How to do the following XML/XSLT operation in a Java Oracle function?

I'd like to write a Java method with the following signature...
public static oracle.xdb.XMLType bwdtransform(java.lang.String suname, oracle.sql.CLOB documentText)
The documentText is simply a CLOB that contains the XML. It needs to have two XSLT stylesheets applied to it, then made into an XMLType and returned.
Another requirement is that the stylesheets have to have the Java XPath extensibility, which is available using the namespace "xmlns:java.lang.String="http://www.oracle.com/XSL/Transform/java/java.lang.String".
I've tried a couple of different ways using oracle.xdb.XMLType.transform() and the classes in the oracle package oracle.xml.parser.v2.*, which is what the listing I pasted in below is based on, but I haven't been able to get anything to work. I THINK the XMLType.transform failed because I was using the Java XPath extensions.
I'd appreciate it if there's a standard Oracle recommended way to do this operation, preferably as optimized as possible.
Here btw is the current code I'm using which isn't working. Any variables that you see that aren't initialized in the function are static to the class and initialized in a static {} block including the stylesheets which are instances of XSLStylesheet.
public static XMLType bwdtransform(java.lang.String suname, oracle.sql.CLOB documentText) throws Exception {
parser.parse(new ByteArrayInputStream(clobToString(documentText).getBytes()));
XMLDocument documentTextXMLDocument = parser.getDocument();
XMLDocumentFragment docFrag = processor.processXSL(twiddlerXSLStylesheet, processor.processXSL(adopterXSLStylesheet, documentTextXMLDocument));
Document intermediateDoc = docFrag.getOwnerDocument();
XMLType x = new XMLType(conn, intermediateDoc);
return x;
I haven't been able to find any way to make this work and any any help in that direction would be oh so greatly appreciated.
For completeness, here's the version of Oracle I'm running, according to sqlplus...
SQL*Plus: Release 11.1.0.7.0 - Production on Thu Apr 30 20:24:53 2009
Thanks!
Ralph

The XMLDB way of doing this like this would be something like the following examples:
SELECT XMLtransform(x.xmlcol,
          DBURIType('/XDB/STYLESHEET_TAB/ROW[ID=1]
                           /STYLESHEET/text()').getXML()).getStringVal()
       AS result
FROM po_tab x; or
SELECT XMLtransform(x.xmlcol,
            (SELECT stylesheet FROM stylesheet_tab WHERE id=1)).getStringVal()
          AS result
FROM po_tab x; or use DBMS_XSLPROCESSOR...

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How to generate the following XML-Output?

Hi all,
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Unfortunately the following SQL-Statement does not working:
select xmlElement("DEPARTMENTS_EMPLOYEES",
xmlAttributes(d.deptno as "DEPTNO"),
xmlElement("DNAME", d.dname),
xmlElement("LOC", d.loc),
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from emp e, emp m
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from dept d;
1. When I provide this statement with SQL*Plus
(unfortunately 9.0.1.3.0) then I get the
following output:
XML()
XMLTYPE()
XMLTYPE()
XMLTYPE()
XMLTYPE()
2. When I provide this statement with SQL Navigator
4.3.0.456 then I get the following error:
[1]: (Error): OCI-21560: argument 3 is null, invalid,
or out of range
3. When I execute the following PL/SQL-Code then I get
the XML-Error message:
DECLARE
x CLOB;
xmlstr VARCHAR2(32767);
line VARCHAR2(2000);
BEGIN
x := dbms_xmlquery.getxml('select xmlElement("DEPARTMENT",
xmlAttributes(d.deptno as "DEPTNO"),
xmlElement("DNAME", d.dname),
xmlElement("LOC", d.loc),
xmlElement("EMPLOYEELIST",
(select xmlAgg(xmlElement("EMPLOYEE",
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xmlForest(e.ename as "ENAME",
e.job as "JOB",
e.hiredate as "HIREDATE",
e.sal as "SAL",
e.comm as "COMM",
m.empno as "MGRNO",
m.ename as "MGRNAME"
from emp e, emp m
where e.deptno = d.deptno
and m.empno = e.mgr
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from dept d');
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LOOP
EXIT WHEN xmlstr IS NULL;
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END;
<?xml version = '1.0'?>
<ERROR>oracle.xml.sql.OracleXMLSQLException: Unimplemented Feature</ERROR>
4. When I provide the following PL/SQL-Code then I get the same xml-error:
DECLARE
x CLOB;
xmlstr VARCHAR2(32767);
line VARCHAR2(2000);
BEGIN
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END;
<?xml version = '1.0'?>
<ERROR>oracle.xml.sql.OracleXMLSQLException: Unimplemented Feature</ERROR>
Can I generate the needed XML-Output from Database with SQL or PL/SQL?
Can anybody help me?
Regards
Leonid Pavlov

I have this done with:
DECLARE
qryCtx DBMS_XMLGEN.ctxHandle;
result CLOB;
xmlstr VARCHAR2(32767);
line VARCHAR2(2000);
BEGIN
qryCtx := dbms_xmlquery.newContext('select deptno, dname, loc, cursor(select e.empno, e.ename, e.job,
to_char(e.hiredate,''DD.MM.YYYY'') hiredate, e.sal, e.comm,
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dbms_xmlquery.setRowsetTag(qryCtx, 'DEPARTMENTS_EMPLOYEES');
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But how can I rename the <EMP>-Element to Employees?

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Hi all,
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<ROW>
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<CUSTOMER_ID>1</CUSTOMER_ID>
<ORDER_TOTAL>1200</ORDER_TOTAL>
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</ITEMS>
</ROW>
<ROW>
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Hi, I'm assuming that table columns have the same names as the xml elements in your example.
Try this:
SQL >select xmlelement("ROWSET",
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13                                                                                )
14                                                                     ) from demo_order_items i where i.order_id=o.order_id)
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17                          )
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Max
[My Italian Oracle blog|http://oracleitalia.wordpress.com/2009/12/27/inviare-email-dal-db-utilizzando-utl_smtp/]

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"PACKAGE"
13-AUG-13
15-AUG-13
"2013-08-15:19:56:47"
"INVALID"
"N"
"N"
"N"
1
"GET_LOGIN_CREDENTIALS"
70775
0
"PROCEDURE"
13-AUG-13
13-AUG-13
"2013-08-13:22:26:49"
"INVALID"
"N"
"N"
"N"
1
"APEX_SYS_PCK"
70792
0
"PACKAGE BODY"
15-AUG-13
15-AUG-13
"2013-08-15:19:56:47"
"INVALID"
"N"
"N"
"N"
2
"EMP_MAINT"
70802
0
"PACKAGE"
15-AUG-13
15-AUG-13
"2013-08-15:19:54:39"
"INVALID"
"N"
"N"
"N"
1

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