How to define a second view-handler (decorator)

Hello,
I'd like to implement the ViewHandler decorator proposed by Adam Winder to accomplish authorization.
http://forum.java.sun.com/thread.jspa?threadID=502322
Besides, I use myfaces and Tiles, thus already having a Viewhandler defined
How do I decorate the Tiles View-Handler?
I don't know if this would be correct...
<application>
<view-handler>org.apache.myfaces.tomahawk.application.jsp.JspTilesViewHandlerImpl</view-handler>
<view-handler>my.package.myViewHandler</view-handler>
Regards,
Jan

Hi Surya,
As a starting point you should review the SAP Help on the subject, this will explain the steps required to get a catalog up and running.
http://help.sap.com/saphelp_ccm20/helpdata/en/index.htm
Regards,
Jason

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    ## Detail 0 ##
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    1) create yet another UIContainer for this view in main window and embed view to this container. It was be done for create separate iView for form.
    2) in the portal I create iView for this form but don't embedd in any page.
    When I try to call my form from list data (that is one iView from another) I get exception:
    <b>com.sap.tc.webdynpro.services.exceptions.WDRuntimeException: duplicate usage of view .MyCarRentalAddCity</b>
    Is there a way to get needed functional?
    Thanks,
    Lev

    Hi,
    do you need to remove the IView from the portal menu or do you just want to make a View container in your WD application invisible if the user doesn't have the rights to see it.
    If so, you could create your own roles on the app server:
    You need to create a new class that extends NamePermission like:
    import com.sap.security.api.permissions.NamePermission;
    public class ApplicationAccessPermission extends NamePermission {
               * @param name
              public ApplicationAccessPermission(String name) {
                   super(name);
               * @param name
               * @param action
              public ApplicationAccessPermission(String name, String action) {
                   super(name, action);
    Also, you have to create an Action.XML file that looks like this:
    <BUSINESSSERVICE
         NAME="com.vendor.administration">
         <DESCRIPTION
              LOCALE="en"
              VALUE="actions view usage"/>
         <ACTION
              NAME="View Permission">
              <DESCRIPTION
                   LOCALE="en"
                   VALUE="Show view"
                   />
              <PERMISSION
                   CLASS="com.vendor.utilities.ApplicationAccessPermission"
                   NAME="ShowView"
                   />
         </ACTION>
    </BUSINESSSERVICE>
    If you have created these to files in your packages, you can access this function like:
    IUser user ;
    try {
              user = WDClientUser.getCurrentUser().getSAPUser();
              if(user.hasPermission(new ApplicationAccessPermission("Show view"))){
                   wdContext.currentV_UIElement().setViewVisibility(WDVisibility.VISIBLE);
              }else{
                   wdContext.currentV_UIElement().setViewVisibility(WDVisibility.NONE);
         }catch (WDUMException e1) {
              wdContext.currentV_UIElement().setViewVisibility(WDVisibility.NONE);
                    e1.printStacktrace();
    You have to bind the ViewVisibility attribute of the context to the View Container you want to hide.
    The applicationAccessPermission you defined in the XML File will be visible in the UME Manager of you J2EE engine. With this action you can create a new role and group that you can map to the users that should see you view.
    But, the exception you get is because you have embedded one view twice, which is not possible.
    Hope this helps.
    Regards,
    Dennis

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