test@ora>
test@ora> --
test@ora> -- Query 2 - add the GROUP BY
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT p2.sal AS p2_sal,
12 COUNT(*) as cnt,
13 COUNT(p1.sal) as cnt_p1_sal,
14 COUNT(DISTINCT p1.sal) as cnt_dist_p1_sal,
15 MIN(p1.sal) as min_p1_sal,
16 MAX(p1.sal) as max_p1_sal
17 FROM psal p1, psal p2
18 WHERE p1.sal >= p2.sal
19 GROUP BY p2.sal;
P2_SAL CNT CNT_P1_SAL CNT_DIST_P1_SAL MIN_P1_SAL MAX_P1_SAL
700 32 32 4 700 1000
800 4 4 3 800 1000
900 6 6 2 900 1000
1000 1 1 1 1000 1000
test@ora>
test@ora>Now, if you group by p2.sal in the output of query 1, and check the number of distinct p1.sal, min of p1.sal etc. you see that for p2.sal values - 800, 900 and 1000, there are 3 or less p1.sal values associated.
So, the last 3 rows are the ones you are interested in, essentially. As follows:
test@ora>
test@ora> --
test@ora> -- Query 3 - GROUP BY and HAVING
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT p2.sal AS p2_sal,
12 COUNT(*) as cnt,
13 COUNT(p1.sal) as cnt_p1_sal,
14 COUNT(DISTINCT p1.sal) as cnt_dist_p1_sal,
15 MIN(p1.sal) as min_p1_sal,
16 MAX(p1.sal) as max_p1_sal
17 FROM psal p1, psal p2
18 WHERE p1.sal >= p2.sal
19 GROUP BY p2.sal
20 HAVING COUNT(DISTINCT p1.sal) <= 3;
P2_SAL CNT CNT_P1_SAL CNT_DIST_P1_SAL MIN_P1_SAL MAX_P1_SAL
800 4 4 3 800 1000
900 6 6 2 900 1000
1000 1 1 1 1000 1000
test@ora>
test@ora>
test@ora>That's what you are doing in that query.
The thing is - in order to find out Top-N values, you simply need to scan that one table PSAL. So, joining it to itself is not necessary.
A much simpler query is as follows:
test@ora>
test@ora>
test@ora> --
test@ora> -- Top-3 salaries - distinct or not; using ROWNUM on ORDER BY
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT sal
12 FROM (
13 SELECT sal
14 FROM psal
15 ORDER BY sal DESC
16 )
17 WHERE rownum <= 3;
SAL
1000
900
900
test@ora>
test@ora>
test@ora>And for Top-3 distinct salaries:
test@ora>
test@ora> --
test@ora> -- Top-3 DISTINCT salaries; using ROWNUM on ORDER BY on DISTINCT
test@ora> --
test@ora> with psal as (
2 select 'able' as name, 1000 as sal from dual union all
3 select 'baker', 900 from dual union all
4 select 'charles', 900 from dual union all
5 select 'delta', 800 from dual union all
6 select 'eddy', 700 from dual union all
7 select 'fred', 700 from dual union all
8 select 'george', 700 from dual union all
9 select 'george', 700 from dual)
10 --
11 SELECT sal
12 FROM (
13 SELECT DISTINCT sal
14 FROM psal
15 ORDER BY sal DESC
16 )
17 WHERE rownum <= 3;
SAL
1000
900
800
test@ora>
test@ora>
test@ora>You may also want to check out the RANK and DENSE_RANK analytic functions.
RANK:
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions123.htm#SQLRF00690
DENSE_RANK:
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/functions043.htm#SQLRF00633
HTH
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How this query executing internally
Dear All,
This query picks the nth highest paid employee details, we can acheive this by rank or desnse_rank functions also
But those execution is easily understandable.But Iam not able to understand , how this below correlated subquery executing internally .Please help me on this query
select * from emp a where &n=(select count(distinnct b.sal) from emp b where a.sal<=b.sal)
Thanks in advance>
how this below correlated subquery executing internally .Please help me on this queryPlease check the Explain plan.
Explain plan
set pagesize 25
set linesize 121
EXPLAIN PLAN FOR
< Your Query >;
SELECT * FROM TABLE(dbms_xplan.display);Example :-
SQL> EXPLAIN PLAN FOR select count(1) from dual;
Explained.
SQL> SELECT * FROM TABLE(dbms_xplan.display);
PLAN_TABLE_OUTPUT
Plan hash value: 323232323
| Id | Operation | Name | Rows | Cost (%CPU)| Time |
| 0 | SELECT STATEMENT | | 1 | 2 (0)| 00:00:01 |
| 1 | SORT AGGREGATE | | 1 | | |
| 2 | FAST DUAL | | 1 | 2 (0)| 00:00:01 |
----------------------------------------------------------------- -
Whats wrong with this query.can anyone help me......
select CASE WHEN TO_NUMBER(SUBSTR(TO_CHAR(START_TIME_TIMESTAMP,'DDMMYYYY HH24:MM:SS'),13,2))>0 AND TO_NUMBER(SUBSTR(TO_CHAR(START_TIME_TIMESTAMP,'YYYYMMDD HH24:MM:SS'),13,2)) <14
THEN TO_DATE(CONCAT(SUBSTR(TO_CHAR(START_TIME_TIMESTAMP,'YYYYMMDD HH24:MM:SS'),13,2)||'00',SUBSTR(TO_CHAR(START_TIME_TIMESTAMP,'YYYYMMDD HH24:MI:SS'),16)||'00'),'DD-MM-YYYY HH24:MI:SS') end
from table;
i have written this query.whats wrong with this query..........
the error is "literal does not match format string"
Reegards soumenWhy does your date_format loose, ununify and not fix ?
And what is your exact requirement?
>>
CASE WHEN
TO_NUMBER(SUBSTR(TO_CHAR(START_TIME_TIMESTAMP,'DDMMYYYY HH24:MM:SS'),13,2))>0
AND TO_NUMBER(SUBSTR(TO_CHAR(START_TIME_TIMESTAMP,'YYYYMMDD HH24:MM:SS'),13,2)) <14
<<
This is
CASE WHEN TO_CHAR(START_TIME_TIMESTAMP,'MM') between '01' and '13'
>>
THEN TO_DATE(CONCAT(SUBSTR(TO_CHAR(START_TIME_TIMESTAMP,'YYYYMMDD HH24:MM:SS'),13,2)
||'00',
SUBSTR(TO_CHAR(START_TIME_TIMESTAMP,'YYYYMMDD HH24:MI:SS'),16)||'00'),
'DD-MM-YYYY HH24:MI:SS')
<<
This is
TO_DATE(
TO_CHAR(START_TIME_TIMESTAMP,'MM"00"SS"00"),
'DD-MM-YYYY HH24:MI:SS')
Obviously, format is not matching !
SQL> select to_char(sysdate,'MM"00"SS"00') from dual;
TO_CHAR(
06004900
SQL> select to_date('06004900','DD-MM-YYYY HH24:MI:SS') from dual;
select to_date('06004900','DD-MM-YYYY HH24:MI:SS') from dual
ERROR at line 1:
ORA-01861: literal does not match format string -
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THIS QUERY CAN'T RUN KINDLY HELP (NOT MODIFY IN TABLE)
ALTER TABLE DEP80
MODIFY (JOB_ID NOT NULL VARCHAR2(20));Syntax is wrong.
SQL> create table dep80 (job_id varchar2(20));
Table created.
SQL> alter table dep80 modify (job_id not null varchar2(20));
alter table dep80 modify (job_id not null varchar2(20))
ERROR at line 1:
ORA-00907: missing right parenthesis
SQL> alter table dep80 modify job_id varchar2(20) not null;
Table altered.
SQL> -
I am new to oracle, plz..anybody can explain this query step by step....plz
Select distinct(a.esal) from employee1 a where &N = (select count(distinct(b.esal)) from employee1 b where a.esal<=b.esal);
this is the query to find Nth largest & Nth smallest value from the table employee1....but, i am unable to understand how this query works ....plz..anybody can explain this query step by step with example....plzHi,
Welcome to the forum!
The first step in understanding any code is to format it so you can easily see what is a sub-query, what the major clauses of each sub-query are, and things like that.
For example:
Select distinct (a.esal)
from employee1 a
where &N = ( select count (distinct (b.esal))
from employee1 b
where a.esal <= b.esal
);The only thing I have added to the code you posted was whitespace: newlines, tabs and spaces.
Now it's easy to see that you're doing a query with a scalar sub-query in the WHERE clause.
It usually makes sense to read complicated queries from the inside out, that is, start with the deepest nested sub-query.
In this example, that means:
select count (distinct (b.esal))
from employee1 b
where a.esal <= b.esalWhat does this query do? Unfortunately, it references something (b.esal) from the super-query, so you can't run it by itself, to see what it does. Let's replace that reference with some hard-coded value, just for now, and run it:
select count (distinct (b.esal))
from employee1 b
--where a.esal <= b.esal -- This is the original WHERE clause
where a.esal <= 1000 -- For testing only
;Experiment with this for a while, and compare it to the values in the employee1 table (or a small test table that resembles employee1). Try different numbers in place of 1000.
You'll see that the query is counting how many different salaries are lower than, or equal to, a given salary (1000 in the example above).
When you understand the sub-query, look at the original query again.
It is testing to see if exactly &N different esals are lower than or equal to the esal on each row, and displaying that esal if it is. (&N is a substitution variable. If you haven't already defined a value for it, SQL*Plus will ask you for a value when you run the query.)
In other words, it is finding the N-th lowest value of esal. -
[8i] Query with lots of subqueries: a simpler way to do this query?
Ok, so generally, my problem is that I can't figure out how to write this query without including a bunch of copies of the same subquery (similar to having to join multiple copies of a table). Basically, I have to get information that's in rows in one table into columns in the results of my query. I've created sample tables, with insert statements for sample data, and a trimmed-down version of the query I'm running against those (2) tables. I'll explain what I mean by "trimmed-down" where I provide the SQL for that query.
My restrictions:
1) I'm running in 8i
2) I cannot create any tables in the database (I can only do read-only queries and create views).
Here are my sample tables and sample data:
CREATE TABLE reqs
( req_id NUMBER NOT NULL,
part_no VARCHAR2(5),
req_date DATE,
req_qty NUMBER,
CONSTRAINT reqs_pk PRIMARY KEY (req_id)
INSERT INTO reqs
VALUES (1,'part1',To_Date('01/01/2010','mm/dd/yyyy'),5);
INSERT INTO reqs
VALUES (2,'part2',To_Date('01/10/2010','mm/dd/yyyy'),25);
INSERT INTO reqs
VALUES (3,'part1',To_Date('01/20/2010','mm/dd/yyyy'),3);
INSERT INTO reqs
VALUES (4,'part2',To_Date('02/01/2010','mm/dd/yyyy'),15);
INSERT INTO reqs
VALUES (5,'other',To_Date('02/05/2010','mm/dd/yyyy'),1);
INSERT INTO reqs
VALUES (6,'part1',To_Date('02/07/2010','mm/dd/yyyy'),10);
INSERT INTO reqs
VALUES (7,'part3',To_Date('02/25/2010','mm/dd/yyyy'),22);
INSERT INTO reqs
VALUES (8,'part1',To_Date('03/01/2010','mm/dd/yyyy'),24);
INSERT INTO reqs
VALUES (9,'part3',To_Date('04/01/2010','mm/dd/yyyy'),12);
CREATE TABLE part
( part_no VARCHAR2(5) NOT NULL,
part_desc VARCHAR2(25),
qty_instock NUMBER,
CONSTRAINT part_pk PRIMARY KEY (part_no)
INSERT INTO part
VALUES ('part1','description 1 here',5);
INSERT INTO part
VALUES ('part2','description 2 here',10);
INSERT INTO part
VALUES ('part3','description 3 here',0);Now, here is the query I'm running against the two tables:
SELECT part.part_no
, part.part_desc
, part.qty_instock
, pd.tot_req_qty AS qty_past_due
, m1.tot_req_qty AS qty_this_month
, m2.tot_req_qty AS qty_next_month
, m3.tot_req_qty AS qty_month_3
FROM part
SELECT reqs.part_no
, SUM(reqs.req_qty) AS tot_req_qty
, CASE
WHEN reqs.req_date < sysdate
THEN 'Past Due'
ELSE To_Char(reqs.req_date,'MON-yyyy')
END AS month_reqd
FROM reqs
GROUP BY reqs.part_no
, CASE
WHEN reqs.req_date < sysdate
THEN 'Past Due'
ELSE To_Char(reqs.req_date,'MON-yyyy')
END
) pd --for past due
SELECT reqs.part_no
, SUM(reqs.req_qty) AS tot_req_qty
, CASE
WHEN reqs.req_date < sysdate
THEN 'Past Due'
ELSE To_Char(reqs.req_date,'MON-yyyy')
END AS month_reqd
FROM reqs
GROUP BY reqs.part_no
, CASE
WHEN reqs.req_date < sysdate
THEN 'Past Due'
ELSE To_Char(reqs.req_date,'MON-yyyy')
END
) m1 --for month 1
SELECT reqs.part_no
, SUM(reqs.req_qty) AS tot_req_qty
, CASE
WHEN reqs.req_date < sysdate
THEN 'Past Due'
ELSE To_Char(reqs.req_date,'MON-yyyy')
END AS month_reqd
FROM reqs
GROUP BY reqs.part_no
, CASE
WHEN reqs.req_date < sysdate
THEN 'Past Due'
ELSE To_Char(reqs.req_date,'MON-yyyy')
END
) m2 --for month 2
SELECT reqs.part_no
, SUM(reqs.req_qty) AS tot_req_qty
, CASE
WHEN reqs.req_date < sysdate
THEN 'Past Due'
ELSE To_Char(reqs.req_date,'MON-yyyy')
END AS month_reqd
FROM reqs
GROUP BY reqs.part_no
, CASE
WHEN reqs.req_date < sysdate
THEN 'Past Due'
ELSE To_Char(reqs.req_date,'MON-yyyy')
END
) m3 --for month 3
WHERE part.part_no = pd.part_no
AND pd.part_no = m1.part_no
AND m1.part_no = m2.part_no
AND m2.part_no = m3.part_no
AND pd.month_reqd = 'Past Due'
AND m1.month_reqd = To_Char(Add_Months(sysdate,1),'MON-yyyy')
AND m2.month_reqd = To_Char(Add_Months(sysdate,2),'MON-yyyy')
AND m3.month_reqd = To_Char(Add_Months(sysdate,3),'MON-yyyy')
ORDER BY part.part_noThe sample query above only gets 3 months worth of my tot_req_qty for each part number, which equals 3 (+1 for past due) copies of the subquery. This is how this query is "trimmed down" from my actual query; in my real query, I need to include at least 6 months (up to 12 months) of my tot_req_qty for each part number--which means 6-12 (+1) copies of the subquery...ick. I just can't imagine that being an efficient way to get this done.
Here's a table of the results I expect to get from my sample query:
PART_NO PART_DESC QTY_INSTOCK QTY_PAST_DUE QTY_THIS_MONTH QTY_NEXT_MONTH QTY_MONTH_3
part1 description 1 here 5 8 10 24 0
part2 description 2 here 10 40 0 0 0
part3 description 3 here 0 0 22 0 12Is there anything I can do differently here?
Thanks!!
Edited by: user11033437 on Feb 4, 2010 11:53 AM Fixed a typo
Edited by: user11033437 on Feb 4, 2010 12:08 PM Fixed another typoHi,
Instead of doing self-joins, you can pivot one result set.
Since it's just one result set, you can use an in-line view for it:
SELECT part.part_no
, part.part_desc
, part.qty_instock
, SUM ( CASE WHEN m.month_reqd = 'Past Due'
THEN m.tot_req_qty
ELSE 0
END
) AS qty_past_due
, SUM ( CASE WHEN m.month_reqd = To_Char(sysdate,'MON-yyyy')
THEN m.tot_req_qty
ELSE 0
END
) AS qty_this_month
, SUM ( CASE WHEN m.month_reqd = To_Char(Add_Months(sysdate, 1),'MON-yyyy')
THEN m.tot_req_qty
ELSE 0
END
) AS qty_next_month
, SUM ( CASE WHEN m.month_reqd = To_Char(Add_Months(sysdate, 2),'MON-yyyy')
THEN m.tot_req_qty
ELSE 0
END
) AS qty_month_3
FROM part
, ( -- Begin in-line view m
SELECT part_no
, SUM (req_qty) AS tot_req_qty
, month_reqd
FROM ( -- Begin in-line view rd
SELECT part_no
, req_qty
, CASE
WHEN req_date < sysdate
THEN 'Past Due'
ELSE To_Char(req_date,'MON-yyyy')
END AS month_reqd
FROM reqs
WHERE req_date < TRUNC ( ADD_MONTHS (SYSDATE, 3)
, 'MONTH'
) rd -- End in-line view rd
GROUP BY part_no
, month_reqd
) m -- End in-line view m
WHERE part.part_no = m.part_no
GROUP BY part.part_no
, part.part_desc
, part.qty_instock
ORDER BY part.part_no
;Notice I used a nested in-line view to compute month_reqd, rather than repeat the CASE expression. That's independent of the pivot: you can do either one with or without the other.
Thanks for posting the CREATE TABLE and INSERT statements! -
Need information on this Query
Hi guys,
can someone explain how this query works indetail.
SELECT DISTINCT (a.sal) FROM EMP A WHERE &N = (SELECT COUNT (DISTINCT (b.sal)) FROM EMP B WHERE a.sal<=b.sal);
Advance thanks for your help.
Kadiyala
Edited by: user10223931 on Mar 4, 2009 8:17 PMHi,
SELECT DISTINCT (a.sal),(SELECT COUNT (DISTINCT (b.sal)) FROM EMP B WHERE a.sal<=b.sal) FROM EMP A order by 2 descI hope this will help you.
The query will rank the records as per salary amount. and you will get the salary amount of the specified rank. -
Help with re-writing this query
Dear experts;
create table t2
ID varchar2(1000),
name varchar2(1000),
place varchar2(1000)
create table mappingt2
grades varchar2(1000)
individual varchar2(1000)
insert into t2 values ('James', 'John', 'newyork');
insert into t2 values ('Linda', 'James', 'London');
insert into t2 values ('Alex', 'kim', 'Mexico');
insert into t2 values ('karen', 'Jack', 'Tunis');
insert into t2 values ('CC', 'Jack', 'Peru');
insert into t2 values ('Linda', 'James', 'Germany');
insert into mappingt2 values ('A', 'James');
insert into mappingt2 values ('C', 'Kim');
insert into mappingt2 values ('C', 'Linda');
insert into mappingt2 values ('B', 'CC');I have the following query below
SELECT (select grades from mappingt2 t
where t.individual = pt.ID) as current_grade
,(select grades from mappingt2 ty
where ty.individual = pt.name) alt_grade
,pt.place
FROM t2 ptI was just wondering whether this query can be better written. All help is appreciated. Thank youuser13328581 wrote:
Hi Frank, Tom Kyte claims sub scalar queries is usually betterHe didn't say usually he said if you want the first row faster
>
if your goal is to optimize your query for initial response time, you may want to use the former query, with the scalar subquery, because Oracle Database would have to get just the first row from DEPT, run the scalar subquery (select count...) against EMP to get the count, and then return it. The process for returning that first row would be very fast.
>
The corollary to this that was not explicitly mentioned in the article that I can see is that this probably comes at the expense of the time taken to return all the rows which can then take longer.
Maybe you are looking for
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