How to loop with varying values depending on where you are in the loop

Question

Hi,
I have need of loops / nested loops that pick different figures depending on where you are in the loop.
The whole function needs to run through 'ml' times. 'ml' is a dynamic figure.
Loop 1 = While the loop is within the first 12 iterations, 'exconemp' must equal 100. For iterations 13 - 24, 'exconemp' must equal 102.5, for 25 - 36 it will be 105.06, for 37 - 48 it will be 107.69. This needs to change every 12th iteration until it has reached 'ml'. The calculation takes the value of the previous 'exconemp' and then multiplies that by 0.025.
Loop 2 = While the loop is within the first 120 iterations, 'abc' must equal 0.015 and any further iterations must use 0.01. This must also work in a way to figure out whether 'ml' is higher or lower than 120 and work accordingly.
My main issue is this - how do I get the loops to run through as this:
While the iteration is < 12, do this, THEN take the final figure (12th iteration) and start on 13 - 24, do this THEN etc etc.
How do I produce a THEN statement? I can get the code to pick up the final values, but not change along the way.
I think that I may be better creating an array for Loop 1, but I am not entirely convinced of this. I also think it would be better/tidier if I can get 'month 1 total' and 'month 2 total' into the loops, but am not sure on how to do this.
The values that I need to produce are (only first 36 shown):
1 - 12 = 125.55, 251.65, 378.31, 505.52, 633.29, 761.63, 890.53, 1019.99, 1150.03, 1280.63, 1411.81, 1543.57
13 - 24 = 1679.05, 1815.12, 1951.79, 2089.06, 2226.93, 2365.41, 2504.50, 2644.20, 2784.52, 2925.45, 3067.00, 3209.18
25 - 36 = 3355.19, 3501.85, 3649.15, 3797.11, 3945.71, 4094.96, 4244.87, 4395.44, 4546.68, 4698.57, 4851.14, 5004.38
var ml = 240 // dynamic figure, multiple of 12 up to 780
var exconemp;
var exconem = 100;
var inf = 0.025;
var tree;
var tec;
var power;
var fvis;
var abc;
var fvee;
var tfv;
function myfunction() {
//Loop 1
//while (ml <= 12) {
  exconemp = exconem;
//while (ml > 12) {
// exconemp = exconem*inf;
//end Loop 1
  trace("exconemp=", exconemp); // employees contribution
tree = exconemp/(1-0.2)-exconemp;
tec = exconemp + tree;
  trace("tree", tree);
  trace("tec", tec);
power = Math.pow(1+0.07, 1/12);
//Loop 2
//while (ml <= 120) {
  abc = 0.015;
//while {
  //abc = 0.01;
//end Loop 2
fvis = power*(1-abc/12);
trace("fvis=", fvis);
fvee = tec*fvis;
trace("fvee=", fvee); // month 1 total
tfv = (tec+fvee)*fvis;
trace("tfv=", tfv); // month 2 total
for (var i:Number = 0; i < ml; i++)
      tfv = (tec+tfv)*fvis;
  trace("tfvloop=", tfv);
I hope that I have explained this well enough.
Many thanks in advance.

Answer 1

I think this will do it although I am not quite getting the numbers you posted.
stop();
var ml = 48; // dynamic figure, multiple of 12 up to 780
var exconemp;
var exconem = 100;
var inf = 0.025;
var tree;
var tec;
var power;
var fvis;
var abc = 0.15;
var fvee;
var tfv;
myfunction();
function myfunction()
    exconemp = exconem;
        for(var index:uint = 1; index <= ml; index++)
            trace(index + "--------------------------------");
                tree = exconemp/(1-0.2)-exconemp;
                tec = exconemp + tree;
                power = Math.pow(1+0.07, 1/12);
                fvis = power*(1-abc/12);
                fvee = tec*fvis;
                    if(index == 1)
                        trace("month 1 total=", fvee);
                    else if(index == 2)
                        tfv = (tec+fvee)*fvis;
                        trace("month 2 total=", tfv); // month 2 total
                    else
                        tfv = (tec+tfv)*fvis; //now that we are here the tfv self perpetuates on itself
                        trace("month " + index + " total=", tfv); // month n total
            if(index % 12 == 0)
                exconemp = exconemp*(1+inf);
                trace("changed exconemp to: " + exconemp);
            if(index % 120 == 0)
                abc = .01;
                trace("changed abc to: " + abc);