I need to install servlet-api.jar in the libext folder.

Hi I am doing a tutorial on struts 2.0.11.
i need to install servlet-api.jar in the libext folder which I have created inside WEB-INF
Now I have downloaded servlet.api which is in the zip form.
When I extract the files. Its giving me two folders
1. javax
2. META-INF
Inside javax there is a folder called servlet. Inside servlet folder there are
a) bunch of call files
b) http folder
c) resources folder
Inside http folder there are
a) class files
b) properties files
Inside the resources folder there are
a) dtd files
b) xsd files
Inside the META-INF folder there is the manifest.mf file
I just need servlet-api.jar
I think that I have extracted the contents of servlet-api.jar by using the extract feature of winzip.
Do you think that by just changing the extension of the file from servlet-api.zip to servlet-api.jar it will do the trick or do i need to do something else.
Please guide

pksingh79 wrote:
Hi ^^,
your replies were very helpful. I did try to check the lib folder of the webserver and there was not servlet-api.jar. However I downloaded a dummy project and it did have servlet-api.jar in it, so I am ok for now.
thanks and regards,
PrashantYou should not be doing that. Always use the one from the application server which you're going to use. Otherwise you will possibly get in runtime trouble due to version differences.
The actual location and filename of the servlet API might differ per application server implementation. If it was for example Tomcat 6, it is the servlet-api.jar in the /lib directory. If it was for example Glassfish (the current release), then it is the javaee.jar in the /lib directory.

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WHERE insert it to can compile SERVLETS ?
where added(directory), some folders follow...?
C:\Program Files\Java\jdk1.6.0_15\bin
C:\Sun\AppServer\lib
C:\Program Files\Java\jdk1.6.0_15\src\javax

You can use any of the following methods:
i) SET CLASSPATH variable with absolute path of your servlet-api.jar and then compile your servlet from any folder.
ii)you can use
C:\jdk\bin>javac -cp C:\tomcat\lib\servlet-api.jar SampleServlet.javaand after comilation put the compiled java class file to classes folder of you web application.
[Obviously if you have any package, then you need to maintaing that folder structure inside classes folder]
Here I assumed your javac is available at C:\jdk\bin folder and servlet-api.jar is available at C:\tomcat\lib folder
---Sujoy

Once i set classpath to servlet-api.jar, it doesnt Instantiate DbBean.

I am using notepad editor. I am trying to instantiate a DbBean class inside the servlet's init() method.
once i set (C:\Program Files\Apache Software Foundation\Tomcat 5.0\common\lib\servlet-api.jar) this path to compile the Controller servlet.
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this is my servlet
import java.sql.*;
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import bean.DbBean;
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public void init(ServletConfig config)throws ServletException
ServletContext context = config.getServletContext();
context.setAttribute("base_url",config.getInitParameter("base_url"));
{color:#ff0000}DbBean dbbean = new DbBean();{color} {color:#0000ff}error showing in this line
{color}dbbean.setDburl(config.getInitParameter("dburl"));
dbbean.setUserName(config.getInitParameter("username"));
dbbean.setPassward(config.getInitParameter("pwd"));
/// database bean can be access from jsp page
context.setAttribute("dbbean",dbbean);
/// Load the data base driver
try{
Class.forName(config.getInitParameter("jdbcDriver"));
catch(ClassNotFoundException e)
System.out.println(e.toString());
super.init(config);
public void doGet(HttpServletRequest req, HttpServletResponse res)throws ServletException,IOException
doPost(req,res);
public void doPost(HttpServletRequest req, HttpServletResponse res)throws ServletException,IOException
String base = "/onlinetest1/";
String url = base + "login.jsp";
String action = req.getParameter("action");
if(action!=null)
if(action.equals("successlogin.jsp"));
url = base + "successlogin.jsp";
RequestDispatcher dispatcher = getServletContext().getRequestDispatcher(url);
dispatcher.forward(req,res);
public void destroy()
System.out.println("Servlet stopped");
This below class can be put inside bean folder( (ie)sub dir of controller servlet)
package bean;
import java.sql.*;
import java.util.*;
import java.io.*;
public class DbBean
String dburl="";
String dbuser="";
String dbpass="";
public void setDburl(String url)
dburl = url;
public void setUserName(String uname)
dbuser = uname;
public void setPassward(String pwd)
dbpass = pwd;
What to do to rectify this, please help me why this error coming,

hi,
Actually i did my ordinary package compilation example below, its run correctly, but after set classpath to %tomcat-home%\common\lib\servlet-api.jar(for same programs its not working) this kinds of error coming.
F:\shyam\test>javac first.java
F:\shyam\test>java first
main class
DB Set Correctly
F:\shyam\test>set classpath=C:\Program Files\Apache Software Foundation\Tomcat 5.0\common\lib\servlet-api.jar
F:\shyam\test>javac first.java
first.java:1: package bean does not exist
import bean.DbBean;
^
first.java:10: cannot find symbol
symbol : class DbBean
location: class first
DbBean dbbean = new DbBean();
^
first.java:10: cannot find symbol
symbol : class DbBean
location: class first
DbBean dbbean = new DbBean();
^
3 errors
F:\shyam\test>
In compilation it wont take DbBean class, please help me.
thanks in advance,
S.Shyam

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Hi guys..!!
I would like to know if someone could help on this:
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Revision: 1985
Author: [email protected]
Date: 2008-06-06 12:20:06 -0700 (Fri, 06 Jun 2008)
Log Message:
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I need to install servlet-api.jar in the libext folder.

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