How to do outer join in data model view?

Hi,
I have 2 queries are needed to be joined in Oracle Report 6i Data Model View. What I want to do is below:
where table1.receipt_no(+)=table2.receipt_no
How do I use the 'Data Link' to do this in Data Model view?
Thanks.
Jun

Hi
You need to use data links. Refer data link section in BUilding Reports manual at http://otn.oracle.com/products/reports/htdocs/getstart/docs/B10310_01/orbr_concepts1.htm#1013156.
Thanks
Rohit

Similar Messages

  • Issues with using Outer join in Data Template

    Hi all,
    this is my data in two tables .
    Table Ronny1
    colA colB
    1 u
    2 v
    3 x
    Table Ronny2
    colC colD
    1 q
    2 r
    This is my data template
    <dataTemplate name="MGF" dataSourceRef="Source1">
         <dataQuery>
              <sqlStatement name="Q1" dataSourceRef="Source1">
                   <![CDATA[select C, D  from Ronny2]]>
              </sqlStatement>
              <sqlStatement name="Q2" dataSourceRef="Source2">
                   <![CDATA[select A , B from lokesh1 where A = :C]]>
              </sqlStatement>
         </dataQuery>
         <dataStructure>
              <group name="G1" source="Q1">
                   <group name="G2" source="Q2">
                        <element name="A" value="A"/>
                        <element name="B" value="B"/>
                   </group>
              </group>
         </dataStructure>
    </dataTemplate>
    Now this would give me result as
    A B
    1 u
    2 v
    however my requirement is this
    A B
    1 u
    2 v
    3 x
    that is, i want to display all the rows of table Ronny1 and matching rows from table Ronny2. I tried modifiying my second sql as
    <![CDATA[select A , B from lokesh1 where A = :C (+)]]> ( using a outer join)
    but this does give me correct data and comes back with the cartesion product.
    Can anyone please answer this for me that how can we use the outer join in data templaes.
    Thanks
    Ronny

    hey vetsrini,
    sorry for the confusion here,
    actually i want to display all the rows from table Ronny1 and i am also pulling in the matching rows from table Ronny2 and my data structure looks as ( pulling in column D from table Ronny2)
    <dataStructure>
    <group name="G1" source="Q1">
    <group name="G2" source="Q2">
    <element name="A" value="A"/>
    <element name="B" value="B"/>
    <element name="D" value="D"/>
    </group>
    </group>
    </dataStructure>
    and this is what i want the output to be
    A B D
    1 u q
    2 v r
    3 x
    Hence the row where A <> C the data in the D column will be null, same as in the case of outer join.
    any suggestions
    Thx
    Ronny

  • How to find out the Hire date of an employee?

    Hi All
    What is effective date, Latest start date and other date fields which are are used when we create a new employee?
    What is the difference between hire date and joining date?
    How to find out the Hire date and joining date of an employee?
    Regards
    Rahman

    The effective dates are related to date tracking. The effective start date shows when this version of the record became effective.
    The Hire Date, or Latest Satrt Date shows the date on which the employee was last hired. If he was hired before from 01/01/01 to 31/12/01, then left but was hired again from 01/01/07, the Latest Hired Date would be 01/01/07 and the First Hired Date would be 01/01/01.
    When using Oracle HR, datetracking allows you to either correct data (because it was wrong or incomplete), or update it (because a time effective change took place e.g. got married).
    The[b] effective dates show when a record was updated. So, if an update was made on 07/02/07, and the update datetrack option was used, the current record would have its effective end date set to 06/02/07 (the day before the update) and a new version would be created with the updates and an effective start date of 07/02/07.
    Hope this helps.

  • How to use outer join condition in my below query.

    Hi All,
    How to use outer join condition in my below query.
    In the table  APPS_JP.GEDIS_OFFER_HEADER goh I have more records
    in the table APPS_JP.GEDIS_ORDER_BUILDS gob I have less number of records.
    I want all the records from APPS_JP.GEDIS_OFFER_HEADER goh
    including other conditions.
    I have tried goh.OFFER_NO=gob.OFFER_NO(+) but same result.
    [code]SELECT   GOH.ORIG_SYSTEM,
               gsp.USER_NAME,
               goh.ORDER_NO,
               goh.OMEGA_ORDER_NUMBER,
               goh.ORDER_TYPE,
               gc.CUSTOMER_ID,
               gc.OMEGA_CUSTOMER_NUMBER,
               CASE WHEN gc.PRIVATE = 'N' THEN gc.CUSTOMER_NAME ELSE '' END
                  AS COMPANY_NAME,
               goh.ORDER_STATUS,
               goh.TOTAL_SELLING_PRICE,
               goh.TOTAL_MARGIN,
                  ga1.ADDRESS1
               || ','
               || ga1.ADDRESS2
               || ','
               || ga1.ADDRESS3
               || ','
               || ga1.POSTAL_CODE
               || ','
               || ga1.CITY
                  AS SHIPPING_ADDRESS,
                  ga2.ADDRESS1
               || ','
               || ga2.ADDRESS2
               || ','
               || ga2.ADDRESS3
               || ','
               || ga2.POSTAL_CODE
               || ','
               || ga2.CITY
                  AS BILLING_ADDRESS,
               ga.ADDRESS_ID,
               gol.DESCRIPTION,
               APPS_JP.TZ.to_local_date (goh.OFFER_DATE, goh.OFFER_DATE_UTC)
                  AS OFFER_DATE,
               gc.LEVEL_8,
               goh.NO_OF_BUILDS,
               gob.SFDC_ID,
               goh.PURCHASE_ORDER_NO AS PO,
               gc1.CUSTOMER_NAME AS END_USAGE,
               gol.LOB,
               goh.TOTAL_MARGIN_PCT,
               goh.TOTAL_DISCOUNT,
               goh.TOTAL_DISCOUNT_PCT
        FROM   APPS_JP.GEDIS_OFFER_HEADER goh,
               APPS_JP.GEDIS_ORDER_BUILDS gob,
               APPS_JP.GEDIS_ORDER_LINES gol,
               APPS_JP.GEDIS_OFFER_RELATED_CUSTOMER gorc,
               APPS_JP.GEDIS_OFFER_RELATED_CUSTOMER ship,
               APPS_JP.GEDIS_OFFER_RELATED_CUSTOMER bill,
               APPS_JP.GEDIS_CUSTOMER gc,
               APPS_JP.GEDIS_CUSTOMER gc1,
               APPS_JP.GEDIS_CONTACT gct,
               APPS_JP.GEDIS_ADDRESS ga,
               APPS_JP.GEDIS_ADDRESS_NORM ga1,
               APPS_JP.GEDIS_ADDRESS_NORM ga2,
               (SELECT   DISTINCT SALESPERSON_ID, USER_NAME
                  FROM   APPS_JP.GEDIS_SALESPERSON
                 WHERE   SALESPERSON_ID IN
                               (SELECT   TO_NUMBER (COLUMN_VALUE) AS SALESPERSON_ID
                                  FROM   TABLE (APPS_GLOBAL.SplitString ('337309'))))
               gsp
       WHERE       goh.ORDER_NO <> 0
               AND goh.OFFER_NO <> 0
               AND goh.OFFER_NO=gol.OFFER_NO
               AND gol.BUILD_NO = 1
               AND gol.LINE_NO = 1
               AND goh.OFFER_NO=gob.OFFER_NO
               AND gob.BUILD_NO = 1
               AND goh.OFFER_NO = gorc.OFFER_NO
               AND gct.CONTACT_ID = gorc.CONTACT_ID
               AND ga.CUSTOMER_ID = gc.CUSTOMER_ID
               AND ga.PRIMARY = 'Y'
               AND goh.LEAD_SALESPERSON=gsp.SALESPERSON_ID
               AND goh.OFFER_NO = ship.OFFER_NO
               AND ship.RELATION_TYPE = 'SHIP'
               AND ga1.ADDRESS_ID = ship.ADDRESS_ID
               AND ga1.CUSTOMER_ID = gc1.CUSTOMER_ID
               AND goh.OFFER_NO = bill.OFFER_NO
               AND bill.RELATION_TYPE = 'BILL'
               AND ga2.ADDRESS_ID = bill.ADDRESS_ID
               AND goh.OFFER_DATE BETWEEN APPS_JP.TZ.LOCAL_TO_DB_DATE (
                                             SYSDATE - 30
                                      AND  APPS_JP.TZ.LOCAL_TO_DB_DATE (SYSDATE)
               AND gorc.RELATION_TYPE = 'BASE'
               AND gorc.CUSTOMER_ID = gc.CUSTOMER_ID
               AND goh.SALES_CHANNEL = gc.SALES_CHANNEL
               AND gc.SALES_CHANNEL = 'SMB'
               AND goh.LEAD_SALESPERSON IN (goh.CREATED_BY, goh.LEAD_SALESPERSON)
    ORDER BY   goh.OFFER_NO;[/code]
    Please help me how to use this outer join condition.
    Thanks in advance.

    Hi,
    If you want all the rows from goh, then you don't want any conditions like  goh.OFFER_NO <> 0.
    Make all the joins to goh outer joins, and make all conditions that apply to any tables joined to goh (or to tables joined to them) part of the join condition, like this:
    FROM             APPS_JP.GEDIS_OFFER_HEADER     goh
    LEFT OUTER JOIN  APPS_JP.GEDIS_ORDER_BUILDS     gob  ON   gob.OFFER_NO = goh.OFFER_NO
                                                         AND  gob.BUILD_NO = 1
    LEFT OUTER JOIN  APPS_JP.GEDIS_ORDER_LINES      gol  ON   gol.OFFER_NO = goh.OFFER_NO
                                                         AND  gol.BUILD_NO = 1
                                                         AND  gol.LINE_NO  = 1
    LEFT OUTER JOIN  APPS_JP.GEDIS_OFFER_RELATED_CUSTOMER
                                                    gorc ...
    I hope this answers your question.
    If not, post a little sample data (CREATE TABLE and INSERT statements, relevant columns only) for all the tables involved, and the results you want from that data.
    Simplify the problem as much as possible.  For example, do you really need all those tables to show what the problem is?  Of course, you need them in tyour real query, but if you understand a solution that only involves 4 or 5 tables, you'll know how to apply it to any number of tables.
    Explain, using specific examples, how you get those results from that data.Always say what version of Oracle you're using (e.g. 11.2.0.2.0).
    See the forum FAQ https://forums.oracle.com/message/9362002#9362002

  • How to find out the "manufacture date"?

    Hello!
    Can you tell me how to find out the manufacture date of my Satellite A110-334 with the serial "SY6224123K"?
    I need this information for my insurance!
    I found only this link for HDD`s: http://www.storage.toshiba.eu/index_manual.php?pid=220&sid=536&la=en
    But there is no "S" on the first digit!??
    So it is maybe "Y6" which can be November 2006! Is this right?
    Thank you!
    ===========
    This is the information on the link above:
    How to encode a Toshiba Hard Disk Drive Serial Number?
    The Toshiba serial number (S/N) includes details of the date of manufacture. The first digit of the serial number indicates the Month of manufacture and the 2nd digit indicates the Year.
    Example:
    M Y x x x x x x x
    M = Month
    Y = Year
    The month digit goes from 1, for January, through to 9, for September, and then X, Y and Z, for October, November and December.
    Examples:
    2 8 1 7 0 0 0 1 A
    2 = February
    8 = 1998
    3 0 5 4 4 3 0 6 T
    3 = March
    0 = 2000
    X 9 D 7 8 3 3 1 T
    X = October
    9 = 1999
    The remaining digits contain information about factory and production line, and some digits are reserved for a continuously running serial number.

    Hello
    Try with http://gedb.toshiba.com/
    Let me know if you find info you need.

  • How to find out the last date & time on which a program has been run

    Hi Experts,
    Can anybody tell how to find out the last date on which a purticular program has been run.
    Valuable answers will be rewarded.
    Thanks & Regards,
    Satish.

    Hi!
    Try STAD transaction. Unfortunately it contains a huge amount of data, so it is available only for a few days backwards... Maybe some weeks, but you can't make yearly reports from its data... So it's not useful to see, which program is in use or not...
    I planned once to download it weekly, but it was not so important...
    Regards
    Tamá

  • How to make linkage query In Data Model for search

    I want to make an linkage query as a condition for my  report in BI Publisher. how to make the linkage in Date Model ?

    This is the forum for SQL Developer, not for general SQL or PL/SQL questions.
    Please repost this in the SQL and PL/SQL forum.

  • How to use outer join on 3 tables

    how to use outer join on 3 tables
    say tables are mkpf,lips and vbrp
    mkpf-xblnr = lips-vbeln
    lips-vbeln  = vbrp-vgbel

    refer following querry
        select a~bukrs
               a~anln1
               a~ord42
               a~ord43
               b~afabe
               b~ndabj
               b~kaafa
               b~aafag
               c~kostl
               d~afasl
               d~ndjar
               d~ndper
        into corresponding fields of table gt_master
        from ( ( anla as a inner join anlc as b
        on abukrs = bbukrs
        and aanln1 = banln1
        and aanln2 = banln2 )
        inner join anlz as c
        on  abukrs = cbukrs
        and aanln1 = canln1
        and aanln2 = canln2 )
        inner join anlb as d
        on  abukrs = dbukrs
        and aanln1 = danln1
        and aanln2 = danln2
        where a~bukrs in s_comp.

  • How to make outer join in Sub Query?

    Hi!
    I'm facing one problem. Can anyone tell me - how to make outer join in sub query?
    I'm pasting one sample code -
    select e.empno, e.ename,e.job,e.sal,d.deptno,d.dname
    from d_emp e, d_dept d
    where e.deptno(+) = (
                          case
                            when d_dept.deptno = 10
                              then
                                  select deptno
                                  from d_dept
                                  where dname = 'SALES'
                          else
                            d_dept.deptno
                          end
    SQL>
    ERROR at line 15:
    ORA-01799: a column may not be outer-joined to a subqueryHow to resolve this issue?
    Regards.

    And any luck with this?
    SQL> with emp as
      2  (select 100 empno, 'Abcd' ename, 1000 sal, 10 deptno from dual
      3  union all
      4  select 101 empno, 'RRR' ename, 2000 sal, 20 deptno from dual
      5  union all
      6  select 102 empno, 'KKK' ename, 3000 sal, 30 deptno from dual
      7  union all
      8  select 103 empno, 'PPP' ename, 4000 sal, 10 deptno from dual
      9  )
    10  ,dept as
    11  (select 10 deptno, 'FINANCE' dname from dual
    12  union all
    13  select 20 deptno, 'SALES' dname from dual
    14  union all
    15  select 30 deptno, 'IT' dname from dual
    16  union all
    17  select 40 deptno, 'HR' dname from dual
    18  )
    19  select e.empno, e.ename, e.sal, d.deptno, d.dname
    20  from emp e,
    21       (select decode(a.deptno, 10, b.deptno, a.deptno) deptno, decode(a.deptno, 10, b.dname, a.dname) dname
    22      from dept a, (select deptno, dname
    23                    from dept
    24                      where dname = 'SALES'
    25                     ) b
    26       ) d
    27  where e.deptno(+) = d.deptno
    28  /
         EMPNO ENAM        SAL     DEPTNO DNAME
           101 RRR        2000         20 SALES
           101 RRR        2000         20 SALES
           102 KKK        3000         30 IT
                                       40 HR
    SQL> Cheers
    Sarma.

  • How  to maintain version in ERwin Data Modeler

    Hi all
    Please tell me
    how to maintain version in ERwin Data Modeler
    regards

    In SharePoint, navigate to the form library, and then click Library Tools > Library > Settings > Library Settings.
    On the Form Library Settings page under General Settings, click
    Versioning settings.
    On the Versioning Settings page under the Document Version History section, select either the
    Create major versions option or the Create major and minor (draft) versions option, and click
    OK.
    http://www.bizsupportonline.net/blog/2012/10/version-control-infopath-forms-templates-sharepoint-libraries/
     Or
    plan this wsp nfoPath_VersionHistory.wsp
    http://infopathversioning.codeplex.com/

  • How to find out last update date for business partner's marketing attribute

    How to find out last update date for business partner's marketing attribute??
    Im freshie for SAP Application and im assigned to find out last update date for marketing attribute changed
    which table is involved??
    Yours kindness will be appreciated
    thanks

    You can take a look at table AUSP as well as CRMD_AUSP_HIST.
    The "changed by" and "changed at" are logged on attribute level, not on attribute value level. When you change one specific value, the system does a "re-insert" of all existing values of this attribute.
    Take a look at the SAP notes 938426 and 966670  these may assit you in resolving the issue.
    Regards,
    William Laverde

  • SQL Developer Data Modeler Viewer - domain datatypes

    I'm using the SQL Developer Data Modeler Viewer (that comes free with SQL Developer) to view a model that was created in Oracle SQL Developer Data Modeler (the chargeable product). The colums have all been defined using domain datatypes. I have an XML file defining the domains but I cannot see where in the viewer you can import a domian file into or where in the model's directory structure the file can be placed to be read by the viewer. Without this the columns are all showing as datatype 'Unknown'.
    Any help much appreciated, thanks.

    two set of domains can be maintained in Data Modeler:
    - per installation - they are in file defaultdomains.xml in "datamodeler\domains" directory
    - per design - they are in "domains" directory under your design directory -
    "Per installation" domains are used in your case - "per design" domains are "attached" to design - when you send the design to someone else, they are in design structure.
    Your solution - to get defaultdomains.xml file from installation where design is created and to put it in your "datamodeler\domains" directory.
    Philip

  • 30EZ2 - Strange message from Data Modeler Viewer.

    I am getting a strange message from Data Modeler Viewer when I try to shutdown SQLDeveloper.
    I have not used data model viewer, but on shutting down sqldevloper I get
    Oracle SQL Developer Data Modeler Viewer is waiting for tasks that should finish, such as writing files.

    As reported in 30EA2: Data Modeler Viewer annoyance when exiting
    The team has yet to respond.
    Regards,
    K.

  • 30EA2: Data Modeler Viewer annoyance when exiting

    Hi,
    Almost always when exiting sqldev, I'm prompted with a dialog stating the 'Data Modeler Viewer is waiting for tasks that should finish, such as writing files', being able to Wait or Exit now. In the Log, I get an entry 'Delete Design: "Untitled_1"'.
    Please make sure to clean up correctly before prompting such a dialog.
    Thanks,
    K.

    Hi,
    I can confirm this is happening on me too.
    I am confused, since I didn't invoke Data Modeler Viewer, yet the prompt appears just before prompting to Save the modified Worksheet.
    This probably a minor bug, but hopefully to be addressed, since it is quite confusing.
    Regards,
    Buntoro

  • Left outer join using date range returns too many rows

    I am trying to pull data for a website.
    Names table:
    company_name varchar2(30)
    julian_day varchar2(3)
    logins number(3)
    login_errors number(3)
    Given a julian date range (e.g. 250-252), I am displaying the information from the Names table.
    The problem is that I also need to display changes (increases/decreases) in the data. I do that by coloring the text based on a 10% increase/decrease. Data for the 3 days 250-252 would be compared to data for the previous 3 days 247-249.
    Not all companies will report data on all days, so some gaps in the data may exist. Therefore, I cannot do just a simple join.
    I am trying to write a query that will give me this information if the user chooses days 250-252.
    Company_name
    sum(logins) for days 250-252
    sum(login_errors) for days 250-252
    sum(logins) for days 247-249
    sum(login_errors) for days 247-249
    The query I'm using is:
    select cur.company_name, sum(cur.logins),
    sum(cur.login_errors), sum(old.logins), sum(old.login_errors)
    FROM names cur LEFT OUTER JOIN names old
    ON cur.company_name = old.company_name
    WHERE cur.adate>='250' and cur.adate<='252'
    and old.adate>='247' and old.adate<='249'
    GROUP by cur.company_name
    Given this data:
    Company_name adate logins login_errors
    ABC 247 10 10
    ABC 248 20 20
    ABC 249 30 30
    ABC 250 15 15
    ABC 251 25 25
    ABC 252 35 35
    My problem is that it returns:
    adate cur.logins cur.login_err old.logins old.login_err
    250 15 15 60 60
    251 25 25 60 60
    252 35 35 60 60
    How can I get it to only give me the one "old" day's data? I went with the LEFT OUTER JOIN because it's possible that there is no data for an "old" day.
    Thanks in advance.....

    Your problem stems from the join itself, and would be the same even without the OUTER JOIN. With your data, there are 3 records in cur and 3 records in old. The join matches each record in cur to each record in old resulting in 9 records in total. Without the SUM, this is clear:
    SQL> SELECT cur.company_name, cur.logins, cur.login_errors,
      2         old.logins, old.login_errors, cur.adate cad, old.adate oad
      3  FROM names cur LEFT OUTER JOIN names old
      4                 ON cur.company_name = old.company_name
      5  WHERE cur.adate>=250 and cur.adate<=252 and
      6        old.adate>=247 and old.adate<=249;
    COMPANY_NA     LOGINS LOGIN_ERRORS     LOGINS LOGIN_ERRORS        CAD        OAD
    ABC                35           35         10           10        252        247
    ABC                25           25         10           10        251        247
    ABC                15           15         10           10        250        247
    ABC                35           35         20           20        252        248
    ABC                25           25         20           20        251        248
    ABC                15           15         20           20        250        248
    ABC                35           35         30           30        252        249
    ABC                25           25         30           30        251        249
    ABC                15           15         30           30        250        249
    9 rows selected.You can do this with only one reference to the table.
    SELECT company_name,
           SUM(CASE WHEN adate BETWEEN 250 and 252 THEN logins ELSE 0 END) curlog,
           SUM(CASE WHEN adate BETWEEN 250 and 252 THEN login_errors ELSE 0 END) curerr,
           SUM(CASE WHEN adate BETWEEN 247 and 249 THEN logins ELSE 0 END) oldlog,
           SUM(CASE WHEN adate BETWEEN 247 and 249 THEN login_errors ELSE 0 END) olderr
    FROM names
    WHERE adate BETWEEN 247 and 252
    GROUP BY company_nameHTH
    John

Maybe you are looking for

  • Variables  are  not  displaying  in  a  order in a query

    Hi friends,     I have  4 vaiables in my query..  i want to dispaly those variables in a  particular order.. for example.. i want to display 1. Country , 2. State , 3. City , 4. Street.. like this order..  but my Query was displaying in a  disorder..

  • Urgent : InfoCube/Dimension

    Step 1 :  In development box, the Cube was empty and did the few changes as below From Dimension1 (already have 4 characteristics) Deleted 3 characteristics from InfoCube via remodeling toolboox  - Check the scheduled conversion and it was successful

  • FTPS podcast producer

    Anybody have any luck publishing with FTPS? I am able to publish via ftp to a filezilla server but am unable with FTPS. I get a "not logged in" error on filezilla. I am using the exact same workflow. I change from ftp to ftps and it does not work. An

  • Dreamweaver CS6 - Guidelines in code view

    Hello, Is there any extension/plugin that allows to make similar view like in Notepad++? Example: http://screenshu.com/static/uploads/temporary/ed/aq/w0/xtgy6g.jpg I mean those vertical guidelines + selecting closing tag that selects also opening tag

  • Measuring AC voltage in Labview 8.5

    I have all my channels set up fine in MAX and the hardware is working correctly.  I'm trying to measure the power as a function of voltage and resistance but my voltage is ac and I'm not sure how to get a single value through the vis.  When I try usi