How to show view based on condition

Hi,
I have a scenario with login screen with a submit button and two views(success and error).
Now I want to show
a)a successful view if user enters a correct login name and password(which will be validated with static values in action method of submit button)
b)a Error view if user enters wrong username and password.
I am struck at action code to write a condition to show respective views.
Some thing like (In Java)
If (login.id=='abc' && login.password='xyz')
show.view1
else
show.view2
I am not familar to ABAP coding as I just started to know.
If anyone know action code, Please help on this.
Thanks in advance
Praveen

Hi Suman,
Thanks for the code. my issue is still not solved
I have to change the code with respect to context node info.
My context looks like
Root
   ->Person
         -->Name
         -->Address (which is designted as password)
Now how to do modify your code with respect to the context. I'm sorry I m new to ABAP coding.I tried with below changed code.it gave me an error as shown in below.(type if_first=>element_name is unknown)
method ONACTIONACTION_GO .
data:
    node_input_data type ref to if_wd_context_node,
    elem_input_data type ref to if_wd_context_element,
    stru_input_data type iffirst=>element_name._
navigate from <CONTEXT> to <INPUT_DATA> via lead selection
node_input_data = wd_context->get_child_node( name = 'PERSON' ).
get element via lead selection
elem_input_data = node_input_data->get_element( ).
get all declared attributes
elem_input_data->get_static_attributes(
    importing
      static_attributes = stru_input_data ).
if stru_input_data-name = 'praveen ' and
stru_input_data-address = 'ilkal'.
Navigate to view1
wd_This->Fire_Outtov2_Plg(
else.
Navigate to View2
wd_this->fire_<plugname>_plg(
wd_This->Fire_Outtov2_Plg(
endif.
endmethod.
Error:
type if_first=>element_name is unknown (why this error..?)
Thanks
Praveen
Edited by: Praveen kumar Kadi on Sep 12, 2008 9:38 AM

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