Know how make best and faster this?. View my code.

Question

//ANYTHING KNOW HOW READ A HTML PAGE FROM
//A URLCONNECTION BEST AND FASTER THAN
//MY METHOD getHTMLFile(URL)?
// MY METHOD
public String getHTMLFile(URL ff)
char bufferc[]; // To put the content of the file
InputStream entrada=null;
try {                 
URLConnection conn=ff.openConnection();
entrada=conn.getInputStream();
BufferedReader leefichero=new BufferedReader(new InputStreamReader(entrada));
DataInputStream in=new DataInputStream(entrada);
String cadenafinal="";
// Who is the long of html file?
char c=' ';
filelength=0;
try {
while(true)
c=(char)(in.readByte());
filelength++;
cadenafinal=cadenafinal+c;
catch(java.io.EOFException IOEOF) {}
// put the content of the file in char's buffer.
bufferc=new char[(int)filelength];
cadenafinal.getChars(0,filelength,bufferc,0);
catch(IOException IOE)
System.err.println("Error: "+IOE);
return "Error, m�todo getHTMLFile(URL).";
// Return the content of the file in a type String.
if(echo) System.out.println(new String(bufferc));
return (new String(bufferc));
} // End of method getHTMLFile(URL).

Answer 1

i had an error in the code. which comes from working too fast. & also for free!
so you should cast to char after you do a check for -1. that is the only change.
two other issues:
you can use a larger buffer size for expected larger streams.
you really should be closing your own stream within a finally clause.
import java.io.*;
import java.net.*;
class Test2 {
     public static String getHTML(URL ff) throws IOException {
          BufferedInputStream data = null;
          try {
               data = new BufferedInputStream( ff.openStream() ) ;
//               data = new BufferedInputStream( ff.openStream(), 2048 or anything here ) ;
               StringBuffer buffer = new StringBuffer();
               int c; //not char c
               while ( -1 != ( c = data.read() ) )   //dont cast here
                    buffer.append( (char) c); //cast to char here
               return buffer.toString();
          } finally {
               try {
                    data.close();
               } catch (Exception e) { ;}//report or ignore
     public static void main(String[] args) throws IOException {
          try {
               String junk = Test2.getHTML( new URL(args[0]) );
               System.out.println(junk);
          } catch (IOException e) {
               e.printStackTrace();
     }