Interval(fraction of hour) in a day

hello to all
I have a
select
to_date('16/08/2012 08:00','dd/mm/yyyy hh24:mi') + ((level-1)*15/24/60)
--when frazione <> 15 then to_date('16/08/2012 08:00','dd/mm/yyyy hh24:mi') + ((level-1)*20/24/60)
--end
Hours
from dual connect by level < 48
and I got
16/08/2012 08:00:00
16/08/2012 08:15:00
16/08/2012 08:30:00
16/08/2012 08:45:00
16/08/2012 09:00:00
16/08/2012 09:15:00
16/08/2012 09:30:00
16/08/2012 09:45:00
...I ask me if possibile to get same result replacing the fraction with a variable ((level-1)*15/24/60), that is I can get the resul with all fraction of day, 10,15,20 minutes and so on , if I like 20 min I get
((level-1)*20/24/60) --- ((level-1)*&inthour/24/60)
16/08/2012 08:00:00
16/08/2012 08:20:00
16/08/2012 08:40:00
thanks in advance

I'm sorry if return on the subject, from the following query:
select
&fractiondate+ (level * numtodsinterval(&minutefraction, 'MINUTE') )
Hours
from dual connect by level < .....which is inside a Db stored , Can I limit the rows returned, that is, I like only those in a range, for example:
from 10:05 (included) to 16:05 (included) for an x interval (minutes), example if x= 60, only those rows I want
10:05
11:05
12:05
13:05
14:05
15:05
16:05Thanks for any help

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Return average of time interval in each hour for each day

I am reading from a database and the data is stored like this
Date................ Hour........Hour Interval..........Price
2010/07/01.........1...................1.....................x
2010/07/01.........1...................2.....................x
2010/07/01.........1...................3.....................x
2010/07/01.........1...................4.....................x
2010/07/01.........1...................5.....................x
2010/07/01.........1...................6.....................x
2010/07/01.........1...................7.....................x
2010/07/01.........1...................8.....................x
2010/07/01.........1...................9.....................x
2010/07/01.........1...................10...................x
2010/07/01.........1...................11...................x
2010/07/01.........1...................12...................x
2010/07/01.........2...................1.....................x
2010/07/01.........2...................2.....................x
2010/07/01.........2...................3.....................x
2010/07/01.........2...................4.....................x
How would I write an sql statement to get the average for the price for each hour. The average should take the average of all the prices in the interval from 1 to 12
Any suggestions
Edited by: user13353366 on Jul 1, 2010 11:55 AM

Hi,
Welcome to the forum!
Whenever you have a question, it helps if you post a little sample data (CREATE TABLE and INSERT statements) and the results you want from that data. No doubt you have a perfectly clear idea of what your data is, and what results you want, but other people are likely to make bad assumptions from just looking at a description of the problem. For example, are date and hour one colum or two? What role does hour_interval play in this problem?
So, in addition to a description of the data and the probelm, post a specific example, like this for the data:
CREATE TABLE     table_x
(     dt          DATE
,     hour_interval     NUMBER (2)
,     price          NUMBER
INSERT INTO table_x (dt, hour_interval, price) VALUES (TO_DATE ('2010/07/01 01', 'YYYY/MM/DD HH24'),   1,   1);
INSERT INTO table_x (dt, hour_interval, price) VALUES (TO_DATE ('2010/07/01 01', 'YYYY/MM/DD HH24'),   2,   1.1);
INSERT INTO table_x (dt, hour_interval, price) VALUES (TO_DATE ('2010/07/01 02', 'YYYY/MM/DD HH24'),   4,   9);
INSERT INTO table_x (dt, hour_interval, price) VALUES (TO_DATE ('2010/07/01 02', 'YYYY/MM/DD HH24'), 13,   9.9);and like this for the results you want from that same data:
HR             AVG_PRICE
2010/07/01 01       1.05
2010/07/01 02          9If those happens to be the results you would want from that data, then, as Lkbrwn said, AVG and GROUP BY can get them for you, like this:
SELECT       TRUNC (dt, 'HH')     AS hr
,       AVG (price)          AS avg_price
FROM       table_x
WHERE       hour_interval     BETWEEN      1
               AND     12
GROUP BY TRUNC (dt, 'HH')
ORDER BY hr
;

Calculating fractions of hours from time date range

Hello friends,
I'm using sql server 2008 r2 and I have a table called attendance with the following fields
attendance_no    int
attendance_date    date
attendance_timein    time(7)
attendance_timeout    time(7)
emp_id    int
and another table called employee with the following fields
emp_id int
emp_name varchar(50)
emp_tel varchar(50)
I need to calculate the total minutes worked as well as total hours worked for each employee with in a specified date range and I created the below query which working fine but it is not calculating the fractions of hours, I mean when an employee works
for example 7 and half hours, its showing just 7 hours instead of 7.5 hours.
SELECT a.attendance_date As 'Date',e.emp_id As 'ID',e.emp_name As 'Name',e.emp_tel As 'Telephone',left(a.attendance_timein,8)[Time in],left(a.attendance_timeout,8)[Time out],
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Thanks in advance
Mohamoud

If I understand correctly, according to
Mohamoud's data sample, there is already Total minutes in the input (the above
table Mohamoud posted)
and all he need is a simple convert to decimal and the divided by 60.
select [Total minutes] / 60.c
Mohamoud,
is that correct?
The result show that you might need some rounding. for example 31/60 is 0.516666 while you show us 0.5
Please clarify if you need rounding and how many characters after the dot you need (this can be done using declaring decimal(x,y), converting, or multipla and using floor function, etc')
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2.] Ask if there's a better way? . . .although if the syntax is right this should work pretty well
Thank you
Edited by: BDub122 on Mar 19, 2013 8:33 AM

Works for me:
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( "EVENT_ID" NUMBER(20,0),
"END_TIME" TIMESTAMP (3)
SEGMENT CREATION IMMEDIATE
PARTITION BY RANGE ("END_TIME")
INTERVAL(NUMTODSINTERVAL(4, 'HOUR')) -- Partition every 4 hours
(PARTITION "2013-03-19 00:00:00" VALUES LESS THAN (TO_DATE
('2013-03-19 00', 'YYYY-MM-DD hh24', 'NLS_CALENDAR=GREGORIAN')))
insert into event values (1, sysdate - 8/24)
insert into event values (1, sysdate - 4/24)
insert into event values (1, sysdate)
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2013-03-19 00:00:00
SYS_P230
SYS_P231
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Hi,
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But in most of my previous projects where not all recorded overtime was calculated, this was often to a missing selection rule in T554S.
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