How to receive large files

Hi,
I own a N82 and in a dillema.My phone shows "low memory error" while receving a large file(104 mb) even though the inbox is empty but can receive files of 30-40 mb.How can i solve this problem.

The phone allocates specific memory quota for contacts, messages.
Your inablity to receive 104 MB file is due to this reason.
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How to upload large file with http via post

Hi guys,
Does anybody know how to upload large file (>100 MB) use applet to servlet with http via post method? Thanks in advance.
Regards,
Mark.

Hi SuckRatE
Thanks for your reply. Could you give me some client side code to upload a large file. I use URL to connect to server. It throws out of memory exception. The part of client code is below:
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+(servletConnection.getInputStream()));
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byte abyte[] = new byte[2048];
int cnt = 0;
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Regards,
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I am having trouble receiving large files using a T1 line.

I can receive large files (3-10meg) using any connection other than T1. Is there a setting I need to change on my Macbook pro?

Obviously your talking about a setting in a program?
Maybe Double NAT ?
Would help if you gave a description of what the program your using is.
What's your result on http://www.speedtest.net

Can I receive large files with Adobe Send?

Does Adobe Send make it possible to receive large files?

The incoming address can be whatever one is most preferable for you (just let the sender know). When you receive an email from Send, it just includes a link to the sent file. That way, you don't bump up against any file size limitations that your email client might impose.
Best,
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How to transfer large files(1GB) to pc

How to transfer large files(1GB) to pc

Or possibly alternatively, and if really desperate, upload it to file distribution service like Fileserve or Rapidshare and then download it from the other machine (and then delete the upload). Many of these services have a free mode although they may have size limitations and they certainly throttle the download speed down (Rapidshare may be one of the worse, Fileserve one of the best). Personally I never tried something the size of 3GB. What I do see is that stuff that large is generally broken up into multiple files to get around the size limitations and to be glued together when all the parts are downloaded.
Just throwing this "out there" as an alternative but as I said, you probably would need to really be desparate to go this route

Along the lines of How To Lead Large Files

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bufReader = new BufferedReader(new InputStreamReader(new FileInputStream(fileName)));
This is the error I get on that statement -
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at java.io.FileInputStream.open(Native Method)
at java.io.FileInputStream.<init>(FileInputStream.java:68)
at com.cofinity.importer.MyFileReader.open(MyFileReader.java:40)
at com.cofinity.importer.MyFileReader.main(Compiled Code)
The statement works fine on files less than 220 MB. It breaks somewhere between 220 and 804 MB.
From the error message it seems that the underlying Native call can't handle opening such a large file. I've searched for the "value to larg" sub-message and found nothing. I tried eliminating the BufferedReader and just using the InputStreamReader, but I received the same error.
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Well it appears to fail in open(). I tried your code on a binary file of size 25739135241 bytes (23.9+ gibibytes) on AIX and it did just fine, so it may be something in the runtime, try upgrading to a newer JDK/SDK, failing that, use the OS to stream in your data:
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How to Expire Large Files using File Server Resource Manager

Is there a way to expire Large Files over 2GB that have not been accessed in 2 years.
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Hi Eddie,
FSRM can help report large files and also can help move old files to a folder, but I did not found a way to combine them in a single process.
Instead how about using Robocopy?
You can run robocopy /min:xxx /minlad:xxx <source> <target>.
/MIN:n :: MINimum file size - exclude files smaller than n bytes.
/MINLAD:n :: MINimum Last Access Date - exclude files used since n.
(If n < 1900 then n = n days, else n = YYYYMMDD date).
Please remember to mark the replies as answers if they help and un-mark them if they provide no help. If you have feedback for TechNet Support, contact [email protected]

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>
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We have a requirement where the Files are picked up from the sftp location and sent to the Fileshare. There is no processing, just the ports using PassThru Pipleine.. It doesnot work well when the file sizes are large. Now we have a file which is of 9GB
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Please mark this post accordingly if it answers your query or is helpful.

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Hi, here is an I/O challenge: I need to copy large binary files under windows in one of my apps. File size can be above 2 GB. The copying should be as fast as possible. What would be the fastest way to do this?
Here is what I've tried so far:
1) Use FileInputStream/FileOutputStream with a byte buffer (see copy1 below)
2) Use BufferedInputStream/BufferedOutputStream (see copy2 below)
3) Use java.nio.FileChannel#transferTo (see copy3 below)
4) Use a shell copy command (see copy4 below)
Testing the four methods with a 500 MB file I get
1) 525271525 Byte in 47141 ms (11142 kByte/s)
2) 525271525 Byte in 68969 ms (7616 kByte/s)
3) 525271525 Byte in 38765 ms (13550 kByte/s)
4) 525271525 Byte in 37984 ms (13828 kByte/s)
This is on a Pentium 4, 2.4 GHz, 512 MB RAM, Windows XP with JDK 1.4.2.
Hence, my favorite method would be 3), since it is more portable than 4).
However, with java.nio.FileChannel#transferTo I get exceptions for files larger than 2 GB. The exception is
java.io.IOException: Falscher Parameter
at sun.nio.ch.FileChannelImpl.map0(Native Method)
at sun.nio.ch.FileChannelImpl.map(FileChannelImpl.java:673)
at sun.nio.ch.FileChannelImpl.transferToTrustedChannel(FileChannelImpl.java:421)
at sun.nio.ch.FileChannelImpl.transferTo(FileChannelImpl.java:490)leading me to suspect that the long values used by Java to specify the file length are not supported by the native code, and that they may be downcast to a 32-bit signed number. (If anyone could shed some more light on this, I'd be grateful!) So, is there a better way than using 4), a shell copy command?
Following is the code I used to for my test:import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.nio.channels.FileChannel;
/** Class for testing different ways to copy files */
public class TestCopy
/** i/o buffer size */
public static final int BUF_SIZE = 1024 * 1024;
/** Copy method, using FileInputStream and byte buffer */
void copy1(File source, File target) throws IOException
    FileInputStream in = new FileInputStream(source);
    FileOutputStream out = new FileOutputStream(target);
    byte[] buf = new byte[BUF_SIZE];
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    while ((i = in.read(buf, 0, BUF_SIZE)) != -1)
      out.write(buf, 0, i);
    in.close();
    out.close();
/** Copy method, using BufferedInputStream */
void copy2(File source, File target) throws IOException
    BufferedInputStream in =
      new BufferedInputStream(new FileInputStream(source), BUF_SIZE);
    BufferedOutputStream out =
      new BufferedOutputStream(new FileOutputStream(target), BUF_SIZE);
    int i;
    while ((i = in.read()) != -1)
      out.write(i);
    in.close();
    out.close();
/** Copy method, using FileChannel#transferTo */
void copy3(File source, File target) throws IOException
    FileChannel in = new FileInputStream(source).getChannel();
    FileChannel out = new FileOutputStream(target).getChannel();
    in.transferTo(0, in.size(), out);
    in.close();
    out.close();
/** Copy method, using command shell copy */
void copy4(File source, File target) throws IOException
    Process p =
      Runtime.getRuntime().exec(
        new String[] {
          "cmd",
          "/C",
          "copy",
          "/Y",
          "/B",
          source.getAbsolutePath(),
          target.getAbsolutePath()});
    int j;
    try
      j = p.waitFor();
      if (j != 0)
        throw new IOException("copy returned exit code " + j);
    catch (InterruptedException e1)
public static void main(String[] args)
    if (args.length != 2)
      System.out.println("usage: java TestCopy <sourceFile> <targetFile>");
      return;
    File source = new File(args[0]);
    File target = new File(args[1]);
    if (!source.exists())
      System.out.println("File not found: " + args[0]);
      return;
    TestCopy tc = new TestCopy();
    try
      long time = System.currentTimeMillis();
      tc.copy1(source, target);
      time = System.currentTimeMillis() - time;
      System.out.println(
        "Copy1: "
          + source.length()
          + " Byte in "
          + time
          + " ms ("
          + source.length() / time
          + " kByte/s)");
      time = System.currentTimeMillis();
      tc.copy2(source, target);
      time = System.currentTimeMillis() - time;
      System.out.println(
        "Copy2: "
          + source.length()
          + " Byte in "
          + time
          + " ms("
          + source.length() / time
          + " kByte/s)");
      time = System.currentTimeMillis();
      tc.copy3(source, target);
      time = System.currentTimeMillis() - time;
      System.out.println(
        "Copy3: "
          + source.length()
          + " Byte in "
          + time
          + " ms("
          + source.length() / time
          + " kByte/s)");
      time = System.currentTimeMillis();
      tc.copy4(source, target);
      time = System.currentTimeMillis() - time;
      System.out.println(
        "Copy4: "
          + source.length()
          + " Byte in "
          + time
          + " ms("
          + source.length() / time
          + " kByte/s)");
    catch (IOException e)
      e.printStackTrace();
}Cheers, HJK

Hmm, I guess I have to agree with jschell. Runtime.exec("cmd /c copy <file1> <file2>"); is the way to go.
The FileChannell#transferTo method in a loop, as asjf suggested, is not much slower, but it's a workaround. Using JNI to call the system command, is probably not worth the effort. I can't see how it will be faster than calling the shell copy command.
Thank you all for your help! Cheers, HJK

Can anyone advise on how to share large files over the net?

Hi all.
So I need to share large video files over the net.
The files will be between 5 and 10 GB
Does anyone have a solution for this?
I have been using my ftp program and just giving the recipient the download link.
But its affecting my upload quota and the recipients download quaota with our ISP's.
Is there an easier way at all?
Thanks.

Contact the ISP for a temporary exception on the quota, or to get an explanation of how long before you can send a second segment for the download. You can split large downloads by UUEncoding them, or making separate disk image segments with Disk Utility. You could also find out if any local WiFi hotspots don't have a quota issue. Lastly, you could send a thumbdrive by mail.

How to receive large files

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