How to stick the ends of line shapes together?

Hi, as shown in the picture I mannualy moved three lines to form the shape like this.
Anybody knows is there a way to stick these three line together? THX

pangeng wrote:
Hi, as shown in the picture I mannualy moved three lines to form the shape like this.
Anybody knows is there a way to stick these three line together? THX
Pages User Guide knows the answer !
Yvan KOENIG (VALLAURIS, France) jeudi 22 septembre 2011 15:52:29
iMac 21”5, i7, 2.8 GHz, 4 Gbytes, 1 Tbytes, mac OS X 10.6.8 and 10.7.0
My iDisk is : <http://public.me.com/koenigyvan>
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How to delete the ends of line ["\n"] in a String before parsing

hi, i'd want to parse a String with Regex/Pattern.
This String contains ends of line i want to delete before applying my parsing treatment.
I've tried to do that by replacing the character "\n" with "" :
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Edited by: jfact on Dec 29, 2007 11:05 AM
Edited by: jfact on Dec 29, 2007 11:06 AM

The second (optional) argument to Pattern is a set of flags. Take a look at the Javadoc.
The 'genomic' implication is that the EOL is an arbitrary line break for human consumption so it does look like you need to remove the EOL. I would just use replaceAll() since it can be done with one line of code (or just a couple if you pre-compile the regex) without the need for any looping.
line = line.replaceAll("\n","");Edited by: sabre150 on Dec 29, 2007 10:27 AM

How to count the number of lines dynamically,

In the below code am trying to read the lines which are selected using a check box, also am categorizing the contents depending on the follow up material.
after displaying one category contents am displaying a line
which also counts to a line in the internal table.
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DATA: LV_LINES TYPE I,
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DO LV_LINES TIMES.
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In the below code am trying to read the lines which are selected using a check box, also am categorizing the contents depending on the follow up material.
after displaying one category contents am displaying a line
which also counts to a line in the internal table.
My question is how to count the number of lines(ULINE) displayed dynamically.
FORM GET_LINES .
DATA: LV_LINES TYPE I,
        LV_TIMES TYPE I,
        LV_TABIX TYPE SY-TABIX.
DESCRIBE TABLE IT_REC LINES LV_LINES.
DO LV_LINES TIMES.
    LV_TIMES = SY-INDEX .
    READ LINE LV_TIMES FIELD VALUE IT_REC-CHECK INTO GV_CHECK.
    IF SY-SUBRC EQ 0 AND GV_CHECK IS NOT INITIAL.
      LV_TABIX = LV_TIMES.
      READ TABLE IT_REC INDEX LV_TABIX INTO GWA_UPDATE.
      IF SY-SUBRC EQ 0.
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      ENDIF.
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ENDDO.
ENDFORM.                    " GET_LINES
The display function is:
FORM DISPLAY_DATA .
ULINE.
WRITE : /1 SY-VLINE, 'check',
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           50 SY-VLINE, 'Follow up material',
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ULINE.
LOOP AT IT_MARC.
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    CLEAR IT_MARC.
ENDLOOP.
DATA: GV_TABIX TYPE SY-TABIX.
LOOP AT IT_REC.
    GV_TABIX = SY-TABIX.
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      MODIFY IT_REC INDEX GV_TABIX TRANSPORTING PARTC.
    ENDIF.
ENDLOOP.
LOOP AT IT_REC.
    WRITE : /1 SY-VLINE, IT_REC-CHECK AS CHECKBOX,
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            50 SY-VLINE, IT_REC-NFMAT,
            70 SY-VLINE, IT_REC-EISBE,
           100 SY-VLINE, IT_REC-PARTC.
    AT END OF NFMAT.
      ULINE.
    ENDAT.
ENDLOOP.
ULINE.
ENDFORM.                    " DISPLAY_DATA
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if (Number(String(app.version).split(".")[0]) == 7) ErrorExit("This script can't work with InDesign CS5 so far.", true);
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                                                            spreadWithBleedBounds[1]-8.07,
                                                            spreadWithBleedBounds[2]+unitValueAsInch,
                                                            spreadWithBleedBounds[3]+8.07
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     var innerRectangle = spread.rectangles.add(tempLayer, undefined, undefined, {geometricBounds:spreadWithBleedBounds, fillColor:doc.swatches.item("Black"), fillTint:30});
     var mask = outerRectangle.excludeOverlapPath(innerRectangle);
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     var partiallyOutOfSpreadItems = [];
     var currentItem;
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          currentItem = allPageItems[i];
          if (IsPartiallyOutOfSpread(currentItem)) partiallyOutOfSpreadItems.push(currentItem);
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     while (obj=objs.pop()) {
          try {
               if(obj.parent instanceof Spread || obj.parent instanceof MasterSpread){ obj.remove() }
          catch(err) {
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     exit();
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          var gr = groups[i];
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               var subGroups = [];
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                    gr.ungroup();
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Hi Kasyan!
I didn't try to integrate this into your script, so you might have to adjust it a little bit. The trick is to define a function that finds the intersection point of two lines --- and, obviously, you should only call it for the lines that are sure to cross the page border! (Otherwise, it would simply extend *any* line up and over the border.)
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My function comes from this page: http://local.wasp.uwa.edu.au/~pbourke/geometry/lineline2d/ and I didn't test what it does to orthogonal lines
(but of course you could add this as an exception), and this is my line-extending script, with a little wrapper to set things up.
The function tests *any* line against *any* other line, so if one crosses the page bounding box, I get the intersection with the bleed box on the side where it crosses the page bbox.
line = app.selection[0];
// pg size in "regular" [y1,x1, y2,x2] format
pagebbox = [0,0, app.activeDocument.documentPreferences.pageHeight,app.activeDocument.documentPreferences.pageWidth ];
bleedDist = 5; //
bleedbbox = [ pagebbox[0] - bleedDist, pagebbox[1] - bleedDist, pagebbox[2] + bleedDist, pagebbox[3] + bleedDist ];
pt1 = line.paths[0].pathPoints[0].anchor;
pt2 = line.paths[0].pathPoints.lastItem().anchor;
// Start point:
if (pt1[0] <= pagebbox[1] || pt1[0] >= pagebbox[3] ||
pt1[1] <= pagebbox[0] || pt1[1] >= pagebbox[2])
if (pt1[0] <= pagebbox[1])
intersectPt = IntersectionPt ( [pt1, pt2], [ [ bleedbbox[1], bleedbbox[0]], [bleedbbox[1], bleedbbox[2] ] ] );
if (pt1[0] >= pagebbox[3])
intersectPt = IntersectionPt ( [pt1, pt2], [ [ bleedbbox[3], bleedbbox[0]], [bleedbbox[3], bleedbbox[2] ] ] );
if (pt1[1] <= pagebbox[0])
intersectPt = IntersectionPt ( [pt1, pt2], [ [ bleedbbox[1], bleedbbox[0]], [bleedbbox[3], bleedbbox[0] ] ] );
if (pt1[1] >= pagebbox[2])
intersectPt = IntersectionPt ( [pt1, pt2], [ [ bleedbbox[1], bleedbbox[2]], [bleedbbox[3], bleedbbox[2] ] ] );
line.paths[0].pathPoints[0].anchor = intersectPt;
// End point:
if (pt2[0] <= pagebbox[1] || pt2[0] >= pagebbox[3] ||
pt2[1] <= pagebbox[0] || pt2[1] >= pagebbox[2])
if (pt2[0] <= pagebbox[1])
intersectPt = IntersectionPt ( [pt1, pt2], [ [ bleedbbox[1], bleedbbox[0]], [bleedbbox[1], bleedbbox[2] ] ] );
if (pt2[0] >= pagebbox[3])
intersectPt = IntersectionPt ( [pt1, pt2], [ [ bleedbbox[3], bleedbbox[0]], [bleedbbox[3], bleedbbox[2] ] ] );
if (pt2[1] <= pagebbox[0])
intersectPt = IntersectionPt ( [pt1, pt2], [ [ bleedbbox[1], bleedbbox[0]], [bleedbbox[3], bleedbbox[0] ] ] );
if (pt2[1] >= pagebbox[2])
intersectPt = IntersectionPt ( [pt1, pt2], [ [ bleedbbox[1], bleedbbox[2]], [bleedbbox[3], bleedbbox[2] ] ] );
line.paths[0].pathPoints.lastItem().anchor = intersectPt;
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var ua;
var x1 = ln1[0][0], x2 = ln1[1][0], x3 = ln2[0][0], x4 = ln2[1][0];
var y1 = ln1[0][1], y2 = ln1[1][1], y3 = ln2[0][1], y4 = ln2[1][1];
ua = ((x4 - x3)*(y1 - y3) - (y4 - y3)*(x1 - x3))/((y4 - y3)*(x2 - x1) - (x4 - x3)*(y2 - y1));
return [ x1 + ua*(x2-x1), y1 + ua*(y2-y1) ];

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I know that many people with a Powerbook G4 17" are suffering from the colored vertical line problem on their displays. This is were a pixel wide vertical line of color (yellow, green, purple, red, and/or blue) randomly appears on the laptop's display, usually between 24-36 months after purchase. This is also known on various internet forums as the "bridget riley effect" -- named after a painter whose art looks very similar to this effect. Many, if not all, of the laptops that suffer from this defect are 17" displays and have a serial number that starts with W8. Mine starts with W85; you can check yours by looking underneath the battery. It usually starts off as just one line, then two, then a few months pass and before you know it your screen looks like this:
This is my screen two years after the first line showed up, which was two and half years after getting it in December of 2005. Not so pretty. And completely useless without an external display, kind of killing the purpose of a Laptop. As a film editor I needed my screen to see the images and more importantly I needed it to be mobile. There's not always a screen to plug into.
I tried getting Apple to fix the problem, but apparently they're just ignoring the fact that almost all the laptops that came from this certain factory in Thailand (indicated by the serial number starting with W8) have failing displays. They delete threads and forums on their website, and try to censor and ignore the problem as much as they can. Unless some huge media blitz happens, or there is some kind of legitimate lawsuit, I highly doubt they ever will do anything about it, and you can't really blame them. They are a big business and addressing this problem with cost them potentially millions in repairs and tarnish their reputation as a quality manufacturer, and Apple's biggest commodity is its reputation. It ***** that Apple allowed this kind of thing to happen, but as things stand right now, it would be a poor business decision to fix it.
So, fellow vertical line sufferers, AKA the W8 club, my advice to you is stop holding out hope that they will pay for your screen to be fixed and get it done yourself! If you do it right you can get it done for between $60-$99. Here's how I did it.
First off, know that this is a hardware problem. There is no setting in system preferences you can change that will make the lines go away. There are failing physical parts in your computer to blame and they need to be replaced.
Second, in order to keep things as cheap as possible, you are going to replace the parts. It's actually pretty easy.
Thirdly, you are going to need a whole new display. I thought maybe if I replaced the display data cable (the cable that runs from the computer under the key board to the back of the screen) it might solve the problem very cheaply, since a brand new one only costs about $9 online. I took the computer apart, replaced the cable, but the display did not change at all. So the problem is the screen, not the cable. I needed a whole new screen, however, a brand spanking new one can cost between $350-$600. So I went on eBay, typed in my computer, and looked for computers that were being sold for "parts" or "repair." These are usually much cheaper because they are not working computers, but you don't need the computer to work, you just need the display to work. If you do this, make sure you read the descriptions. If there's any mention of display problems, move on and keep looking. You don't want to replace the display only to have the lines show up all over again a few months down the line. They wont always give you the serial number, but obviously try to stay away from serial numbers that start with W8. I found a used Powerbook being sold for parts for $63. It didn't have RAM, or a Hard-drive, or screws to keep the keyboard on, but the display apparently had no issues. With shipping and handling it cost me $94 total and three days to get it. The serial number started with V7. I'm sure with a little patience and vigilance, you can find something just as cheap or even cheaper.
NOTE: Some powerbooks have High-Res display screens, so make sure you know which screen yours has so you know which to look for.
Now, how to actually replace the display. I used an awesome website called ifixit.com. They give you detailed easy-to-follow instructions with photographs. I'll let them give you the nitty gritty of how to replace the display. Here is the actual How-to guide I used:
http://www.ifixit.com/Guide/Installing-PowerBook-G4-Aluminum-17-Inch-1-1-67-GHz- Display/258/1
The only tools you really need are a small phillips head screwdriver and a T6 and T8 Torx screwdriver (they are starred on the end, as oppose to crossed like the end of a phillips head). They say you need a "spudger" but I didn't. You can get these at any hardware or auto-parts store. Return them when your done if you are really on a budget, but you might want to take more part from this new computer in the future, so your call. You'll need to print out the instructions first, or use another computer to follow them since you obviously can't use your Powerbook. Find a flat, well-lit work space, preferably near a TV so you don't get bored while working, and use the how-to guide to switch the old display with the new one. It only took me a couple of hours to finish the whole thing, and I didn't have to pay a repair man hundreds. My display works perfectly now! It's so nice to be have the mobility of a laptop again (especially since the computer i got off of eBay came with a battery that can actually hold a charge).
NOTE: There are a bunch of screws and a few small parts that will need to be taken out while replacing the display, and its important they all go back in their proper spots. So I highly recommend you take a long piece of tape, loop it, and stick it flat onto the side of your work space. As you take out each screw or small part, stick them in order to the tape. This way nothing gets lost and when you work backwards to put your computer back together you'll always know which screw or small part is next in line and which one the how-to guide is referring to.
I really hope this helps people with this problem. This seems to be the only solution. And for less than $100 bucks, I think its worth it, especially since you now have back up parts for any other part of your computer that might fail in the future. My disc drive stopped working recently so I'm replacing it with the one that came with the computer I got off eBay; a $90 part. I tried to make this as easy-to-follow, practical, and comprehensive as I could -- for as cheap as I could. GOOD LUCK!!!
-R

I suspect not. There are long threads with hundreds of reports, most with PowerBooks whose serial numbers began with W8 (or W85). Still there is no Repair Extension Program for this issue.
At this point, your only recourse is to discuss the issue with Apple Consumer Relations at 1-800-767-2775, if you are in North America.

Preserve a single space at the end of line using spool command

Hi,
Can you please help me to write the result of an sql query into a file with the last column of the row ending with a single space?
For example:
COL1DATA|COL2DATA|COL3DATA<space1>
As mentioned in the example the col3 value in the file should end with a single space. And there should not be any delimiters at the end of the row.
I tried with set trimspool on/off. But, it didn't work. When I say trimspool on - it is trimming all the trailing spaces.
When I say trimspool off - it is retaining all the trailing spaces to the size of the line.
But, I do not wish to modify the file through shell commands once it is written thru spool. I mean I do not wish to append spaces to the end of a line using shell script or any other method.
I do not wish to use other methods like UTL_FILE also.
Please help me how to do it using spool command?
Thank you.
Ramana

My requirement is that all the trailing spaces should be truncated except the last one in the row.Why?
As you have discovered a single column in sqlplus, is always a fixed length regardless of the size of the data, if the length of the data varies the output is padded to the maximum or line size with spaces. The trim and trimpsool commands are there to remove all the spaces from the end of a line if there are any. There are no commands to trim all the spaces except one, or even to trim all the spaces except two, or three even.
If you want such custom processing you should post process the file in the OS using sed, awk or perl or something designed for such things.

How to stick the ends of line shapes together?

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