Java Generics problem
abstract class ABS<K extends Number>
public abstract <K> K useMe(Object k);// understood ..
public abstract <K> ABS<? extends Number> useMe(ABS<? super K> k) ; //1
public abstract <K> ABS<? super Number> useMe(ABS<? extends K> k); //2
public abstract <K> ABS<K> useMe(ABS<K> k);// understood ..
1 and 2 this both should not work because K can be anything here....
can anyone please explain???
Thanks in advance...
user13384537 wrote:
Firstly thanks for your kind reply .....
can you please elaborate it more ???? because i am confused too much in generic methods especially ....i am preparing for OCPJP and i am not getting reply for this question any where. You are first to reply this question...Both "? super Number" and "? super K" (indeed, "? super {anything}") represent unknown types with no upper bound. While it's true that they could both, in fact, be 'Number's, the compiler has no way of knowing this, which is why it's invalid for an ABS (because you've already defined it as taking a type that extends Number).
I'll be flamed if I'm wrong; but that's the way I understand it.
My suggestion would be to look at the [url http://download.oracle.com/javase/tutorial/extra/generics/index.html]Gilad Bracha tutorial. It's quite long in the tooth, but it's still the best one around, I reckon.
Winston
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One thing java generics are missing
specialization!
I'll give you a templated example with a function here:
template <typename T>
inline std::string to_string(const T& t)
std::istringstream ss;
ss << t;
return ss.str();
that's one of those standard conversion snippets that everyone uses... as long as T supports the "<<" operator, it will convert just fine...
Now, if you're using this function in other template based code, the problem comes up:
template <typename T>
void foo(const T& t)
std::string s = to_string(t);
... do something with s now...
it makes sense, if you want to do operations with a string... but what if the type T *was* a string... the to_string function just did a whole mess of needless operations (stringstream conversion)...
here comes template specialization to the rescue:
template <> inline std::string to_string<std::string>(const std::string& t)
return t;
there we go... no extra steps... because it's inlined to begin with, the compiler will remove it... (this is what's called a conversion shim). Now when the to_string function is called with an std::string argument, it does nothing.Hmmm, it seems I didn't explain it too well:
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Press any key to continue...
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Date: 2008-04-01 15:11:05 -0700 (Tue, 01 Apr 2008)
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this.al = al;
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return al;
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String firstname;
int age;
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