Idoc to String field

Hello everybody,
I want to map the content of an Idoc to one String field, but I don't know how to do this. Can anybody help me?
Best regards
Martin

Hello everybody,
thanks for your advices, but I have a general problem. My Mapping is IDOC to StringField. But when I start testing the Message Mapping by loading an IDOC as XML-File, I have no values when I display the Queue. I did the mapping as mentioned in the Blog.
What is my error?
Thanks and best regards,
Martin

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Add a carriage return in a Unbound String Field

Post Author: Razzle00
CA Forum: Formula
Hi,
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'Heading One:' + CARRIAGE RETURN + trim({tablename.fld_1}) + CARRIAGE RETURN + 'Heading Two:' + CARRIAGE RETURN + trim({tablename.fld_2})
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Post Author: SKodidine
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To add a carriage return, add CHRW(13)
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Dan,
I'm actually surprised you had success with that on AD as I never did. I recommend you get a little lower level and use DBMS_LDAP. Here's a little sample code to get you started:
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      THEN
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EXCEPTION
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END;Regards,
Dan
http://danielmcghan.us
http://sourceforge.net/projects/tapigen

Purpose of using string field

how to use string field and its purpose...

STRING: Character string with variable length This data type can be used only in types (data elements, structures, table types) and domains. In the dictionary a length can be specified for this type (at least 256 characters). It can be used in database tables only with restrictions. For a description of them, refer to the documentation of the ABAP statement 'STRING'. In ABAP, this type is implemented as a reference to a storage area of variable size. The system proposes 132 characters as default for the output length. You cannot attach search helps to components of this type.
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String Field rendering as Number Field in CR Basic for VS2008

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Try placing the field inside a formula field or inside a text field. That should cause the field to be shown no matter what type of data it is. If the data is still not showing, then perhaps it is not being returned properly.
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Thanks
Shawn

Updated to CR 2008 - now have new problem with truncated String fields.

Hi there
I'm hoping someone has a simple answer for this one... notice there's a lot of it on forums but I haven't found an answer.
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What is the database Oracle, SQL server etc.
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Hi
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Thanks

Hi,
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Segment Filtering:
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Data Filtering:
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Please check this link for detail information.
http://help.sap.com//saphelp_470/helpdata/EN/0b/2a611c507d11d18ee90000e8366fc2/frameset.htm
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Regards,
Ferry Lianto
Please reward points if helpful.

Impossible to get a String field with GetFieldID !!!!!!

Hi, I write here my classes and explain my problem :
------------------------- Class Lexicon.java ---------------------------
package SlpTkJava.JavaCode;
public class Lexicon {
public native void next(SearchReturn search);
static {
System.loadLibrary("slptkjava");
--------------------------- Class SearchReturn.java --------------------
package SlpTkJava.JavaCode;
public class SearchReturn {
public LexItem access;
-------------------------- Class LexItem.java --------------------------
package SlpTkJava.JavaCode;
public class LexItem {
public int lemma;
public String graphy;
--------------------------- File Lexicon.c -----------------------------
* Class: SlpTkJava_JavaCode_Lexicon
* Method: next
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at TestLexicon.main(TestLexicon.java:58)
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I can precise that I'm on Solaris.
Please help me it's urgent !
Thank you.
Zigune

I think your problem is:
graphyFID = (*env)->GetFieldID(env, lexItemCls, "graphy", "LJava/lang/String;");
should be
graphyFID = (*env)->GetFieldID(env, lexItemCls, "graphy", "Ljava/lang/String;");
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How to set a string field with people picker control group

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I have a problem with a form list, when I need to set a string field with de content of people picker control that have more than one "user".
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tnks.

Hi ,
Please try out in following way :
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It works for me .

Removing last 2 characters from string field

I am trying to remove the last 2 characters of a string field.
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formula,
left (field, length_formula) is the solution
the length_formula is the number of chars form left
f.i
left(field, length (field)-2)
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Hi Create a formula:
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Vinay

Random Characters insterted into Crystal Reports string fields

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Sorry, i think I've been a bit imprecise so far
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They appear when previewing, when actually printing, everything after the characters is cut off
Are you printing directly from CR or from Enterprise/Infoview or another custom application?
From CR (both to PDF and paper)
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Not sure, although this may be moot since it also shows up in the preview?
Have you printed on another printer and does it too exhibit the same behavior?
Same as above?
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Hi
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Row 1:     1                    'abc'
Row 2:      2                    'xyz'
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Hi,
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Need help with string field formula

Post Author: dshallah
CA Forum: Formula
What I am trying to accomplish:
The report has item numbers and each item number has the
potential to be associated with up to three u2018binsu2019. So the fields are u2018item
numberu2019, u2018bin1, u2018bin2u2019 and u2018bin3u2019.
I tried to write a u2018if thenu2019 statement that would only show
records that had a value of less than 1 in each u2018binu2019 field. When I try to
write the statement I get a message that says u2018A string is required hereu2019 and
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procedure to correct this. Thus help is needed and appreciated.
Here is what I wrote:
if {IC_LOC_HIST.BIN_NAME_1} < 1 then
{IC_LOC_HIST.BIN_NAME_1}
What is correct way to write a statement that will show me
the zero values in each column of bin fields?
Thanks!

Post Author: bettername
CA Forum: Formula
You must have a non-numeric value in there somewhere - up in the top left of the formula editor window, it'll show you the variables you've passed to the formula, which should help track down what's going on.
You could try and check that the value is a number first by using something like:
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