I'm trying to find the checksum but I keep getting a 9 digit number??

Question

I'm trying to write a method that will return the checksum of a file that is passed to it. I would like to compare this checksum to the checksum of a file stored in SVN source control. So far I have this bit of code that I'v cobbled together:
import java.io.*;
import java.util.zip.CheckedInputStream;
import java.util.zip.CRC32;
public class CreateCheckSumOfFile
    public long checkSum(String filePath)
     long checksum = 0;
        FileInputStream file = new FileInputStream(filePath);
        CheckedInputStream check = new CheckedInputStream(file, new CRC32());
        BufferedInputStream in = new BufferedInputStream(check);
        while (in.read() != -1)
            // Read file in completely
        checksum = check.getChecksum().getValue();
        return checksum;   
}I've tried a number of variations however I keep getting a 9 digit number. Why am I not receiving a 32 digit number? Since the checksum is a hexidecimal number shouldn't I be using a String? Any other pointers would be appreciated. Thanks.

Answer 1

Yes thanks you are correct. I was suppose to be calculating a md5sum. I didn't realize there was a difference. I've done some more searching and I've cobbled together some code that is working for me. I've created a method that receives a file path and then returns the md5sum of that file. The md5sums that this produced matched the ones generated by the perl md5sum.exe.
package createchecksumoffile;
import java.io.*;
import java.security.MessageDigest;
public class CreateCheckSumOfFile
    public static void main(String[] args) throws Exception
     String filePath = "Enter your file path";
     String checksum = getMD5Checksum(filePath);
     System.out.println();
     System.out.println("Check Sum of: " + filePath);
     System.out.println(checksum);
     System.out.println();     
    public static String getMD5Checksum(String filePath) throws Exception
     InputStream fileInputStream =  new FileInputStream(filePath);
     byte[] buffer = new byte[1024];
     MessageDigest complete = MessageDigest.getInstance("MD5");
     int numRead;
     do{
         numRead = fileInputStream.read(buffer);
         if (numRead > 0)
          complete.update(buffer, 0, numRead);
     }while (numRead != -1);
     fileInputStream.close();     
     String result = "";
     buffer = complete.digest();
     for (int i=0; i < buffer.length; i++)
         result += Integer.toString( ( buffer[i] & 0xff ) + 0x100, 16).substring( 1 );
     return result;
}I hope this is helpful for someone else. I am very open to criticism of this. The only question I had was about the line:
"byte[] buffer = new byte[1024]"
Does this line create some type of file size limitation?