How to convert Xml Document into orcale tempary table

Question

i am creating xml document into java and passing this xml into oracle database and i need to fetch this xml into result set | rowset.
Xml Structure
<Department deptno="100">
<DeptName>Sports</DeptName>
<EmployeeList>
<Employee empno="200"><Ename>John</Ename><Salary>33333</Salary>
</Employee>
<Employee empno="300"><Ename>Jack</Ename><Salary>333444</Salary>
</Employee>
</EmployeeList>
</Department>
i need like this format
Deptno DeptName empno Ename Salary
100 Sports 200 Jhon 2500
100 Sports 300 Jack 3000

Answer 1

It does depend on your version as odie suggests.
Here's a way that will work in 10g...
SQL> ed
Wrote file afiedt.buf
  1  with t as (select xmltype('<Department deptno="100">
  2  <DeptName>Sports</DeptName>
  3  <EmployeeList>
  4  <Employee empno="200"><Ename>John</Ename><Salary>33333</Salary>
  5  </Employee>
  6  <Employee empno="300"><Ename>Jack</Ename><Salary>333444</Salary>
  7  </Employee>
  8  </EmployeeList>
  9  </Department>
10  ') as xml from dual)
11  --
12  -- End of test data, Use query below
13  --
14  select x.deptno, x.deptname
15        ,y.empno, y.ename, y.salary
16  from t
17      ,xmltable('/'
18                passing t.xml
19                columns deptno   number       path '/Department/@deptno'
20                       ,deptname varchar2(10) path '/Department/DeptName'
21                       ,emps     xmltype      path '/Department/EmployeeList'
22               ) x
23      ,xmltable('/EmployeeList/Employee'
24                passing x.emps
25                columns empno    number       path '/Employee/@empno'
26                       ,ename    varchar2(10) path '/Employee/Ename'
27                       ,salary   number       path '/Employee/Salary'
28*              ) y
SQL> /
    DEPTNO DEPTNAME        EMPNO ENAME          SALARY
       100 Sports            200 John            33333
       100 Sports            300 Jack           333444
SQL>If the XML is a string e.g. a CLOB then it can easily be converted to XMLTYPE using the XMLTYPE function.