Infopackage type not equal datasource type
Hi!
I have message "Infopackage type T <> datasource type D".
I load master data by transaction datasource. I don't see any problem.
this mean that Infopackage for texts data, datasource for transaction data.
But why it happens?
Hi,
"I load data to Characteristic text and attribute using one datasorce 3.x for transaction data."... I am not sure what it means...
we need to have to different datasources for loading the Texts and Attributes... in the 3.x method, the Infosource appears to be the same for both (in fact, the infosource structure is automatically adjusted depending the datasource).. but we need to have two different datasources.. please create a new generic data for the other, if one of the datasources is not available..
if you can give more details, like the name of the data source, name of the Infoobject you are loading etc.. then I can provide more accurate answers.
rgds
Naga
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Integer i = new Integer (42);
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>
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Edited by: Sebastian Stöckle on Nov 22, 2010 11:49 AM -
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Dear all
Our production server and development server not equal our target is only custimizing label both are equal which profile choose
please guide
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User BASIS
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Table/Object Component Error
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venkat -
If I have two identical symbols in Javascript they are not
equal as they would be in Lingo
ie.
//Javascript
var a = symbol( 'hello' );
var b = symbol( 'hello' );
put ( a == b );
// false
put ( a.toString() == b.toString() );
// true
-- Lingo
a = #hello
b = #hello
put a = b
-- 1
So my question is is this a bug or just the way Javascript
works?i suspect the reason for inequality is that the two symbols
are serate objects, each with it's own memory address. try this:
trace(typeof(a));
you'll get:
// object
toString type casts the symbol to it's string value.
this from the srcipting reference pdf:
Symbols
A symbol is a string or other value in Lingo that begins with
the pound (#) sign.
Symbols are user-defined constants. Comparisons using symbols
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quickly, providing more efficient code.
For example, the first statement below runs more quickly than
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function (Lingo) or the toString()
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In JavaScript syntax, you cannot compare symbols of the same
name to determine whether they
refer to the same symbol. To compare symbols of the same
name, you must first convert them to
strings by using the toString() method, and then perform the
comparison.
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