How to get pivot table by using dates

Question

Hi,
How to get pivot table by using dates in column.
Below is the sample table and its value is given.
create table sample1
Order_DATE       DATE,
order_CODE       NUMBER,
Order_COUNT   NUMBER
Insert into sample1 (Order_DATE,order_CODE,Order_COUNT) values (to_timestamp('30-SEP-12','DD-MON-RR HH.MI.SSXFF AM'),1,232);
Insert into sample1 (Order_DATE,order_CODE,Order_COUNT) values (to_timestamp('30-SEP-12','DD-MON-RR HH.MI.SSXFF AM'),2,935);
Insert into sample1 (Order_DATE,order_CODE,Order_COUNT) values (to_timestamp('30-SEP-12','DD-MON-RR HH.MI.SSXFF AM'),3,43);
Insert into sample1 (Order_DATE,order_CODE,Order_COUNT) values (to_timestamp('30-SEP-12','DD-MON-RR HH.MI.SSXFF AM'),4,5713);
Insert into sample1 (Order_DATE,order_CODE,Order_COUNT) values (to_timestamp('30-SEP-12','DD-MON-RR HH.MI.SSXFF AM'),5,11346);
Insert into sample1 (Order_DATE,order_CODE,Order_COUNT) values (to_timestamp('29-SEP-12','DD-MON-RR HH.MI.SSXFF AM'),1,368);
Insert into sample1 (Order_DATE,order_CODE,Order_COUNT) values (to_timestamp('29-SEP-12','DD-MON-RR HH.MI.SSXFF AM'),2,1380);
Insert into sample1 (Order_DATE,order_CODE,Order_COUNT) values (to_timestamp('29-SEP-12','DD-MON-RR HH.MI.SSXFF AM'),3,133);
Insert into sample1 (Order_DATE,order_CODE,Order_COUNT) values (to_timestamp('29-SEP-12','DD-MON-RR HH.MI.SSXFF AM'),4,7109);
Insert into sample1 (Order_DATE,order_CODE,Order_COUNT) values (to_timestamp('29-SEP-12','DD-MON-RR HH.MI.SSXFF AM'),5,14336);
select * from sample1;So how to get the data like below.
          order_date
order_code 30-sep-12 29-sep-12
1 232 368
2 935 1380
3 43 133
4 5713 7109
5 11345 14336

Answer 1

Using the extra data I inserted in my previous reply:select ORDER_CODE,
SUM(DECODE(extract (month from ORDER_DATE),1,ORDER_COUNT,0)) JAN,
SUM(DECODE(extract (month from ORDER_DATE),2,ORDER_COUNT,0)) FEB,
SUM(DECODE(extract (month from ORDER_DATE),3,ORDER_COUNT,0)) MAR,
SUM(DECODE(extract (month from ORDER_DATE),4,ORDER_COUNT,0)) APR,
SUM(DECODE(extract (month from ORDER_DATE),5,ORDER_COUNT,0)) MAY,
SUM(DECODE(extract (month from ORDER_DATE),6,ORDER_COUNT,0)) JUN,
SUM(DECODE(extract (month from ORDER_DATE),7,ORDER_COUNT,0)) JUL,
SUM(DECODE(extract (month from ORDER_DATE),8,ORDER_COUNT,0)) AUG,
SUM(DECODE(extract (month from ORDER_DATE),9,ORDER_COUNT,0)) SEP,
SUM(DECODE(extract (month from ORDER_DATE),10,ORDER_COUNT,0)) OCT,
SUM(DECODE(extract (month from ORDER_DATE),11,ORDER_COUNT,0)) NOV,
SUM(DECODE(extract (month from ORDER_DATE),12,ORDER_COUNT,0)) DEC
from SAMPLE1
where trunc(order_date, 'YY') = trunc(sysdate, 'YY')
group by order_code
order by order_code;
ORDER_CODE JAN FEB MAR APR MAY JUN JUL AUG   SEP   OCT NOV DEC
         1   0   0   0   0   0   0   0   0   600   600   0   0
         2   0   0   0   0   0   0   0   0  2315  2315   0   0
         3   0   0   0   0   0   0   0   0   176   176   0   0
         4   0   0   0   0   0   0   0   0 12822 12822   0   0
         5   0   0   0   0   0   0   0   0 25682 25682   0   0Now a bit of explanation.
1) Whenever you pivot rows to columns, no matter what version of Oracle and no matter what method you use, you have to decide in advance how many columns you are going to have and what the names of the columns are. This is a requirement of the SQL standard.
2) I use the WHERE clause to get just the data for this year
3) With EXTRACT, I get just the month without the year.
4) Using DECODE, I put every month's data into the correct column
5) Once I do all that, I can just GROUP BY order_code while SUMming all the data for each month.