Java Access Helper problem

I just downloaded Java Access Helper zip file, and unzipped, and run the following command in UNIX
% java -jar jaccesshelper.jar -install
I get the following error message, and the installation stopped.
Exception in thread "main" java.lang.NumberFormatException: Empty version string
at java.lang.Package.isCompatibleWith(Package.java:206)
at jaccesshelper.main.JAccessHelperApp.checkJavaVersion(JAccessHelperApp.java:1156)
at jaccesshelper.main.JAccessHelperApp.instanceMain(JAccessHelperApp.java:159)
at JAccessHelper.main(JAccessHelper.java:39)
If I try to run the jar file, I get the same error message.
Does anyone know how I can fix this?
Thanks

sorry ab the multiple post, it was urgent for me to
know the answer.
I've JDK 1.4.2 and JAccessHelper should work with 1.3
or later
Can there be some kind of path problems?No, I doubt it. It's just some internal app failure - looks like it's trying to determine the running Java version, and is not doing a good job at it. But the failure has nothing per se to Java, it's that specific app - what are we supposed to know about that app though?

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Java Access Helper Jar file problem

I just downloaded Java Access Helper zip file, and unzipped, and run the following command in UNIX
% java -jar jaccesshelper.jar -install
I get the following error message, and the installation stopped.
Exception in thread "main" java.lang.NumberFormatException: Empty version string
at java.lang.Package.isCompatibleWith(Package.java:206)
at jaccesshelper.main.JAccessHelperApp.checkJavaVersion(JAccessHelperApp.java:1156)
at jaccesshelper.main.JAccessHelperApp.instanceMain(JAccessHelperApp.java:159)
at JAccessHelper.main(JAccessHelper.java:39)
If I try to run the jar file, I get the same error message.
Does anyone know how I can fix this?
Thanks

Cross-posted, to waste yours and my time...
http://forum.java.sun.com/thread.jsp?thread=552805&forum=54&message=2704318

Java tutorial - helps, problem is i don't understand the API

I don't understand the JAVA Tutorials or the API

Take two steps back.
Buy a book on basic Java Programming. You need to understand the concepts behind programming before you should start reading the API.
But kudos for at least trying to read the API.
Now look at the column on the left, and follow the link called [url http://developer.java.sun.com/developer/onlineTraining/] Tutorials
and then the link titled [url http://java.sun.com/docs/books/tutorial/index.html]The Java Tutorial (Java Series).
And finally read through the sections starting with [url http://java.sun.com/docs/books/tutorial/getStarted/cupojava/index.html]Your First Cup of Java.
Then once you have been through all of that, come back and ask for clarification
on any specific points that you have trouble understanding.
Finally (Because the Finally always gets executed) Try taking a class in java programming.
regards

Java JDK Installation Problem - Need Help!

Below is my program Access.java which resides in c:\java. It generates a "NoSuchMethodError" when I run it on my Windows 2000 computer at work. When my friend here at work runs the SAME program on his Windows 2000 computer, it runs fine. I have No idea why! I suspect it's a classpath problem, but I use the same classpath on my Windows 98 computer at home w/o a problem.
For windows 2000, I set my path statement by going into the Control Panel ->System->Advanced Tab and adding a user variable named path.
To set my classpath, I use sysedit. Anyway, here's what my path and classpath statements look like in my c:\autoexec.bat
path=c:\windows;c:\windows\command;c:\java
path=c:\jdk1.3.1\jre\bin;c:\jdk1.3.1\bin;%path%
set classpath = .;%classpath%;c:\jdk1.3.1\jre\lib;c:\java\;
Finally, here's my c:\java\Access.java program that blows up (only on MY Windows 2000 machine)
//Access.java
package com.gfarms.geometry;
class Other
public void fnc(int b)
System.out.println("integer received = " + b);
public class Access
public static void main(String[] args)
Other a = new Other();
a.fnc(48);
Any help would be deeply appreciated!

Try this:
create a new directory called c:\java\com\gfarms\geometry and move Access.java to it. Delete all class files.
compile from c:\java:
c:\java> javac com/gfarms/geometry/Access.java
run it:
c:\java> java com.gfarms.geometry.Access

[ Java Accessibility - Problem]

I have a problem with Java Accessibility API with C#.
I get the handle of my Applet with Spy++ and invoke the function GetAccessibleContextFromHWND (WindowsAccessBridge.dll).
But the result pointer is -858993460 it's impossible! Then I invoke isJavaWindow and the result is FALSE! Why? the handle that I put is right! If I get an enumeration of the opened window and invoke isJavaWindow is always False! Why?
Code:
IntPtr HINSTANCE= SunAPI.LoadLibrary(SunAPI.PATH_WindowsAccessBridge+SunAPI.WindowsAccessBridge);
SunAPI.Windows_run();
long lng;
return SunAPI.isJavaWindow(hwnd);
SUNAPI.cs
public class SunAPI
[DllImport("kernel32.dll")]
public static extern IntPtr LoadLibrary(string lpFileName);
[DllImport("WindowsAccessBridge", CallingConvention =     CallingConvention.Cdecl)]
public extern static void Windows_run();
[DllImport("WindowsAccessBridge", CallingConvention =     CallingConvention.Cdecl)]CallingConvention.Cdecl)]
public extern static bool isJavaWindow(IntPtr window);
[DllImport("WindowsAccessBridge", CallingConvention =     CallingConvention.Cdecl)]CallingConvention.Cdecl)]
public static extern IntPtr GetAccessibleContextFromHWND(IntPtr hwnd, out long vmID,IntPtr ac);
[DllImport("User32.dll", SetLastError = true)]
public static extern IntPtr FindWindowEx(IntPtr hwndParent, IntPtr hwndChild, string className, string windowName);
}

Use FindWindow instead of FindWindowEx.
IntPtr FindWindow(string className, string windowTitle);
Edited by: 998634 on Apr 9, 2013 3:46 AM

Problems with Java Access Bridge

Hello to all,
first of all, sorry if the message is in the wrong place.
I'm developing an application, in C++, to fill up the fields in a Java aplication, it should work on a Windows 7 x64 machine. I'm using jdk 6u29 and java access bridge 2.0.2 for 32 bits soft.
My problem is that in some computers the function isJavaWindow() allways returns false when it it should be true, the most rare thing with it is tha it is working in a virtual machine, and in a clone of this virtual machine it is not working... Is there any special consideration I have to take into account when using Java AccessBridge?
Thank you!
Roger.

Bump... I'd like to know how to click a button with Access Bridge too. I can automate windows programs tho... So, isn't there really anyone who knows how to automate a Java program with C++ and Access Bridge?

Java access problem - no authorization

when i log in to SAP java access engine
I can see the first page. If I click on anything, I get an error message that I am not authorized to see the same .
Please help me
Thanks
bharat

check with SU53 transaction for authorization issues,if found send the screenshot to Basis requesting the same
Hope it Helps
Chetan
@CP..

New to java(need help on access specifier)

hi! i am new to java.plzzzzz help me i have to make a project on access specifier's i know all theroy.but
i am unable to understand how i can define all specifiers practicly.i mean in a program.
thanks.plzzzzzzzz help me

the most common project i can think of is a payroll system..
you can have real implementation of all the access specifiers
good luck

JAVA with MYSQL problem

i am using jdk1.6.0_02,apache tomcat 5.5.23 ,mysql integrated with redhat linux EE 4 and.mysql connector java 5.0.7.bin.jar.
look at the the following java program
import java.sql.*;
public class TestMysql
public static void main(String args[])
try
String driver = "com.mysql.jdbc.Driver";
Class.forName( driver );
String url = "jdbc:mysql://localhost/test";
DriverManager.getConnection( url, "root", "mysql" );
catch( Exception x )
{ x.printStackTrace();
i got the following exception
java.sql.SQLException: Access denied for user 'root'@'localhost.localdomain' (us *** password:
YES)
at com.mysql.jdbc.SQLError.createSQLException(java.lang.String, java.lang.Str ***, int)
(Unknown Source)
at com.mysql.jdbc.MysqlIO.checkErrorPacket(int) (Unknown Source)
at com.mysql.jdbc.MysqlIO.checkErrorPacket() (Unknown Source)
at com.mysql.jdbc.MysqlIO.secureAuth411(com.mysql.jdbc.Buffer, int, java.lang .String,
java.lang.String, java.lang.String, boolean) (Unknown Source)
at com.mysql.jdbc.MysqlIO.doHandshake(java.lang.String, java.lang.String, jav a.lang.String)
(Unknown Source)
at com.mysql.jdbc.Connection.createNewIO(boolean) (Unknown Source)
at com.mysql.jdbc.Connection.Connection(java.lang.String, int, java.util.Prop erties,
java.lang.String, java.lang.String) (Unknown Source)
at com.mysql.jdbc.NonRegisteringDriver.connect(java.lang.String, java.util.Pr operties)
(Unknown Source)
at java.sql.DriverManager.getConnection(java.lang.String, java.util.Propertie s)
(/usr/lib/libgcj.so.5.0.0)
at java.sql.DriverManager.getConnection(java.lang.String, java.lang.String, j
ava.lang.String) (/usr/lib/libgcj.so.5.0.0)
at Connect.main(java.lang.String[]) (Unknown Source)
access denied problem. but the user name and password are correct. i can login to mysql by using
the same username and password.
but when connecting through java , i can't ? what is the problem?
can u help me.?
actually i am working in JSP. and when i got this problem, i created a small java program for testing.
here i am submitting the java program.

friend please put your code inside
// your code goes here it will more readable and other can solve it better.
==================
and your problem tells that you must set access permission inside
mySQL server.
or try with creating new User with password.
EnJOY.
Ghanshyam
Edited by: Ghanshyam on Sep 28, 2007 4:13 PM

JPasswordField is not recognized by Java Access Bridge

Hi,
I am using Zoomtext 9.1 Reader/Magnifier for accessibilty purpose with my Swing based application. For communication in between the Zoomtext and Swing application I ma using Java Access Bridge 2.1.
The problem is with JPasswordField. When I am putting focus on the password field it's not reading it out, but when I am typing password in this field, zoom text is reading the typed in alphabet instead of aestrik "*".
The focus behavior for JTextField is working fine.
Also unable to read the Message shown in JOption dialog box.
Could any body help me out?
Thanks in advance.
Here is the sample code to see the behavior:
import javax.swing.*;
import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
public class ZoomTest
public static void main(String[] args)
JTextField userName = new JTextField(10);
JPasswordField password = new JPasswordField(10);
JButton submit = new JButton("Submit");
submit.setFocusCycleRoot(true);
JMenuBar jMenuBar = new JMenuBar();
JMenu jMenuFile = new JMenu("File");
jMenuFile.setToolTipText("File");
JMenuItem jMenuItemNew = new JMenuItem("New");
JMenuItem jMenuItemOpen = new JMenuItem("Open");
JMenuItem jMenuItemCopy = new JMenuItem("Copy");
jMenuFile.add(jMenuItemNew);
jMenuFile.add(jMenuItemOpen);
jMenuFile.add(jMenuItemCopy);
jMenuBar.add(jMenuFile);
JLabel userNameLabel = new JLabel("User Name", JLabel.RIGHT);
userNameLabel.setLabelFor(userName);
JLabel passwordLabel = new JLabel("Password", JLabel.RIGHT);
passwordLabel.setLabelFor(password);
final JFrame frame = new JFrame("Login");
JPanel panel = new JPanel( );
panel.setLayout(new GridLayout(3, 2, 5, 5));
panel.add(userNameLabel);
panel.add(userName);
panel.add(passwordLabel);
panel.add(password);
panel.add(submit);
submit.setToolTipText("Submit");
submit.addActionListener(new ActionListener()
public void actionPerformed(final ActionEvent e)
JOptionPane.showMessageDialog(new JFrame(), "Click submit");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setJMenuBar(jMenuBar);
frame.setContentPane(panel);
frame.setVisible(true);
}

After discussion with Zoomtext tech support guys we came to know that Zoomtext 9.1 is not supporting Java Swing applications for accessibility options. So I will recommend not to use Zoomtext for Accessibilty options in any of the Java Swing applications.

Sir i am using datasocket read ,i am communicating with java but my problem is that bcz im using while loop to see if value has changed my labview consumes all the processors time ,sir i want a event like thing so that while loop is not in continuous loop

sir i have given lot of effort but i am not able to solve my problem either with notifiers or with occurence fn,probably i do not know how to use these synchronisation tools.

sir i am using datasocket read ,i am communicating with java but my problem is that bcz im using while loop to see if value has changed my labview consumes all the processors time ,sir i want a event like thing so that while loop is not in continuous loopHi Sam,
I want to pass along a couple of tips that will get you more and better response on this list.
1) There is an un-written rule that says more "stars" is better than just one star. Giving a one star rating will probably eliminate that responder from individuals that are willing to anser your question.
2) If someone gives you an answer that meets your needs, reply to that answer and say that it worked.
3) If someone suggests that you look at an example, DO IT! LV comes with a wonderful set of examples that demonstate almost all of the core functionality of LV. Familiarity with all of the LV examples will get you through about 80% of the Certified LabVIEW Developer exam.
4) If you have a question first search the examples for something tha
t may help you. If you can not find an example that is exactly what you want, find one that is close and post a question along the lines of "I want to do something similar to example X, how can I modify it to do Y".
5) Some of the greatest LabVIEW minds offer there services and advice for free on this exchange. If you treat them good, they can get you through almost every challenge that can be encountered in LV.
6) If English is not your native language, post your question in the language you favor. There is probably someone around that can help. "We're big, we're bad, we're international!"
Trying to help,
Welcome to the forum!
Ben
Ben Rayner
I am currently active on.. MainStream Preppers
Rayner's Ridge is under construction

Using Java Access bridge (Accessibility) with oracle forms 6.0 client

I'm trying to use JAB (java Access bridge ) to capture events in oracle forms 6.0 client .
I've a Jinitiator 1.1.8 and JRE version 1.4x
I've configured JAB as per the installation guide . However the events don't surface in Java Monkey .
Has anybody encountered similar issue ? what is the solution for the issue ??
Also on one of the forums I read Jinitiator 1.3x and above is automatically recognised by Java Access bridge .
For jinitiator version less than 1.3 manual configuration is required . however I haven;'t been able to find any on the oracle forms KB
Also here is the excerpt from the link http://www.oracle.com/us/corporate/accessibility/faqs/index.html
Q: Are there special steps for using Java-based applications with assistive technology?
A: If the Oracle application is written in Java, such as JDeveloper or Oracle Forms (runtime), customers must first install the latest version of Sun's Java Access Bridge. The Java Access Bridge provides the integration with screen readers such as JAWS or SuperNova that support Java. You just download the Access Bridge and install it. Sun's AccessBridge 2.0x recognizes Oracle's JInitiator 1.3x and above so no manual configuration steps are necessary. The Access Bridge is available from: http://java.sun.com/products/accessbridge. At the time this document was written, Access Bridge 2.0.1 is the most current publicly available production release; Oracle recommends upgrading to this version. Sun's AccessBridge is bundled with Oracle Universal Installer (OUI) and can be found in the Java Runtime Engine (JRE). More information for configuring such products is in the respective product documentation, or on http://www.oracle.com/us/corporate/accessibility/products/index.html.
Edited by: 974810 on 4 Dec, 2012 1:10 AM

ODP.NET requires Oracle Client 9.2 or higher.
You can find additional information about ODP.NET from the FAQ:
http://www.oracle.com/technology/tech/windows/odpnet/faq.html
and the ODP.NET homepage:
http://www.oracle.com/technology/tech/windows/odpnet/index.html
Hope that helps,
Mark

APEX 2.2 Help Problems

I have a couple of issues. 
1. Using None Database Authentication causes 'Unauthorized Access' Message when accessing help, while been a public user. 
2. When calling images in item help does not work, but does in page help.
 
Notes. 
1. Found thread explaining issue 1 and that it was a bug in 2.2 and using Database Authentication was a work around (Looks like the APEX team has succumb to the Oracle Way of doing things, Sigh). So this is no longer a question, just a gripe. 
2. Using img src=#WORKSPACE_IMAGES#blah.gif (obviously with the brackets and quotes) in Page help displays correctly, but in item help we get the familar image not found icon.

Wayne,
1. Using None Database Authentication causes 'Unauthorized Access' Message when accessing help, while been a public user.This is not an accurate description of the bug. I am unable to recreate the problem as you described it. Perhaps you have found a new bug. A bug like this was fixed in 2.2.1.
(Looks like the APEX team has succumb [sic] to the Oracle Way of doing things, Sigh).I don't know what that means, feel free to elaborate.
So this is no longer a question, just a gripe.What is the gripe?
2. Using img src=#WORKSPACE_IMAGES#blah.gif (obviously with the brackets and quotes) in Page help displays correctly, but in item help we get the familar image not found icon.This is a new bug. Apparently no one has ever tried this before. Thanks for the info.
Scott

Access rights problem

I have set up two OID instances to talk between one another and think I have the mapping files correct.
I now see Insufficient Access Rights in the logs. Does anyone have any ideas what this could be? Does the exchange between servers run under a specific user?
orclOdipSynchronizationStatus: Mapping Failure, Agent Execution Not Attempted
orclOdipSynchronizationErrors: Error Creating Entry in OID
Sleeping for 1secs
Exception creating Entry : javax.naming.NoPermissionException: [LDAP: error code 50 - Insufficient Access Rights
]; remaining name 'cn=[email protected],cn=users,dc=hoc,dc=test,dc=com'
[LDAP: error code 50 - Insufficient Access Rights]
OIDUserImport:Error in Mapping EngineODIException: DIP_OIDWRITER_ERROR_CREATE
ODIException: DIP_OIDWRITER_ERROR_CREATE
at oracle.ldap.odip.gsi.LDAPWriter.createEntry(LDAPWriter.java:975)
at oracle.ldap.odip.gsi.LDAPWriter.insert(LDAPWriter.java:328)
at oracle.ldap.odip.gsi.LDAPWriter.writeChanges(LDAPWriter.java:239)
at oracle.ldap.odip.engine.AgentThread.mapExecute(AgentThread.java:406)
at oracle.ldap.odip.engine.AgentThread.execMapping(AgentThread.java:262)
at oracle.ldap.odip.engine.AgentThread.run(AgentThread.java:155)
Regards

Do let us know if you find the answer. I've been stuck for days on an LDAP access rights problem.

Hi, Trying to log in with my user id and password at iocbc but was not able to access. Problem message shown : Applet not initialised or may not be supported. Please refresh the page or check the browser setting Anyone can advise? or i need to download?

Hi,
i have the same problem?
Trying to log in with my user id and password at iocbc but was not able to access.
Problem message shown : Applet not initialised or may not be supported. Please refresh the page or check the browser setting
Anyone can advise?

You need to install Java for your Mac OS version, and/or make sure it's enabled in the Java Preferences application and your browser's preferences.

Java Access Helper problem

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