How to get the Date format inside the table

I have a startdate column in the db in the format May 5, 2001 12:39:00 PM, when I query it from a view in this way : SELECT startdate, ... FROM ..., it returns the format in the db,
However I have to do this SELECT
decode(startdate, null, 'NOT START'), startdate), ... the result is 5-MAY-01,
then I tried this to_char(startTime, 'Month DD, YYYY HH:MI: A.M.') the results become May 05, 2001 12:39:00 PM. (more space between month and day, and 05 instaed of 5)
Does anybody know how to fix this, so I get exactly what is in the db?
Thanks in advance

No matter what you do if you are storing a date in a column it will get stored in the Oracle's internal 7 byte date format.
The way you get it on retreiving it is as set by your date format. You can either change the default date format for the instance, the individual session or the individual SQL statement(in this case using to_char(date, 'format')).
If you want to store the date in a format you want to store you'll have to store it as char or varchar2.
<BLOCKQUOTE><font size="1" face="Verdana, Arial, Helvetica">quote:</font><HR>Originally posted by George ([email protected]):
I have a startdate column in the db in the format May 5, 2001 12:39:00 PM, when I query it from a view in this way : SELECT startdate, ... FROM ..., it returns the format in the db,
However I have to do this SELECT
decode(startdate, null, 'NOT START'), startdate), ... the result is 5-MAY-01,
then I tried this to_char(startTime, 'Month DD, YYYY HH:MI: A.M.') the results become May 05, 2001 12:39:00 PM. (more space between month and day, and 05 instaed of 5)
Does anybody know how to fix this, so I get exactly what is in the db?
Thanks in advance<HR></BLOCKQUOTE>
When you do to_char() with 'month' oracle blank pads the month to nine characters, the same goes with day too. So to get rid of it you'll have to trim() the month. And if you want to get a single digit for date less than 10 instead of 0x you'll have to do a bit of extra jugglery using translate() or replace().
Hope this helps
Naveen

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