How to run a thread for second time ?

Question

I have a written a ThreadPool, but I found that basically a thread is not running for the second time. i.e First i call run() method and call stop(). If i call again run() method for the same thread, it is not running. What should I do, If i want to run the thread for the second time ?
class NewThread implements Runnable {
String name;
NewThread(String a) {
name=a;
public void run() {
try{
for(int i=0;i<5;i++) {
System.out.println("Thread :" + name + " #" +i);
Thread.sleep(5);
catch (Exception e) {
e.printStackTrace();
class threadRunnableTest {
public static void main (String args[]) {
Runnable runnable=new NewThread("BaSkAr");
Thread thread = new Thread(runnable);
try{
System.out.println("First Thread is starting !!!");
thread.start();
Thread.sleep(2000);
System.out.println("First Thread it to be stopped!!");
thread.stop();
System.out.println("Second Thread is starting !!!");
thread.start();
Thread.sleep(2000);
System.out.println("Second Thread it to be stopped!!");
thread.stop();
catch (Exception e) {
e.printStackTrace();

Answer 1

baskark wrote:
I have a written a ThreadPool, but I found that basically a thread is not running for the second time. i.e First i call run() method and call stop(). If i call again run() method for the same thread, it is not running. What should I do, If i want to run the thread for the second time ?
class NewThread implements Runnable {
String name;
NewThread(String a) {
name=a;
public void run() {
try{
for(int i=0;i<5;i++) {
System.out.println("Thread :" + name + " #" +i);
Thread.sleep(5);
catch (Exception e) {
e.printStackTrace();
class threadRunnableTest {
public static void main (String args[]) {
Runnable runnable=new NewThread("BaSkAr");
Thread thread = new Thread(runnable);
try{
System.out.println("First Thread is starting !!!");
thread.start();
Thread.sleep(2000);
System.out.println("First Thread it to be stopped!!");
thread.stop();
System.out.println("Second Thread is starting !!!");
thread.start();
Thread.sleep(2000);
System.out.println("Second Thread it to be stopped!!");
thread.stop();
catch (Exception e) {
e.printStackTrace();
It's usually helpful to check the documentation:
[http://java.sun.com/javase/6/docs/api/java/lang/Thread.html#start()|http://java.sun.com/javase/6/docs/api/java/lang/Thread.html#start()]
start
public void start()Causes this thread to begin execution; the Java Virtual Machine calls the run method of this thread.
The result is that two threads are running concurrently: the current thread (which returns from the call to the start method) and the other thread (which executes its run method).
It is never legal to start a thread more than once. In particular, a thread may not be restarted once it has completed execution.
So, make a new java.lang.Thread