How to reuse a response from a server in the next request?

Question

Hello all,
I am invoking the doGet method to get authenticated by the clickatell's server... the server responds with a "Ok: xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx" (not exact values) message in a fresh html page. This is the status code and its session_id after authentication.
The problem is, how to reuse the session_id value in a request to invoke the doPost method?
Can anyone help with an idea?
public void doGet(HttpServletRequest req, HttpServletResponse res)
throws ServletException, IOException {
     String urlStr = new String ("http://api.clickatell.com/http/auth?api_id="
     + api_id + "&user="
     + username + "&password=" + password);
     res.sendRedirect(res.encodeRedirectURL(urlStr)) ;     
public void doPost (HttpServletRequest req, HttpServletResponse res)
throws ServletException, IOException {          
     String msg, to;
     msg = req.getParameter("msg");
     to = req.getParameter("to");          
     String urlStr = new String ("http://api.clickatell.com/http/sendmsg?session_id=" +sessionID + "&to=" + to + "&text=" + msg);
HttpServletResponseWrapper hsrw = new HttpServletResponseWrapper(res);               
     res.sendRedirect(res.encodeRedirectURL(urlStr));
}

Answer 1

Hello,
Can you try with the following code after doing appropriate modifications for your requirements.
package servlet;
import javax.servlet.http.*;
import javax.servlet.*;
import java.io.*;
import java.net.*;
public class TestServlet extends HttpServlet {
     public void service(HttpServletRequest req,HttpServletResponse res)throws ServletException,IOException{
          System.out.println("Start ..........................................................");
          URL url                              = new URL("Your Portlet URL");
          HttpURLConnection urlConn     = (HttpURLConnection)url.openConnection();
          String toPost = "Your string";
          System.out.println("URLConnection object\t" + urlConn);
          urlConn.setDoInput(true);
          urlConn.setDoOutput(true);
          urlConn.setUseCaches(false);
          urlConn.setRequestProperty ("Content-Type", "Appropriate content type");
          //urlConn.setRequestProperty("Content-Length","Appropriate content length");
          urlConn.setRequestMethod("POST");
          OutputStream out = urlConn.getOutputStream();
          out.writeBytes(toPost.getBytes());          
          out.flush();
          out.close();          
          PrintWriter outStream = new PrintWriter(res.getOutputStream(),true);
          DataInputStream in = new DataInputStream(urlConn.getInputStream());
          String inputLine = in.readLine();
          while(inputLine!=null){
               outStream.println(inputLine);
               inputLine= in.readLine();
          outStream.close();
          in.close();
          System.out.println("End ...........................................................");
As long as you do not get input stream from your URL Connection you will experience problems. Also the parameters should be passed as query string in the url. Rather pass them using output stream object obtained from URL connection. Also in your responding servlet you will be required to read the parameters using an Input Stream something like this.
DataInputStream in = new DataInputStream(request.getInputStream());
               String inputLine = in.readLine();          
               while(inputLine!=null){
                    System.out.println("Input Received by servlet\t" + inputLine);                                        
                    inputLine = in.readLine();
HTH
VJ