How to delete duplicate row in certain case

Hi all,
I need you help to delete my duplicate row.
Sample Data in table (table1)
 
Timein
DateIn
locationin useridin
status
08:20:00 01/09/2007
0001
U01
1
08:10:30 01/09/2007
0004
U01
1
07:20:00 01/09/2007
0006
U01
1
08:14:00 01/09/2007
0001
U02
1
06:10:30 01/09/2007
0004
U02
1
08:10:10 01/09/2007
0006
U02
1
 
I need to delete the row in table1 and leave the minimum timein in
that table by useridin.
The last output in table1 is like below.
Timein
DateIn
locationin useridin
status
07:20:00 01/09/2007
0006
U01
1
06:10:30 01/09/2007
0004
U02
1
Can i used below sql to output the result;


delete
from
table1 t1 
where
t1.rowid
>


(
select
min(t2.rowID)
from
table1 t2

where
t1.Datein
= t2.Datein


and
t1.Status
=
t2.Status

and
t1.UserIdin
=
t2.UserIdin
order by t2.timein);
 
Thanks
in advanced

Hi Rob,
Just trying to chip in little bit!
Created Table As follows same as you, only two rows with duplicatem user, datein, and timein:
create table table1
as
select '08:20:00' timein, date '2007-09-01' datein, '0001' locationin, 'U01' useridin, 1 status from dual union all
select '08:10:30', date '2007-09-01', '0004', 'U01', 1 from dual union all
select '07:20:00', date '2007-09-01', '0006', 'U01', 1 from dual union all
select '08:14:00', date '2007-09-01', '0001', 'U02', 1 from dual union all
select '06:10:30', date '2007-09-01', '0004', 'U02', 1 from dual union all
select '06:10:30', date '2007-09-01', '0001', 'U02', 1 from dual
If I run your delete statement result row will be as follows:
SQL> select * from table1;
TIMEIN DATEIN LOCA USE STATUS
07:20:00 01-SEP-07 0006 U01 1
06:10:30 01-SEP-07 0004 U02 1
06:10:30 01-SEP-07 0001 U02 1
Here problem is that its not able to delete duplicate rows having same timein and timeout.
So I changed you query as follows:
DELETE FROM tab1
WHERE rowid NOT IN (
     SELECT     MIN(rowid)
     FROM     tab1
     WHERE     (UseridIn, TO_DATE(TO_CHAR(DateIn,'YYYYMMDD') || TimeIn,'YYYYMMDDHH24:MI:SS')) IN
          (     SELECT     UseridIn, MIN(TO_DATE(TO_CHAR(DateIn,'YYYYMMDD') || timein,'YYYYMMDDHH24:MI:SS'))
               FROM     tab1
               GROUP BY UseridIn)
     GROUP BY UseridIn
If I run your delete statement with little bit of changes, the result row was as follows:
SQL> select * from table1;
TIMEIN DATEIN LOCA USE STATUS
07:20:00 01-SEP-07 0006 U01 1
06:10:30 01-SEP-07 0004 U02 1
Regards,
Raj

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