How to join entity in the EJBQL?

Dear all,
I have written the following EJBQL:
select o from Commitment o join o.invoiceStat i where o.companyCode = 'HKC' and o.item = 'ABCD01' and i.year = 2008
The entity class is as follows:
public class Commitment implements Serializable {
@Column(name="commitment_amt",nullable = false)
private Double commitmentAmt;
@Id
@Column(name="item_code",nullable = false)
private String item;
@Id
@Column(name="institution_code",nullable = false)
private String companyCode;
@OneToMany(mappedBy = "commitment")
private List<InvoiceStatistic> invoiceStat;
I join the invoiceStat in the EJBQL and also I need to filter, ie. i.year = 2008,
but maybe because of invoiceStat is a OneToMany List Object, the EJBQL didn't filter using i.year=2008.
How could I filter the OneToMany ? Please help
Thanks.

What is this forum called? What languages does it focus on?
Have you bothered to even read what stands at the top of this page and every other page in this forum?
h2. SQL and PL/SQL
Not Enterprise Java Beans bastardised query language called EJBQL.

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>> so the Sample_Tester_Relationship would always have the sample_nbr value and <something>_timestamp regardless. But it would only JOIN the tester_id and its DATETIME, only IF these 2 DATETIME values were close, and the DATEDIFF interval was set
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(sample_nbr CHAR(12) NOT NULL PRIMARY KEY
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ON DELETE CASCADE,
tester_id CHAR(10) NOT NULL
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ON DELETE CASCADE,
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--CELKO-- Books in Celko Series for Morgan-Kaufmann Publishing: Analytics and OLAP in SQL / Data and Databases: Concepts in Practice Data / Measurements and Standards in SQL SQL for Smarties / SQL Programming Style / SQL Puzzles and Answers / Thinking in
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Dear all,
I have written the following EJBQL:
select o from Commitment o join o.invoiceStat i where o.companyCode = 'HKC' and o.item = 'ABCD01' and i.year = 2008
The entity class is as follows:
public class Commitment implements Serializable {
@Column(name="commitment_amt",nullable = false)
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I join the invoiceStat in the EJBQL and also I need to filter, ie. i.year = 2008,
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