How to handle big number

i am trying to implement wallet applet, there i want to credit 1000 , for this i am passing my apdu like
cla ins p1 p2 lc=2 and 03 e8
1000=03 E8
when i am getting this by
apdu.getBuffer();
its value are change , here e8=232 but here byte array shows different value ,because it support unsigned nature,
how i can get 232 in short variable for E8

Hi,
You could use this:
short amount = Util.getShort(apdu.getBuffer(), ISO7816.OFFSET_CDATA);You can replace ISO7816.OFFSET_CDATA with the offset to the amount if your APDU becomes more complex. You can also validate that the Lc is 2 bytes. I am sure your stored value will not exceed 32,676 (max signed short)?
Cheers,
Shane

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Hi Sridhar Gautham,
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Handle big amount of data

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hans wrote:
> Hello,
>
> I have to analyse a great amount of data (more than 20MByte), that I
> read from a logfile. I can't split these data into smaller parts
> because some of my analysis-methods need all data (regression,....).
>
> Are there any tricks for LabVIEW (5.0.1), how to handle big amounts of
> data?
>
> hans

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Thank you for this answer.
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How to find the number of references to an object in a big application

How to find the number of references created for a given object in a big application environment.
That means, if i give any object name (of my application) as input, then how can i find the[b] number of references created for that particular object ??

Please don't post the same question multiple times.
I've answered your question in the other thread here:
http://forum.java.sun.com/thread.jspa?messageID=4312939

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I take it you might come from an arabic background.
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We had a few visit here when they have come across a snafu. So they exists.

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Attachments:
Desing.png ‏402 KB

I recently wrote some articles about this very subject:
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hi ,
I am using Release 10.2.0.1.0 of Oracle. I am having a scenario in which i am getting poor execution plans due to stale stats , and how should i tackle the scenario. below is the part of my main query which deviates the execution path due to wrong cardinality estimation.
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Plan hash value: 3167980259
| Id | Operation                   | Name                    | Starts | E-Rows | A-Rows |   A-Time   | Buffers | Reads |
|   1 | TABLE ACCESS BY INDEX ROWID| tab1                    |      1 |   1    |    167K|00:01:13.72 |     158K| 12390 |
|* 2 |   INDEX RANGE SCAN          | IDX_N1                  |      1 |   1    |    167K|00:00:13.27 |   13880 |   1736 |
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930254 wrote:
hi ,
I am using Release 10.2.0.1.0 of Oracle. I am having a scenario in which i am getting poor execution plans due to stale stats , and how should i tackle the scenario. below is the part of my main query which deviates the execution path due to wrong cardinality estimation.
      My column c1 of table tab1 holds javatimestamp values i.e. its NUMBER datatype which points to a date and time component only. And we gather stats each weekend on this table tab1.
      below is my query:
      select /*+gather_plan_statistics*/* from tab1
      where c1 BETWEEN 1346300090668 AND 1346325539486    ;
Plan hash value: 3167980259
| Id | Operation                   | Name                    | Starts | E-Rows | A-Rows |   A-Time   | Buffers | Reads |
|   1 | TABLE ACCESS BY INDEX ROWID| tab1                    |      1 |   1    |    167K|00:01:13.72 |     158K| 12390 |
|* 2 |   INDEX RANGE SCAN          | IDX_N1                  |      1 |   1    |    167K|00:00:13.27 |   13880 |   1736 |
     Above shows a big gap in actual and estimated cardinality estimation, and its due to the fact that the HIGH_VALUE (1346203206173 points to 8/29/2012 1:20:06 AM) in DBA_TAB_COLUMN for     column C1 is well below the STARTRANGE(1346300090668 points to 8/30/2012 4:14:51 AM) and ENDRANGE(1346325539486 points to 8/30/2012 11:18:59 AM) of the BETWEEN clause.
     So even gathering stats daily on the table wont help me as because, in morning again it will require updated maxvalue for the column C1 for estimating proper, So how to handle this situation? Dont want to go with 'hint' , want to make the stats proper so that optimizer will automatically pick the right path.Edited by: 930254 on Aug 30, 2012 4:41 AMUm, refresh the stats on a regular basis?
Oracle 10 and later has a default job to do that. Runs at 2200 daily.
If you need an 'on demand' refresh, that's easy enough to set up.

How to find the number of data items in a file written with ArryToFile function?

I have written an array of number in 2 column groups to a file using the LabWindows/CVI function ArrayToFile...Now if I want to read the file with FileToArray Function then how do I know the number of items in the file. during the write time I know how many array items to write. but suppose I want the file to read at some later time then How to find the number of items in the file,So that I can read the exact number and present it. Thanks to all
If you are young work to Learn, not to earn.
Solved!
Go to Solution.

What about:
OpenFile ( your file );
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There are some ways to improve performance of this code, but if you are not reading thousands of lines it's quite fast.
After this part you can dimension the array to pass to FileToArray... unless you want to read it yourself since you already have it open!
Proud to use LW/CVI from 3.1 on.
My contributions to the Developer Zone Community
If I have helped you, why not giving me a kudos?

How to find the number of references created for a given object ??

How to find the number of references created for a given object in a big application environment.
That means, if i give any object name (of my application) as input, then how can i find the[b] number of references created for that particular object ??

Please do not post the same question multiple times.
As for your original question, there is no direct way to do it.
Especially not the way you phrased it,
since objects don't have "names".
Applications also don't have "names".
They have classes and instances.
Also, there are 2 related issues, and I'm not sure which one is the one you asked.
#1. Finding the number of references to the same object.
Eg.
Map<String,String> a = new HashMap<String,String>();
Map<String,String> b = new HashMap<String,String>();
Map<String,String> c = a;In this case, there are only 2 objects.
The first object has (at least) 2 references pointing to it.
The second object has (at least) 1 reference pointing to it.
(There may be more, if the HashMap library keeps
references to these things, or if the HashMap object has
some internal cyclic references...)
If you're asking this, then it can't be done.
It's an active research topic in universities
and software research labs, called "alias analysis".
Type it in google, and you'll see people are working hard
and having little success so far.
#2. Finding the number of instances created from a class.
In this case, what you have to do is to add a counter to
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you increment the counter. Like this:
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For every class you care about, you have to modify its constructor.
Also: when an object is deleted, you won't always know it
(and thus you won't always be able to decrement the counter).
Finalizers cannot always work (read Joshua Bloch's
"Effective Java" book if you don't believe me), but basically
(1) finalizers will not always be called, and
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