Inserting Into MYSQL Table Via Air/PHP = Not Allowed?

I'm having trouble inserting data into my mysql database tables through my air app. All the code is pretty much exactly the same as in some examples I've seen but it simply won't do it. Is this because of some sort of security restriction because the air app is on my machine and the server with my mysql database on is elsehwhere? Or is it possible to insert data via an air app?
Here is the example I've been following:-
http://livedocs.adobe.com/flex/3/html/help.html?content=data_access_2.html

jimmyoneshot wrote:
Thanks for the answers boys. I've decided I'm going to change it into a flex app instead as then there won't be any problems. It simply means I'll have to add a logon system to it.
While were on the subject do you guys happen to know of any examples anywhere of how someone can REMOVE data from an sql table via flex/php?
What I'm looking for is basically when a user uses my app and enters info into some text inputs, if that specfic info exists within a table then that data will be removed from the table. The way this works is that they will choose an item within a tilelist which is populated by the data from this mysql table and this will insert the data of the selected item into the text inputs and then they click a remove button to remove that item. Can't find anything similar anywhere though.
You will have to use a common identifier, eg:
give each row in your database an ID.
then pass that ID value on the button press to a PHP script, which does something like:
$deleteID = $_POST["delID"];
mysql_query("DELETE FROM exampleTable WHERE ID='$deleteID
maybe check that a row with that ID exists first for verification, then pass back a value indicating if removal was a success or not.
You can delete on other values, but remember they have to be unique for the database, else you'll run the risk of deleting multiple values.
Or you could delete on a compound key, depends on the data you're storing in the grid.

Similar Messages

How to insert into 2 tables from the same page (with one button link)

Hi,
I have the following 2 tables....
Employees
emp_id number not null
name varchar2(30) not null
email varchar2(50)
hire_date date
dept_id number
PK = emp_id
FK = dept_id
Notes
note_id number not null
added_on date not null
added_by varchar2(30) not null
note varchar2(4000)
emp_id number not null
PK = note_id
FK = emp_id
I want to do an insert into both tables via the application and also via the same page (with one button link). I have made a form to add an employee with an add button - adding an employee is no problem.
Now, on the same page, I have added a html text area in another region, where the user can write a note. But how do I get the note to insert into the Notes table when the user clicks the add button?
In other words, when the user clicks 'add', the employee information should be inserted into the Employees table and the note should be inserted into the Notes table.
How do I go about doing this?
Thanks.

Hi,
These are my After Submit Processes...
After Submit
30     Process Row of NOTES     Automatic Row Processing (DML)     Unconditional
30     Process Row of EMPLOYEES     Automatic Row Processing (DML)     Unconditional
40     reset page     Clear Cache for all Items on Pages (PageID,PageID,PageID)     Unconditional
40     reset page     Clear Cache for all Items on Pages (PageID,PageID,PageID)     Unconditional
40     reset page     Clear Cache for all Items on Pages (PageID,PageID,PageID)     Unconditional
40     reset page     Clear Cache for all Items on Pages (PageID,PageID,PageID)     Unconditional
50     Insert into Tables     PL/SQL anonymous block     Conditional
My pl/sql code is the same as posted earlier.
Upon inserting data into the forms and clicking the add button, I get this error...
ORA-06550: line 1, column 102: PL/SQL: ORA-00904: "NOTES": invalid identifier ORA-06550: line 1, column 7: PL/SQL: SQL Statement ignored
     Error      Unable to process row of table EMPLOYEES.
Is there something wrong with the pl/sql code or is it something else?

Insert into multiple table view

I have a view with multiple table query and and INSTEAD OF trigger on the view that inserts into multiple tables. When I attempt to do a commit out of a ADF Creation Form, I get the following error: ORA-01779: cannot modify a column which maps to a non key-preserved table ORA-06512: at line 1.
Has anyone had success inserting into multiple tables via a view that has more than one table?
Thanks,
Lisa

Lisa,
Sounds like your instead-of trigger may not be being called and you are trying to insert directly into the view.
I did write a [url http://stegemanoracle.wordpress.com/2006/03/15/using-updatable-views-with-adf/]blog entry about using a view with instead-of triggers last year.
John

Oracle 10g performance degrades while concurrent inserts into a table

Hello Team,
I am trying to insert into single table via multiple threads, Some of these threads perform reasonably well but some will take really longer time, As the time goes on performance drastically degrades (even down by 500 to 600 times). With AWR report i see that there quite huge number of buffer gets there. I am not sure how can i reduce those. If i ran on a single thread this operation is consistent.
I tried quite a few options like
1. Increasing SGA Memory
2. Moving redo logs to another disk drive.
3. Trying it on a empty table
4. Trying it on a table which has huge data (4 Million rows)
5. I have even tried partitioning the table with HASH algoritm
Note: Each thread i am pupming equal amount of data (let say 25K rows).
Can any body suggest me a clue what could be the culprit here.
Thanks in Advance
Satish Kumar Ballepu

user11150696 wrote:
Can you please guide me how do i do that, I am not aware of how to generate explain plan for that query.Since you have the trace file already (and I don't mean the tkprof output), you could do the following:
Read the trace file to find the statement you're interested id - the line above it will be a +"PARSING"+ line, and will include a reference to the statement hash_value look like +'hv=3838377475845'+.
Use the hash_value to query v$sql to get the sql_id and child_number;
Use the sql_id and child number in a call to dbms_xplan.display_cursor:
PARSING IN CURSOR #7 len=68 dep=0 uid=55 oct=3 lid=55 tim=448839952404 *hv=3413100263* ad='2f6ede48'
select ... etc. (the statement I want the plan for)
SQL> select sql_id , child_number from v$sql where hash_value = *3413100263*;
SQL_ID        CHILD_NUMBER
053tyaz5qzjr7            0
SQL> select * from table(dbms_xplan.display_cursor(*'053tyaz5qzjr7'*,*0*));
PLAN_TABLE_OUTPUT
SQL_ID 053tyaz5qzjr7, child number 0
select /*+ use_concat */ small_vc from t1 where n1 = 1 or n2 = 2
Plan hash value: 82564388
| Id | Operation                    | Name | Rows | Bytes | Cost |
|   0 | SELECT STATEMENT             |       |       |       |     4 |
|   1 | CONCATENATION               |       |       |       |       |
|   2 |   TABLE ACCESS BY INDEX ROWID| T1    |    10 |   190 |     2 |
|* 3 |    INDEX RANGE SCAN          | T1_N2 |    10 |       |     1 |
|* 4 |   TABLE ACCESS BY INDEX ROWID| T1    |    10 |   190 |     2 |
|* 5 |    INDEX RANGE SCAN          | T1_N1 |    10 |       |     1 |
Predicate Information (identified by operation id):
   3 - access("N2"=2)
   4 - filter(LNNVL("N2"=2))
   5 - access("N1"=1)
Note
   - cpu costing is off (consider enabling it)Regards
Jonathan Lewis
http://jonathanlewis.wordpress.com
http://www.jlcomp.demon.co.uk
"For every expert there is an equal and opposite expert."
Arthur C. Clarke
To post code, statspack/AWR report, execution plans or trace files, start and end the section with the tag {noformat}{noformat} (lowercase, curly brackets, no spaces) so that the text appears in fixed format.

Can select, but cannot insert into oracle tables using php.

I am having trouble inserting data into a tables in oracle using PHP. I can insert into the tables using baninst1, but nothing else. I can't even insert using the tables' owner. Every time I try I get the ORA-00492 error of table or view does not exist. However, I can run a select statement just fine. So far, baninst1 is the only user that can actually do inserts. I've triple checked all the table grants and everything is fine. Also, I can copy/paste the exact insert statement into SQL*Plus and it works with the correct user. It doesn't have to be baninst1. I've tried everything I can think of. I've tried putting the table name in quotes, adding the schema name to the table, checking public synonyms, but everything appears to be ok. I would greatly appreciate any suggestions others may have.
I'm using PHP 5.2.3 with an oracle 9i DB.

Here is the code that doesn't work. It works only with baninst1, no other username will work and all I do is change the my_username/my_password to something different. This is one example function where I try to do an insert, but it doesn't work on any of the tables I try.
Thanks for looking.
class Oracle {
     private $oracleUser = "my_username";
     private $oraclePassword = "my_password";
     private $oracleDB = "MY_DB";
     private $c = null;
     function Connect() {
          if ( !($this->c = ocilogon( $this->oracleUser, $this->oraclePassword, $this->oracleDB ) ) )
               return false;
          return true;
     function AddNewTest($testName, $course, $section, $term, $maxAttempts, $length, $startDate, $startTime, $endDate, $endTime)
          $result = "";
          if( $this->c == null )
               $this->Connect();
          $splitIndex = strpos($course, " ");
          $subjectCode = substr($course, 0, $splitIndex);
          $courseNumber = substr($course, $splitIndex + 1);
          $insertStatment = "insert into szbtestinfo(szbtestinfo_test_name,
                                                            szbtestinfo_course_numb,
                                                       szbtestinfo_section,
                                                            szbtestinfo_max_attempts,
                                                            szbtestinfo_length_minutes,
                                                            szbtestinfo_start,
                                                            szbtestinfo_end,
                                                            szbtestinfo_id,
                                                            szbtestinfo_subj_code,
                                                            szbtestinfo_eff_term)
                                                            values( '" . $testName .
               "', '" . $courseNumber .
               "', '" . $section .
               "', " . $maxAttempts .
               ", " . $length .
               ", to_date('" . $startDate . " " . $startTime . "', 'MM/DD/YYYY HH24:MI')" .
               ", to_date('" . $endDate . " " . $endTime . "', 'MM/DD/YYYY HH24:MI')" .
               ", szsnexttest.nextval" .
               ", '" . $subjectCode .
               "', '" . $term . "')";
          //return $insertStatment;
          $s = OCIParse($this->c, $insertStatment);
          try
               $result = OCIExecute($s);
          catch(exception $e)
          return $result;
     }

Record not inserting into the table through Forms 10g

Hi all,
I have created a form in 10g(10.1.2.0.2) based on just one table that has 4 columns(col1, col2, col3, col4).
Here col1, col2 and col3 are VARCHAR2 and col4 is date and all the columns are not null columns(There are no primary and foriegn key constrains, which means duplicates are allowed).
My form contains 2 blocks where block 1 has one text item (col1) and 3 buttons (Delete, Save, Exit).
And block2 is a database block and has col2,col3,col4 which are in tabluar layout frame displaying 10 records.
When the form is opened the cursor has to be in block1.col1 for querrying. Here i enter a value in col1, and then when I click on col2 in the block2, then I put execute_query in new_block_instance of block2, which displays the records.
The block2 properties are not updatable, insertable and query is allowed.
Everything is working good until here. But here in the block2 when I want to insert another record into the table, by navigating all the way down to the last empty record and entering the new values for col2, col3 and col4 And then Ctrl+S will display the message "*FRM-40400: Transaction complete: 1 record applied and saved.*" But actually the record is not inserted into the table.
I also disabled the col4 by setting the Enabled property to No, since while inserting new record the date have to be populated into it and it shouldnt be changed by the user. And im populating the sysdate into the new record by setting Intial Value property to *$$DATE$$*.
And another requirement which I could not work arround here is that, the col3 also should be populated with the username of the user while inserting.
please help me...

Hi Sarah,
I do not want to update the existing record. So I kept Udate Allowed to No in property palette for the items in block2.
Do I have to do this property at block level also?
I'm inserting a new record here.
Edited by: Charan on Sep 19, 2011 8:48 AM

Record not inserting into sap table with connector framework ?

here is the code, but record not being inserting into the table ... but same piece of code working fine while updating ... the record ...
try {
interaction = connection.createInteractionEx();
IInteractionSpec interactionSpec = interaction.getInteractionSpec();
String functionName = "Z_XYZ";
interactionSpec.setPropertyValue("Name", functionName);
String writingTable = "MYTABLE";
RecordFactory rf = interaction.getRecordFactory();
MappedRecord importParams = rf.createMappedRecord("input");
importParams.put("ATTR1", "VALUE1");
importParams.put("ATTR2", "VALUE2");
IFunction function = connection.getFunctionsMetaData().getFunction(functionName);
IStructureFactory sf = interaction.retrieveStructureFactory();
IRecordSet table = (IRecordSet) sf.getStructure(function.getParameter(writingTable).getStructure());
table.insertRow();
table.setString("ATNAME", "VALUE");
table.setString("ATWRT", "VALUE");
importParams.put(writingTable, table);
MappedRecord output = (MappedRecord) interaction.execute(interactionSpec, importParams);
} catch (Exception e) {
any idea?
than ks
MMK

Hi Mohan,
Does a creation through SE37 with the same input work?
Yoav.

Record is not inserting into the Table thourgh forms 10g

Hi All,
I have the form built in 10g(10.1.2.0.2).
Basically the form has 2 blocks.
Block 1 with only one item, where we enter some value and hit enter(this will navigate to block2 and execute the query).
Block 2(tabular) will fetch the records. Now this block2 have 3 columns(caseid, userid, date).
Now when I insert a new record, I just need to enter the caseid only. And userid and date have to be automatically populated.
I can populate the USERID and DATE fields.
And when I enter some value in caseid item of block 2, and then do Control+S(to insert the record and Save the transaction),
i get the message saying FRM-40400: Transaction complete: 1 records applied and saved.
But when I query again for the same, I dont se the record inserted into the table.
Why is this happening?
Help please...

@ Inol
There is no promary or foriegn key relation ship. The form is fetching records from just one table. As I said block1 has col1. and Block2 has col2,3,4.
@Andreas
Yes I did select * from table, select count(*) from table in SQL*Plus. Nothing is inserted.
And one thing I have to tall here is, I have a ON-INSERT trigger in block2.
The code in ON-INSERT trigger is
-- :BLOCK2.DATE := TO_DATE(:DATE,'DD-MON-YYYY') ;
/* commented since I was populating date by assigning $$DATETIME$$ to the Initial value property of the data item. */
:BLOCK2.SOURCE_CASE := :BLOCK1.SOURCE_CASEID;Forgot to tell you,
Since I was inserting the record from block2(3 columns), to the table which has 4 columns, there is another item in block 2 which has the visible property No.
So the block 2 has 4 columns. And the hidden column will hold the value that is in the item of block1. This is what i'm pushing in the ON-INSERT trigger.
Edited by: Charan on Sep 20, 2011 1:51 PM

Problem while inserting into a table which has ManyToOne relation

Problem while inserting into a table *(Files)* which has ManyToOne relation with another table *(Folder)* involving a attribute both in primary key as well as in foreign key in JPA 1.0.
Relevent Code
Entities:
public class Files implements Serializable {
@EmbeddedId
protected FilesPK filesPK;
private String filename;
@JoinColumns({
@JoinColumn(name = "folder_id", referencedColumnName = "folder_id"),
@JoinColumn(name = "uid", referencedColumnName = "uid", insertable = false, updatable = false)})
@ManyToOne(optional = false)
private Folders folders;
public class FilesPK implements Serializable {
private int fileId;
private int uid;
public class Folders implements Serializable {
@EmbeddedId
protected FoldersPK foldersPK;
private String folderName;
@OneToMany(cascade = CascadeType.ALL, mappedBy = "folders")
private Collection<Files> filesCollection;
@JoinColumn(name = "uid", referencedColumnName = "uid", insertable = false, updatable = false)
@ManyToOne(optional = false)
private Users users;
public class FoldersPK implements Serializable {
private int folderId;
private int uid;
public class Users implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Integer uid;
private String username;
@OneToMany(cascade = CascadeType.ALL, mappedBy = "users")
private Collection<Folders> foldersCollection;
I left out @Basic & @Column annotations for sake of less code.
EJB method
public void insertFile(String fileName, int folderID, int uid){
FilesPK pk = new FilesPK();
pk.setUid(uid);
Files file = new Files();
file.setFilename(fileName);
file.setFilesPK(pk);
FoldersPK folderPk = new FoldersPK(folderID, uid);
// My understanding that it should automatically handle folderId in files table,
// but it is not…
file.setFolders(em.find(Folders.class, folderPk));
em.persist(file);
It is giving error:
Internal Exception: java.sql.SQLException: Field 'folderid' doesn't have a default value_
Error Code: 1364
Call: INSERT INTO files (filename, uid, fileid) VALUES (?, ?, ?)_
_ bind => [hello.txt, 1, 0]_
It is not even considering folderId while inserting into db.
However it works fine when I add folderId variable in Files entity and changed insertFile like this:
public void insertFile(String fileName, int folderID, int uid){
FilesPK pk = new FilesPK();
pk.setUid(uid);
Files file = new Files();
file.setFilename(fileName);
file.setFilesPK(pk);
file.setFolderId(folderId) // added line
FoldersPK folderPk = new FoldersPK(folderID, uid);
file.setFolders(em.find(Folders.class, folderPk));
em.persist(file);
My question is that is this behavior expected or it is a bug.
Is it required to add "column_name" variable separately even when an entity has reference to ManyToOne mapping foreign Entity ?
I used Mysql 5.1 for database, then generate entities using toplink, JPA 1.0, glassfish v2.1.
I've also tested this using eclipselink and got same error.
Please provide some pointers.
Thanks

Hello,
What version of EclipseLink did you try? This looks like bug https://bugs.eclipse.org/bugs/show_bug.cgi?id=280436 that was fixed in EclipseLink 2.0, so please try a later version.
You can also try working around the problem by making both fields writable through the reference mapping.
Best Regards,
Chris

Insert into two tables, how to insert multiple slave records

Hi, I have a problem with insert into two tables wizard.
The wizard works fine and I can add my records, but I need to enter multiple slave table records.
My database:
table: paper
`id_paper` INTEGER(11) NOT NULL AUTO_INCREMENT,
`make` VARCHAR(20) COLLATE utf8_general_ci NOT NULL DEFAULT '',
`model` VARCHAR(20) COLLATE utf8_general_ci NOT NULL DEFAULT '',
`gsm` INTEGER(11) NOT NULL,
PRIMARY KEY (`id_paper`)
table: paper_data
`id_paper_data` INTEGER(11) NOT NULL AUTO_INCREMENT,
`id_paper` INTEGER(11) NOT NULL,
`value` DOUBLE(15,3) NOT NULL,
`nanometer` INTEGER(11) NOT NULL,
PRIMARY KEY (`id_paper_data`)
I need to add multiple fields "value" and "nanometer"
Current form looks like this:
Make:
Model:
Gsm:
Value:
nanometer:
I need it to look like this:
Make:
Model:
Gsm:
Value:
nanometer:
Value:
nanometer:
Value:
nanometer:
Value:
nanometer:
and so on.
The field "id_paper" in table paper_data needs to get same id for entire transaction. Also how do I set default values for each field "nanometer" on my form the must be different (370,380,390 etc)?
Thanks.

you can find an answer here: http://209.85.129.132/search?q=cache:PzQj57dsWmQJ:www.experts-exchange.com/Web_Development /Software/Macromedia_Dreamweaver/Q_23713792.html+Insert+Into+Two+Tables+Wizard&cd=3&hl=lt& ct=clnk&gl=lt
This is a copy of the post:
Hi experts,
Im using ADDT to design a page that needs to insert one record into a master ALBUMS table, along with three records into a GENRES table, all linked by the primary, auto-incremented ALBUMS. ALBUM_ID.
Ive tried many different ways of combining the Insert into Multiple Tables wizard and the insert record wizard with Link Transactions, all with no luck. Either only the album info gets inserted, or a ALBUM_ID cannot be null error from MySQL. Here is the structure of the tables
ALBUMS
ALBUM_ID, INT(11), Primary, Auto_Increment
alb_name, varchar
alb_release, YEAR
USER_ID, int
alb_image, varchar
GENRES
ALBUM_ID, int, NOT NULL
GENRE_ID, int, NOT NULL
ID, int, primary, auto-increment
Many thanks in advance...
==========================================================================================
//remove this line if you want to edit the code by hand
function Trigger_LinkTransactions(&$tNG) {
global $ins_genres;
$linkObj = new tNG_LinkedTrans($tNG, $ins_genres);
$linkObj->setLink("ALBUM_ID");
return $linkObj->Execute();
function Trigger_LinkTransactions2(&$tNG) {
global $ins_genres2;
$linkObj = new tNG_LinkedTrans($tNG, $ins_genres2);
$linkObj->setLink("ALBUM_ID");
return $linkObj->Execute();
function Trigger_LinkTransactions3(&$tNG) {
global $ins_genres3;
$linkObj = new tNG_LinkedTrans($tNG, $ins_genres3);
$linkObj->setLink("ALBUM_ID");
return $linkObj->Execute();
//end Trigger_LinkTransactions trigger
//-----------------------Different Section---------------------//
// Make an insert transaction instance
//Add Record Genre 1
$ins_genres = new tNG_insert($conn_MySQL);
$tNGs->addTransaction($ins_genres);
$ins_genres->registerTrigger("STARTER", "Trigger_Default_Starter", 1, "VALUE", null);
$ins_genres->registerTrigger("BEFORE", "Trigger_Default_FormValidation", 10, $detailValidation);
$ins_genres->setTable("genres");
$ins_genres->addColumn("GENRE_ID", "NUMERIC_TYPE", "POST", "GENRE_ID");
$ins_genres->addColumn("ALBUM_ID", "NUMERIC_TYPE", "VALUE", "");
$ins_genres->setPrimaryKey("ID", "NUMERIC_TYPE");
// Add Record Genre 2
$ins_genres2 = new tNG_insert($conn_MySQL);
$tNGs->addTransaction($ins_genres2);
$ins_genres2->registerTrigger("STARTER", "Trigger_Default_Starter", 1, "VALUE", null);
$ins_genres2->setTable("genres");
$ins_genres2->addColumn("GENRE_ID", "NUMERIC_TYPE", "POST", "GENRE_ID2");
$ins_genres2->addColumn("ALBUM_ID", "NUMERIC_TYPE", "VALUE", "");
$ins_genres2->setPrimaryKey("ID", "NUMERIC_TYPE");
// Add Record Genre 3
$ins_genres3 = new tNG_insert($conn_MySQL);
$tNGs->addTransaction($ins_genres3);
$ins_genres3->registerTrigger("STARTER", "Trigger_Default_Starter", 1, "VALUE", null);
$ins_genres3->setTable("genres");
$ins_genres3->addColumn("GENRE_ID", "NUMERIC_TYPE", "POST", "GENRE_ID3");
$ins_genres3->addColumn("ALBUM_ID", "NUMERIC_TYPE", "VALUE", "");
$ins_genres3->setPrimaryKey("ID", "NUMERIC_TYPE");
=========================================================================================
Hi Aaron,
Nice job!!
$ins_albums->registerTrigger("AFTER", "Trigger_LinkTransactions2", 98);
$ins_albums->registerTrigger("AFTER", "Trigger_LinkTransactions3", 98);
These lines, right? :-( Sorry I forgot to mention that
Thanks a lot for the grading!

How can I insert into a table other than the default table in a form

Hi,
I want to insert into a table with some fields value of a form of another table. I have written insert code On successful submission of that form, but after submit it gives the following error
An unexpected error occurred: ORA-06502: PL/SQL: numeric or value error (WWV-16016)
My code is like this
declare
l_trn_id number;
l_provider_role varchar2(3);
l_provider_id varchar2(10);
begin
l_trn_id := p_session.get_value_as_number(p_block_name=>'DEFAULT',p_attribute_name=>'A_TRANSACTION_ID');
l_provider_id := p_session.get_value_as_varchar2(p_block_name=>'DEFAULT',p_attribute_name=>'A_PROVIDER1');
l_PROVIDER_ROLE := p_session.get_value_as_varchar2(p_block_name=>'DEFAULT',p_attribute_name=>'A_PROVIDER_ROLE1');
if (l_provider_role is not null) and (l_provider_id is not null) then
insert into service_provider_trans_records(service_provider_id,transaction_id,role_type_id)
values(l_provider_id, l_trn_id, l_provider_role);
commit;
end if;
end;
Where 'PROVIDER1' and 'PROVIDER_ROLE1' are not table fields.
How can do that or why this error comes ? Any idea?
Thanks
Sumita

Hi,
When do you get this error? Is it while running or while creating the form.
Here is a sample code which inserts a non-database column dummy into a table called dummy. This is done in successful procedure.
declare
l_dummy varchar2(1000);
begin
l_dummy := p_session.get_value_as_varchar2(p_block_name=>'DEFAULT',
p_attribute_name=>'A_DUMMY');
insert into sjayaram903_1g.dummy values(l_dummy);commit;
end;
Please check in your case if the size of the local variable is enough to hold the values being returned.
Thanks,
Sharmila

Inserting into a table which is created "on the fly" from a trigger

Hello all,
I am trying to insert into a table from a trigger in Oracle form. The table name however, is inputted by the user in am item form.
here is what the insert looks like:
insert into :table_name
values (:value1, :value2);
the problem is that forms does not recognize ::table_name. If I replace :table_name with an actual database table, it works fine. However, I need to insert to a table_name based from oracle form item.
By the way, the table|_name is built on the fly using a procedure before I try to insert into it.
Any suggestion on how can I do that? My code in the trigger is:
declare
dm_drop_tbl(:table_name,'table) // a call to an external procedure to drop the table
dm_create_tbl(:table_name,'att1','att2');
insert into :table_name
values (:value1, :value2);
this give me an error:
encounter "" when the symbol expecting one.....

Hi ,
You should use the FORMS_DDL built_in procedure. Read the on-line documentation of forms ...
Simon

Diffrence between backend insert and front end insert into a table.

I am developing a conversion program for tax exemption. For this program only ZX_EXEMPTIONS table is used to populate the data and we got confirmation from Oracle also regarding this.For inserting the data into this table we are taking the max of tax_exemption_id which is pk for this table and adding one to it and inserting into the table. But problem here is after inserting from back end we are not able to insert from front end.
It seems backend data is holding the tax_exemption_id which is suppose to reserve by front end data.Please explain the different behavior of populating of tax_exemption_id from front end and back end.

Hi,
i think the problem is that you are using max-value + 1 for tax_exemption_id. But as ZX_EXEMPTIONS is using sequence ZX_EXEMPTIONS_S
for primary key generation, you encounter situation that you are increasing PK Id for this table without increasing sequence value.
When trying to insert rows from front end - which probably uses sequence value - it tries to use a sequence value already used by your backend
process (which generated it by Maxvalue + 1) and would then encounter a primary key violation.
I think you should use sequence mentioned above to generate your PK Ids in backend process as well. And before doing so, check current value
of ZX_EXEMPTIONS_S, as you might need to rebuild the sequence in order to select nextval sucessfully for both frontend and backend.
Regards

How to insert into a table with a nested table which refer to another table

Hello everybody,
As the title of this thread might not be very understandable, I'm going to explain it :
In a context of a library, I have an object table about Book, and an object table about Subscriber.
In the table Subscriber, I have a nested table modeling the Loan made by the subscriber.
And finally, this nested table refers to the Book table.
Here the code concerning the creation of theses tables :
Book :
create or replace type TBook as object
number int,
title varchar2(50)
Loan :
create or replace type TLoan as object
book ref TBook,
loaning_date date
create or replace type NTLoan as table of TLoan;
Subscriber :
create or replace type TSubscriber as object
sub_id int,
name varchar2(25)
loans NTLoan
Now, my problem is how to insert into a table of TSubscriber... I tried this query, without any success...
insert into OSubscriber values
*(1, 'LEVEQUE', NTLoan(*
select TLoan(ref(b), '10/03/85') from OBook b where b.number = 1)
Of course, there is an occurrence of book in the table OBook with the number attribute 1.
Oracle returned me this error :
SQL error : ORA-00936: missing expression
00936. 00000 - "missing expression"
Thank you for your help

1) NUMBER is a reserved word - you can't use it as identifier:
SQL> create or replace type TBook as object
2 (
3 number int,
4 title varchar2(50)
5 );
6 /
Warning: Type created with compilation errors.
SQL> show err
Errors for TYPE TBOOK:
LINE/COL ERROR
0/0      PL/SQL: Compilation unit analysis terminated
3/1      PLS-00330: invalid use of type name or subtype name2) Subquery must be enclosed in parenthesis:
SQL> create table OSubscriber of TSubscriber
2 nested table loans store as loans
3 /
Table created.
SQL> create table OBook of TBook
2 /
Table created.
SQL> insert
2    into OBook
3    values(
4           1,
5           'No Title'
6          )
7 /
1 row created.
SQL> commit
2 /
Commit complete.
SQL> insert into OSubscriber
2    values(
3           1,
4           'LEVEQUE',
5           NTLoan(
6                  (select TLoan(ref(b),DATE '1985-10-03') from OBook b where b.num = 1)
7                 )
8          )
9 /
1 row created.
SQL> select *
2    from OSubscriber
3 /
    SUB_ID NAME
LOANS(BOOK, LOANING_DATE)
         1 LEVEQUE
NTLOAN(TLOAN(000022020863025C8D48614D708DB5CD98524013DC88599E34C3D34E9B9DBA1418E49F1EB2, '03-OCT-85'))
SQL> SY.

Fetch data from one table and insert into two tables in desired format

I have similar to the following data in a table and it is not normalized. The groupID is being used to group two records of similar nature.
DECLARE @OldDoc TABLE (oldDocID INT, groupID INT, deptID INT)
INSERT INTO @OldDoc (oldDocID, groupID) VALUES (1, NULL, 111),(2,NULL,111),(3,1,111),(4,NULL,333),(5,1,222),(6,NULL,333),(7,2,222),(8,2,333),(9,NULL,111),(10,3,222),(11,NULL,333),(12,3,444)
I need to process the data from the above table (@OldDoc) and write into two new tables (@NewDoc and @NewDocGroup) as follows.
oldDocID should be stored as newDocID when inserting to @NewDoc table. Only records with groupID NULL and one record (first one) per group should be considered (For example, oldDocID 5 is not considered as 3 and 5 belong to the same groupID 1) for insertion.
DECLARE @NewDoc TABLE (newDocID INT)
INSERT INTO @NewDoc (newDocID) VALUES (1),(2),(3),(4),(6),(7),(9),(10),(11)
All records from @OldDoc should be considered for insertion into @NewDocGroup table. OldDocID is inserted as NewDocID and deptID is as-is. Instead of groupID, the ID of the first record in the
group should be considered as parentNewDocID (For example, 3 is considered as parentNewDocID for newDocID 5 as 3 and 5 belong to the same groupID in @OldDoc table) for the newDocID.
DECLARE @NewDocGroup (newDocID INT, parentNewDocID INT, deptID INT)
INSERT INTO @NewDocGroup (newDocID, parentNewDocID, deptID) VALUES (1,1,111),(2,2,111),(3,3,111),(4,4,333),(5,3,222),(6,6,333),(7,7,222),(8,7,333),(9,9,111),(10,10,222),(11,11,333),(12,10,444)
How do I accomplish the above using SQL ? Thanks for the help.

>> I have similar to the following data in a table and it is not normalized. The group_id is being used to group two records [sic] of similar nature. <<
Rows are not records. Tables have to have a key by definition. You do not do math with identifiers, so they should not be numeric. Let's ignore that error for now. In short, you are posting garbage. If you had followed Forum Netiquette, would you have posted
this?
CREATE TABLE Old_Documents
(old_doc_id INTEGER NOT NULL PRIMARY KEY,
group_id INTEGER,
dept_nbr INTEGER NOT NULL
REFERENCES Departments (dept_nbr));
INSERT INTO Old_Documents(old_doc_id, group_id, dept_nbr)
VALUES (1, NULL, 111),
(2, NULL, 111),
(3, 1, 111),
(4, NULL, 333),
(5, 1, 222),
(6, NULL, 333),
(7, 2, 222),
(8, 2, 333),
(9, NULL, 111),
(10, 3, 222),
(11, NULL, 333),
(12, 3, 444);
>> I need to process the data from the above table (Old_Documents) and write into two new tables (New_Documents and New_Documents_Groups) as follows. <<
Just like punch cards and mag tape data processing! Being old and being new are a status, not another kind of entity. But that is how mag tapes work. And you even use the verb "fetch" from tape files. This design flaw is called attribute splitting.
Do you have a Male_Personnel and Female_Personnel table? NO! It is just Personnel!
>> old_doc_id should be stored as new_doc_id when inserting to New_Documents table. Only records [sic] with group_id NULL and one record [sic] (first [sic; no ordering in a table] one) per group should be considered (For example, old_doc_id 5 is not considered
as 3 and 5 belong to the same group_id =1) for insertion. <<
Think about your punch card mindset. Why did you physically materialize that redundant New_Documents table? Let me answer that: this is how you work with punch cards! In SQL we use a VIEW:
CREATE VIEW New_Documents (new_doc_id)
AS
SELECT old_doc_id
FROM Old_Documents;
>> All records [sic] from Old_Documents should be considered for insertion into New_Documents_Groups table. The old_doc_id is inserted as new_doc_id and dept_nbr is as-is. Instead of group_id, the ID [sic: which identifier??] of the first [sic: tables
have no ordering like a deck of punch cards] record [sic] in the group should be considered as parent_new_doc_id (For example, 3 is considered as parent_new_doc_id for new_doc_id 5 as 3 and 5 belong to the same group_id in Old_Documents table) for the new_doc_id.
<<
Why not use 5 as the parent? My guess is that you are trying to form equivalence classes. See:
https://www.simple-talk.com/content/print.aspx?article=2020
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