How to Ignore the signal?

Question

Insert a number if the number of digits of that number is greater than its average return true else false.
So what i'd like to know , (and btw sorry about the other questions) how can it ignore the signal ?
e.g: number_aux = 53 -> this will be: Number of digits: 2
Media = (5 +3) / 2 = 4
( 2 < 4 ) then return false. now i'd like to find a way to insert -53 (negative) and the output must be the same (false) ignoring de signal "-"
here is my code:
In this code if u inserted a negative ( -6 or -53) the output is always true because e takes in mind the signal . How do i tell him to ignore it?
    System.out.println.... 
      int number _aux =Integer.parseInt(... ....etc
                                          int sum = 0;
          int count = 0;
          int media;
          while (number_aux != 0){
          int digit = number_aux % 10;
          number_aux  /= 10;
          sum += digit;
          if(number_aux  >= 0) count++;
          media =(int) (sum / count);
          return (count > media);thank you so much.
Josh

Answer 1

I already used my brain LOLO , if new the answer i
would not be here ask for help lol.
shiver You forgot to add three or more exclamation marks.
give me a hint , how to ignore the signal without
that method ( using my code)If I'd give you any number, how would you do it? What would there conditions and formula be? Think about that. Programming isn't magic. It's finding a step-wise solution to a problem and writing it down.