How to fill array with random number?

I need to fill a 3-dimensional array that has user-controlled dimension sizes with random numbers (1-10). I'm unsure of how to do this. I feel like I have to use the initialize array and maybe the build array functions somehow but I'm not entirely sure. Any help would be appreciated. Thanks.

Something like this
Kudos are always welcome if you got solution to some extent.
I need my difficulties because they are necessary to enjoy my success.
--Ranjeet
Attachments:
Array with random number.vi ‏9 KB

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How to fill an array with random numbers

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import java.util.Random;
class random
 static int[] bull(int size) {
 int[] numbers = new int[size];
 Random select = new Random();
 for(int i=0;i<numbers.length;i++) {
harris:
for(;;) {
int trelos=select.nextInt(10000);
numbers=trelos;
 for(int j=0;j<i;j++) {
if(trelos==numbers[j])
continue harris;
numbers[i]=trelos;
break;
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/*The following method is a simpler method,but it is possible two numbers to be the same*/
static int[] bull2(int size) {
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Random select = new Random();
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 numbers[i]=select.nextInt(9);
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int[] nikos = random.bull(10);
int[] nikos2 = random.bull2(10);
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for(int i=0;i<nikos2.length;i++)
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¿How to fill an array with random letters?

Hello, I was wondering If filling a bidimensional array
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I was wondering If filling a bidimensional array
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>I was wondering If filling a bidimensional array (8x10 for example) with random letters
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Hi,
i'm looking for a fast way to fill an array, respectively an int[8], with all possible combinations of 0 and 1 (or -1 and 1, shouldn't make a difference).
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Thanks,
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Edited by: NikolausO on Oct 30, 2008 4:22 AM

pm_kirkham wrote:
No I replied to message number 5. as the ' (In reply to #5 )' above my post indicates, which was in reply to (a reply) to Sabre150's post which wasn't using enhanced loops, nor has any obvious place where you could use that approach to fill the array.
Though you could pass in an array of the values to fill the array with, and loop over those, instead of using 0 or 1, at which point Sabre's approach becomes the same as your OP, but without the manual unrolling:
import java.util.Arrays;
public class NaryCombinations {
public interface CombinationHandler {
void apply (int[] combination) ;
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calculateCombinations(new int[]{-1, 0, 1}, 4, new CombinationHandler () {
public void apply (int[] combination) {
System.out.println(Arrays.toString(combination));
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recursivelyCalculateCombinations(values, 0, depth, handler, new int[depth]);
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CombinationHandler handler, int[] combination) {
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handler.apply(combination);
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Which looks to use the same basic approach to the generalization I created shortly after posting the original.
public class Scratch1
 * A 'callback' to be invoked with every combination
 * of the result.
 public interface Callback
 * Invoked for each combination.
 * 
 * Each call is passed an new instance of the array.
 * @param array the array containing a combination.
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 if ((values == null) || (values.length < 1))
 throw new IllegalArgumentException("The 'values' must have be at least of length 2");
 callback_ = callback;
 values_ = values.clone();
 array_ = array;
 public Scratch1(final int order, final Callback callback, final int... values)
 this(new int[order], callback, values);
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 public void process()
 process(0);
 * Internal method with no logical external use.
 private void process(int n)
 if (n == array_.length)
 callback_.processArray(array_.clone());
 else
 for (int v : values_)
 array_[n] = v;
 process(n + 1);
 private final Callback callback_;
 private final int[] values_;
 private final int[] array_;
 public static void main(String[] args) throws Exception
 final Callback callback = new Callback()
 public void processArray(int[] array)
 System.out.println(java.util.Arrays.toString(array));
 new Scratch1(6, callback, 2, 1, 0).process();

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in my main class file
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thanx for the help paulcw, but when i removed the seed code it done the same
but i added this to my main class and now it works fine
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Message was edited by:
jave_cool

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How to fill array with random number?

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