How to insert the file name to column

When user upload the file, in order to avoid the double file name conflict, so I need to change the file name to something else, but I still need save the former file name to some column to download the file with correct file name, I know how to rename and upload file, but I don't know how to catch the file name and save it to some column when using addt insert transaction?

Hi,
As I said earlier, you have to maintain the list of filename's "itemdescr" in different temp file and load it an and when required table instead of checking for round robin functionality. If you are looking forward that oracle sqlldr can able to access the filename as one of the parameter then - it might not possible AFAIK.
else perform the direct insert on the table from sqlclient.
- Pavan Kumar N

Similar Messages

How to insert the file name to the start and the end of a SQL file by a powershell script

I just began to learn powershell script and I have a problem that I cannot figure out. I have a lot of .sql files. I need to insert its file name to the beginning of the file (After USE statement) and the end of the file (before the last END statement). Is
there anybody knowing how to do this?
Thanks so much
Regards

Actually, I want to add a insert SQL statement to the beginning of the file and the end of the file. Only the file name is a variable and different among
different files. All the other sql statements are the same and can be hard coded. Hopefully it helps –
The problem I think is that I want to add the same thing (except the file name) to hundreds of sql files and only the file name is different. I do not want
to add it manually and want to use a script to add it –

Looping multiple excel files at a time in ssis and create a new column to insert the files names

Hi Friend,
i have one requirement.
I got around 200 excel files with date as file name like 120101.xls, 120102.xls (YYMMDD).
I am able to loop all the files and insert data but i am unable to load the files names using ssis.
Please can any one help to fix this using script task or any other code..
It is very urgent

Thank You Vaibhav,
I want to insert the file name along with the other columns of data from excel.
like this deriving a new column FILE_NAME
Your ForEach Loop task must be returning the entire file path, I suppose.
1. Get the file name from your file path.
New variable: FileName
Expression : RIGHT(@[User::FilePath],FINDSTRING(REVERSE(@[User::FilePath]),"\\",1)-1)
2. Inside Data flow, after Excel source use Dervied Column and use above @FileName
3. At your OLEDB destinition, use MyFileName.
-Vaibhav Chaudhari

How to Capture the File Names of any extension using ssis

Hello,
Can you please let me know on how to Capture the File Names of any extension(EG : xls,text,.csv etc) at a time and stores in excel file using SSIS?
Any help would be appreciated.
Thanks,
Vinay s

If you need to act differently on each file type separately or if not all types of files are wanted, i.e. the Filespecifier cannot be *.* in the Foreach loop:
In the ssis package
make 3 variables:
to store the file extension, e.g. User::CurrentExtension of type string
to store the filename found in the directory: @CurrentFilename
to store the name of the directory where the files reside e.g. User::CurrentDirectory
make a foreach loop of type Foreach Item enumerator:
in the items list you add each file extension that you need
txt
csv
xls
xlsx
As Variable mappings map the CurrentExtension to Index 0
Inside this foreach loop add another foreach loop of type Foreach File enumerator, in the collection Expressions
add Expression Directory , set to @[User::CurrentDirecotry]
add Expression FileSpec, set to "*." + @[User::CurrentFileExtension]
In the Variable mappings, map Variable user::CurrentFilename to Index 0
Inside this loop use Execute SQL Task to insert the filename in a Excel connection.
Jan D'Hondt - SQL server BI development

How to print the file name in sap

Hi All,
I have requirment like,
there is a folder in my local system, inside that folder there are 10 Excel file like file1.xls,file2.xls..............file10.xls
how to print the file name of all these file in SAp like
file1.xls
file2.xls
file3.xls
file4.xls
file10.xls
Appropriate points will be rewarded.
Thanks in Advance
Arun kumar

Hi,
Still you are facing any problem with this code expalin the problem with details , otherwise close this thread.
Use Method cl_gui_frontend_services=>directory_list_files to read file names for a given directory
after reading the files then Use FM : RSPO_SX_OUTPUT_TEXTDATA to create spool from internal table data and print the data.
sample code :
data: desktop_dir type string.
data: ifiles type table of string.
data: xfiles type string.
data: count type i.
data: filepath type string.
call method cl_gui_frontend_services=>get_desktop_directory
changing
 desktop_directory = desktop_dir .
call method cl_gui_cfw=>flush.
call method cl_gui_frontend_services=>directory_list_files
exporting
 directory = desktop_dir
* filter = '*.xls'
 files_only = 'X'
* DIRECTORIES_ONLY =
changing
 file_table = ifiles
 count = count.
DATA : x_name LIKE tsp03d-name,
 x_dest LIKE tsp03d-padest VALUE 'LOCL',
 x_rows LIKE sxpcklsti1-body_num VALUE 0,
 x_startrow LIKE sxpcklsti1-body_start VALUE 1,
 x_pages LIKE rspotype-pages VALUE 1,
 x_pages_1 TYPE p DECIMALS 2,
 x_rqtitle LIKE sxpcklsti1-obj_descr,
 x_rqcopies TYPE i VALUE 1,
 x_rqowner LIKE trdyse01cm-username,
 x_immediate LIKE pri_params-primm VALUE ' ',
 x_rqid LIKE tsp01-rqident,
 i_contents LIKE solisti1 OCCURS 0 WITH HEADER LINE,
 x_pages = 1.
 x_rqowner = sy-uname.
 x_dest = 'LOCL'.
 x_startrow = 1.
 x_rqcopies = 1.
 x_immediate = 'X' .
 CALL FUNCTION 'RSPO_SX_OUTPUT_TEXTDATA'
 EXPORTING
* name = x_name
 dest = x_dest
 rows = x_rows
 startrow = x_startrow
 pages = x_pages
 rqtitle = x_rqtitle
 rqcopies = x_rqcopies
 rqowner = x_rqowner
 immediately = x_immediate
 IMPORTING
 rqid = x_rqid
 TABLES
 text_data = i_contents
 EXCEPTIONS
 name_missing = 1
 name_twice = 2
 not_found = 3
 illegal_layout = 4
 internal_error = 5
 size_mismatch = 6
 OTHERS = 7.
 IF sy-subrc <> 0.
** MESSAGE ID SY-MSGID TYPE SY-MSGTY NUMBER SY-MSGNO
** WITH SY-MSGV1 SY-MSGV2 SY-MSGV3 SY-MSGV4.
 ENDIF.
Regards
Appana
*Reward Points for helpful answers
Message was edited by: L Appana

How to put the file name in notepad file

dear frank,
how to put the file name in notepad file via power shell. I mean i want to put the file name in that notepad file
for example,
my file name is ABL and in this file data is
02/06/2015,180.00,182.00,176.01,180.50,1575500
02/06/2015,4.20,4.20,4.20,4.20,500
02/06/2015,113.50,113.70,112.91,113.09,157800
02/06/2015,682.01,695.90,682.00,683.19,4250
02/06/2015,213.98,215.00,213.00,214.87,326200
02/06/2015,21.52,21.65,21.52,21.60,4000
02/06/2015,111.00,111.25,108.25,108.91,17100
02/06/2015,52.00,52.00,52.00,52.00,500
and i want to data in this form
ABL,02/06/2015,180.00,182.00,176.01,180.50,1575500
ABL,02/06/2015,4.20,4.20,4.20,4.20,500
ABL,02/06/2015,113.50,113.70,112.91,113.09,157800
ABL,02/06/2015,682.01,695.90,682.00,683.19,4250
ABL,02/06/2015,213.98,215.00,213.00,214.87,326200
ABL,02/06/2015,21.52,21.65,21.52,21.60,4000
ABL,02/06/2015,111.00,111.25,108.25,108.91,17100
ABL,02/06/2015,52.00,52.00,52.00,52.00,500
There are many file like this that i want to be edit
plese tell me how can i do it, i think it is possible via windows power shell.
thanks in advance.

Hi
Just for completeness, what version of VB.NET are you using?
Here is a complete project to copy all the files with the added "ABL," at the start of each line. You need to start a new Project with a BLANK default Form1, and replace all of Form1 code with the code below. When you run this project, you
need to use the 2 buttons to set up the ORIGINAL file folder and a folder to place the copies. You need to check if the file EXTENSION is correct (I assumed txt), and check the text to add to each line is correct. Once all is set up you should have a
big red button to start the operation.
NOTE: it is important that you try this out on a copy of some of the files to verify accuracy BEFORE trying on original files. Make sure you have a good back up of the original files before doing anything else.
' new project with default BLANK Form1
' replace all Form1 code with this code
' WARNING: make sure you have a backup of
' any files you use this application to
' operate on.
Option Strict On
Option Infer Off
Option Explicit On
Public Class Form1
Dim OrigFileFolderPath As String = Nothing
Dim CopyToFolderPath As String = Nothing
Dim lab1, lab2, lab3 As New Label
Dim tb1, tb2, tb3 As New TextBox
Dim b1, b2, b3, b4 As New Button
Dim fb As New FolderBrowserDialog
Dim bgw As New System.ComponentModel.BackgroundWorker
Private Sub Form1_Load(sender As Object, e As EventArgs) Handles Me.Load
Me.Size = New Size(731, 300)
With lab1
.Text = "Original Files Folder Path"
.Location = New Point(15, 5)
End With
With tb1
.Width = 560
.Location = New Point(10, 30)
.BackColor = Color.Khaki
.ForeColor = Color.Maroon
.Font = New Font(Me.Font.FontFamily, 12)
.BorderStyle = BorderStyle.FixedSingle
.Anchor = AnchorStyles.Top Or AnchorStyles.Left Or AnchorStyles.Right
End With
With lab2
.Text = "Copy Files to Folder Path"
.Location = New Point(15, 125)
End With
With tb2
.Width = 665
.Location = New Point(10, 150)
.BackColor = Color.Khaki
.ForeColor = Color.Maroon
.Font = New Font(Me.Font.FontFamily, 12)
.BorderStyle = BorderStyle.FixedSingle
.Anchor = AnchorStyles.Top Or AnchorStyles.Left Or AnchorStyles.Right
End With
With lab3
.Text = "File Ext"
.Location = New Point(600, 5)
.Anchor = AnchorStyles.Top Or AnchorStyles.Right
End With
With tb3
.Text = ".txt"
.Width = 80
.Location = New Point(590, 30)
.BackColor = Color.Khaki
.ForeColor = Color.Maroon
.TextAlign = HorizontalAlignment.Center
.Font = New Font(Me.Font.FontFamily, 12)
.BorderStyle = BorderStyle.FixedSingle
.Anchor = AnchorStyles.Top Or AnchorStyles.Right
End With
With b1
.Text = "Choose Original Files Folder Path"
.AutoSize = True
.Location = New Point(10, 65)
End With
With b2
.Text = "Choose Copy Files to Folder Path"
.AutoSize = True
.Location = New Point(10, 185)
End With
With b3
.Text = "DO THE COPY"
.AutoSize = False
.Size = New Size(240, 50)
.BackColor = Color.Red
.ForeColor = Color.White
.Font = New Font(Me.Font.FontFamily, 20, FontStyle.Bold)
.Location = New Point(420, 80)
.Anchor = AnchorStyles.Top Or AnchorStyles.Right
.Visible = False
End With
With b4
.Text = "CANCEL JOB"
.AutoSize = False
.Size = New Size(240, 50)
.BackColor = Color.Red
.ForeColor = Color.White
.Font = New Font(Me.Font.FontFamily, 20, FontStyle.Bold)
.Location = New Point(420, 80)
.Anchor = AnchorStyles.Top Or AnchorStyles.Right
.Visible = False
End With
Me.Controls.AddRange({lab1, lab2, lab3, tb1, tb2, tb3, b1, b2, b3, b4})
With bgw
.WorkerReportsProgress = True
.WorkerSupportsCancellation = True
End With
AddHandler bgw.DoWork, AddressOf bgw_DoWork
AddHandler bgw.RunWorkerCompleted, AddressOf bgw_Completed
AddHandler b1.Click, AddressOf b1_Click
AddHandler b2.Click, AddressOf b2_Click
AddHandler b3.Click, AddressOf b3_Click
AddHandler b4.Click, AddressOf b4_Click
End Sub
Private Sub b1_Click(sender As Object, e As EventArgs)
fb.SelectedPath = My.Computer.FileSystem.SpecialDirectories.MyDocuments
fb.ShowNewFolderButton = False
Dim r As DialogResult = fb.ShowDialog
If r = Windows.Forms.DialogResult.OK Then
tb1.Text = fb.SelectedPath
If IO.Directory.Exists(tb1.Text) AndAlso IO.Directory.Exists(tb2.Text) AndAlso Not (tb1.Text = tb2.Text) Then
If tb3.Text = Nothing Then
redo: tb3.Text = InputBox("Enter the file extension that you want to copy/change", "FILE EXTENSION")
If tb3.Text = Nothing Then GoTo redo
End If
b3.Visible = True
Else
b3.Visible = False
End If
End If
End Sub
Private Sub b2_Click(sender As Object, e As EventArgs)
fb.SelectedPath = My.Computer.FileSystem.SpecialDirectories.MyDocuments
fb.ShowNewFolderButton = True
Dim r As DialogResult = fb.ShowDialog
If r = Windows.Forms.DialogResult.OK Then
tb2.Text = fb.SelectedPath
If IO.Directory.Exists(tb1.Text) AndAlso IO.Directory.Exists(tb2.Text) AndAlso Not (tb1.Text = tb2.Text) Then
If tb3.Text = Nothing Then
redo: tb3.Text = InputBox("Enter the file extension that you want to copy/change", "FILE EXTENSION")
If tb3.Text = Nothing Then GoTo redo
End If
b3.Visible = True
Else
b3.Visible = False
End If
End If
End Sub
Private Sub b3_Click(sender As Object, e As EventArgs)
b3.Visible = False
b4.Visible = True
If Not tb3.Text.StartsWith(".") Then tb3.Text = "." & tb3.Text
bgw.RunWorkerAsync()
End Sub
Private Sub b4_Click(sender As Object, e As EventArgs)
bgw.CancelAsync()
End Sub
Private Sub ReadPWFile(fn As String)
Dim filename As String = My.Computer.FileSystem.GetName(fn)
Dim barename As String = IO.Path.GetFileNameWithoutExtension(fn)
Dim copyto As String = tb2.Text & "\" & filename
Dim line As String = Nothing
Dim lines As New List(Of String)
Using sr As IO.StreamReader = New IO.StreamReader(fn)
Do
line = sr.ReadLine()
If Not line = Nothing Then
lines.Add(barename & "," & line)
End If
Loop Until line = Nothing
End Using
Using sw As IO.StreamWriter = New IO.StreamWriter(copyto)
For Each s As String In lines
sw.WriteLine(s)
Next
End Using
End Sub
Private Sub bgw_DoWork(sender As Object, e As System.ComponentModel.DoWorkEventArgs)
Dim ftc As Collections.ObjectModel.ReadOnlyCollection(Of String) = My.Computer.FileSystem.GetFiles(tb1.Text)
For Each f As String In ftc
If bgw.CancellationPending Then
e.Cancel = True
Exit For
End If
Dim ex As String = My.Computer.FileSystem.GetFileInfo(f).Extension.ToLower
If My.Computer.FileSystem.GetFileInfo(f).Extension.ToLower = tb3.Text.ToLower Then
ReadPWFile(f)
End If
Next
End Sub
Public Sub bgw_Completed(sender As Object, e As System.ComponentModel.RunWorkerCompletedEventArgs)
tb1.Text = Nothing
tb2.Text = Nothing
b3.Visible = False
b4.Visible = False
MessageBox.Show("Finished copying files", "Job Completed")
End Sub
End Class
Regards Les, Livingston, Scotland

How to hide the file name (the bizarre number assigned by the camera) when exporting an image version in aperture from an album. Pl understand I want to keep the file name in the project library version.

how to hide the file name (the bizarre number assigned by the camera) when exporting an image version in aperture from an album. Pl understand I want to keep the file name in the project library version.

Within Aperture you have Images, which are constructed on-the-fly from two files (the Master and the Version). You get an image-format file _only_ when you export an Image. You select the file name (usually a scheme) when you create an image-format file (that is, when you export). Look under "Aperture→Presets→File Naming" for built-in Presets. You can, of course, create your own or customize any provided.
The Preset is applied to only the file newly created by your "export" command. It is not applied to the Image in Aperture (unless you rename your Versions or your Masters).

How to find the File name using the FTP Adapter

hi all,
how to find the File name using the FTP Adapter with BPEL.
Regards

Found the solution for this.
First In the mediator's routing rule use assign property $in.property.jca.file.FileName to $out.property.jca.file.FileName
In the BPEL's receive activity go to the properties tab and get the property to a BPEL variable. That should do it.
Thanks for the posts

How to include the file name as an XML field

Hi,
I'm using a file adapter for process a flat file and convert it into an XML. Does anybody knows how to include the file name into an XML field.
Ex.
I process the file named XXIMN21022007.txt and I need an XML like:
<MT_FILE>
<field1></field1>
<field2></field2>
<field3></field3>
<filename>XXIMN21022007.txt</filename>
</MT_FILE>
Regards
Gonzalo

Just go for dynamic configuration.
Check the sender file adapter to write the filename in the header (as explained in Michal's blog) and then read that header in some mapping.
U can use that even in simple message mappings.
http://help.sap.com/saphelp_nw2004s/helpdata/en/43/03612cdecc6e76e10000000a422035/frameset.htm
Your code for the filename tag would be something like:
DynamicConfiguration conf = (DynamicConfiguration) container
 .getTransformationParameters()
 .get(StreamTransformationConstants.DYNAMIC_CONFIGURATION);
DynamicConfigurationKey key = DynamicConfigurationKey.create(
 http://sap.com/xi/XI/System/File,
 FileName);
return conf.get(key);
Regards,
Henrique.

How OSB archive the file name

How OSB archive the file name?
I have used JCA adapter to archive file while reading in OSB and OSB does archive the file with different name.
But OSB is creating the file with name as understandable form. Is it possible to give my own defined name while archiving the file(s).
Please help me !
-Thanks

I dont think it is possible to change the names of the archive files once OSB processes the file. I haven't found any references of the same in the JCA adapter documentation as well.
You can check with Oracle support if this is feasible.
Thanks,
Patrick.

MessageFileUpload how to retrive the file name?

Hi there guys,
maybe it's a stupid question but i cannot find the answer :_( any of you knows how to retrive the file name i am going to upload from the messageFIleUpload item?
Thank You, Pier Paolo.
Edit: Found in another post!! eeheh LAZY ME!! :_)
Message was edited by:
PandreoL

Nice to know that you found the solution. You could have as well used the javadoc for the same.
--Shiv

Import From Folder: How to Extract the File Name in a Custom Column.

Hello All
Here´s what we´re trying to do:
We have a folder with csv files named like this:
Sales_2013-02-05.csv
Sales_2013-02-04.csv
Sales_2013-02-03.csv
Sales_2013-02-02.csv
Sales_2013-02-01.csv
And in the csv files there are the sales columns but not the date column.
So we want to extract the date from the file name.
I´ve tried entering = Source[Name] in a custom column, but it adds a "LIST" link, and on a click on expand, it adds ALL file names from the folder in each row, instead of just the needed one.
If we could get the proper file name in each row (from where they got extracted), we could split the column and get the date from there. But I don´t know how put the filename there properly.
Can you help?

This isn't entirely straightforward, but it's definitely possible. What you need to do is to apply all of your transforms to each individual file instead of the combined files. I do that as follows:
1) Use Folder.Files as generated by the GUI to look at the list of my files.
2) Pick one file and do all the transformations to it that I want to apply to all of the files. Sometimes, this just amounts to letting the autodetection figure out the column names and types.
3) Go into the advanced editor and edit my code so that the transformations from step 2 are applied to all files. This involves creating a new function and then applying that function to the content in each row.
4) Expand the tables created in step 3.
As an example, I have some files with names that match the ones you suggested. After steps 1 + 2, my query looks like the following:
let
    Source = Folder.Files("d:\testdata\files"),
    #"d:\testdata\files\_Sales_2013-02-01 csv" = Source{[#"Folder Path"="d:\testdata\files\",Name="Sales_2013-02-01.csv"]}[Content],
    #"Imported CSV" = Csv.Document(#"d:\testdata\files\_Sales_2013-02-01 csv",null,",",null,1252),
    #"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
    #"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
in
    #"Changed Type"
For step 3, I need to take steps 3-5 of my query and convert them into a function. As a check, I can apply that function to the same file that I chose in step 2. The result looks like this:
let
    Source = Folder.Files("d:\testdata\files"),
    Loader = (file) =>
        let
            #"Imported CSV" = Csv.Document(file,null,",",null,1252),
            #"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
            #"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
        in
            #"Changed Type",
    #"d:\testdata\files\_Sales_2013-02-01 csv" = Source{[#"Folder Path"="d:\testdata\files\",Name="Sales_2013-02-01.csv"]}[Content],
    Loaded = Loader(#"d:\testdata\files\_Sales_2013-02-01 csv")
in
    Loaded
Now I apply the same function to all of the rows, transforming the existing "Content" column into a new value:
let
    Source = Folder.Files("d:\testdata\files"),
    Loader = (file) =>
        let
            #"Imported CSV" = Csv.Document(file,null,",",null,1252),
            #"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
            #"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
        in
            #"Changed Type",
    Transformed = Table.TransformColumns(Source, {"Content", Loader})
in
    Transformed
Finally, I need to expand out the columns in the table, which I can do by clicking on the expand icon next to the Content column header. The resulting query looks like this:
let
    Source = Folder.Files("d:\testdata\files"),
    Loader = (file) =>
        let
            #"Imported CSV" = Csv.Document(file,null,",",null,1252),
            #"First Row as Header" = Table.PromoteHeaders(#"Imported CSV"),
            #"Changed Type" = Table.TransformColumnTypes(#"First Row as Header",{{"One", Int64.Type}, {"Two", type text}, {"Three", type text}})
        in
            #"Changed Type",
    Transformed = Table.TransformColumns(Source, {"Content", Loader}),
    #"Expand Content" = Table.ExpandTableColumn(Transformed, "Content", {"One", "Two", "Three"}, {"Content.One", "Content.Two", "Content.Three"})
in
    #"Expand Content"
From here, you should be able to get to what you want.

How can I insert the file name automatically on all pages?

I would like that on all pages of my keynote presentations the file name is inserted automatically in a footer as eg in EXCEL and Word.

Oh yeah! Very similar to that one is Print Window. I use it all the time.
http://www.printwindowapp.com
It costs $20 if you want all the extra features the free version doesn't have. But I've always used the free version. Nothing in the paid version I need.

How to change the file name of pdf file in html page?

Hi,
Actually my requirement is to upload 50 PDF files containing javascript in each file into flex page with the help of one html page.
i did the the javascript part by using batch processing.
now i want to call those pdf files one after another without changing the file name in html page
the code written in html page is
<html>
 <body>
 <object id="PDFObj"
 data="http:\\localhost\pdf\20090807 - Batch 630.pdf"
 type="application/pdf"
 width="100%"
 height="100%">
 </object>
 </body>
</html>
So every time i have to change that file name to acess another file.
Is there is any other way to sort this problem????
Plz anyone help me to sort out this problem with some code or some example.

I once had a similar task for creating a webpage that I only use on my computer--a webpage that accesses PDF's and SWF's font previews from a list of fonts as "a href's". What you must do is utilize the power of the command line, whether on a Mac on a PC or on Linux, Linux being the most powerful (although Mac IS Unix). You must utilize variables, variable replacement, and then a command to print out the results of a "for" or "while" loop to a text file which will be your HTML file with each individual link automatically built into the HTML code. You will have a list of 50 links. If you are simply looking for a GOOGLE type functionality where you click on "Next" and "Previous" you will have to dig deeper into variable replacement--this I don't know how to do yet but there are books for command-line shell interpreters. One shell interpreter is called "bash" (born-again shell) and there is a book on the market which gives a detailed example of how to replace variables in a shell script. Again, I don't know how it works. I will try to learn this at a later time when I am more seasoned with the basics of shell scripting.

How to store the File Name from a Unix Directory into a ODI variable?

Hi,
I have built a ODI package with the following steps:
1. ODI is polling for a flat file in a Unix directory. I have used OdiFileWait tool for this purpose. Here the file name is not fixed, so I am using wild character (*) to poll for file. Example: DF*ABC1*.DAT where the first wild character denotes 1 letter and the second wild character denotes 2 digits.
2. In the second step, if the file is found, I am moving the file to ODI file server path (../oracledi/demo/file). Here I have used ODIFileMove tool.
3. Then I am using an ODI Interface to Load the file data into a Oracle database table.
4. I am using a Process log table to keep the log for each step I am executing in ODI that is ODIFileWait, ODIFileMove, Interface etc. for each file. In this table a row needs to be inserted after ODIFileWait tool gets the file, with the File Name and File Date. Later on this row will be updated as the consequent steps are executed.
Here is my concern, I need to get the exact File Name of the file after ODIFileWait gets the file and I need to insert that in the Process Log table after the ODIFileWait step gets a file. So if I can store the File Name in a ODI Variable, I can insert it into the Process log table at this point. This I am not able to do.
The files are coming in a different directory (not in ODI file server path), So after getting the file it is moved to ODI file server path (../oracledi/demo/file)
The Files which I am processing are fixed length format. Also, the File name and File Date is stored in the 1st Record(Header record) of the files.
Kindly provide me suggestions to implement this in my code.
Thanks and Regards,
Anik
Edited by: 809820 on Nov 10, 2010 11:36 PM

Look at this link -http://odiexperts.com/getting-one-or-several-unknown-files-from-a-directory
change the command to fetch the ls command and write into File and then using either java or jython break the data and fetch the file name and date and insert into log table.
(or)
you can use the os.system command and get the complete ls command into string and then process and insert it.
Let us know if you need any other help.

How to insert the file name to column

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