Internal mechanism of Sorted Set
Hi,
I want to understand the internal mechanism of how the objects in a SortedSet gets sorted automatically? Also i have a confusion about the objects thar are stored in a Sorted set:-
1. Is it mandatory for the objects to be stored in Sorted set to override equals and hascode? If yes, are these methods called automatically every time a new object is stored in Sorted Set?
OR
2. Is it mandatory for the objects to be stored in Sorted set to implement comparable or comparator interface? If yes, is the compareTo method called automatically every time a new object is stored in Sorted Set?
Thanks
Neha_Khands wrote:
1. Is it mandatory for the objects to be stored in Sorted set to override equals and hascode? No, but probably a very good idea to do so.
If yes, are these methods called automatically every time a new object is stored in Sorted Set?They might be. It would depend on the particular implementation. The documentation for the given implementation should specify and requirements around those methods.
OR
2. Is it mandatory for the objects to be stored in Sorted set to implement comparable or comparator interface?Either the class your storing must implement Comparable, OR you must provide a separate Comparator object (and that Comparator would NOT be implemented by the class you're storing).
If yes, is the compareTo method called automatically every time a new object is stored in Sorted Set?Yes. Imagine you have a bunch of cards with numbers written on them, and they're laid out in a row, in numerical order, such as [2, 8, 9, 10, 14, 19]. Now you have a card with the number 12 on it. You want to insert it into that group, in the proper place to keep order. To do that, you're going to have to compare that card's value to some of the cards already there, to know where it goes. At some point you'll compare it to 10, find that it's greater, and know that it must therefore go to the right of 10. This comparison is performed "automatically" by you when someone asks you to add (store) a new card into that set.
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