Is 2^N-1 equals to (1 (N-1))-1

Dear all,
Is 2^(N-1) equals to (1<<(N-1))-1? If yes, why. If no, also why
Thanks =D
Roy

Let N = 1
Math.pow(2, 1) - 1 = 1
(2 ^ 1) - 1 = 2
(1 << (1 - 1)) -1 = 0
Let N = 2
Math.pow(2, 2) - 1 = 3
(2 ^ 2) - 1 = -1
(1 << (2 - 1)) -1 = 1
Let N = 3
Math.pow(2, 3) - 1 = 7
(2 ^ 3) - 1 = 0
(1 << (3 - 1)) -1 = 3
Let N = 4
Math.pow(2, 4) - 1 = 15
(2 ^ 4) - 1 = 5
(1 << (4 - 1)) -1 = 7
Let N = 5
Math.pow(2, 5) - 1 = 31
(2 ^ 5) - 1 = 6
(1 << (5 - 1)) -1 = 15

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Attachments:
Check Run Arrow_BD.png ‏6 KB

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Is 2^N-1 equals to (1 (N-1))-1

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