Lat/Lon Format

Canon 5D III, Canon GP-E2 GPS, LR 5.2
The Lat/Lon format in LR is displayed as:
35°45'54" N 82°15'54" W
That is very inconvenient for any other work.
The desired Lat/Lon format needs to be
35.76500, -82.26500
I can’t find a way to change the format. Can any one help?

WCA01 wrote:
Do you know of such a plugin and where to get it?
Jeffrey Friedl's metadata viewer will format it just the way you want, out of the box:
http://regex.info/blog/lightroom-goodies/metadata-viewer
It's a one-at-a-time thing, and takes a second or two for results.
If you want something more persistent and immediate, which you can use in lib-filters and/or smart collections..., consider ExifMeta - use the 'GPS Lat-Long in Decimal' preset (preset manager section of plugin manager).
Rob

Similar Messages

How to get GML data in LAT/LONG format rather than LONG/LAT format

I want to generate GML from my spatial data but sdo_util.to_Gmlgeometry extracts data in LONG/LAT format where as I need it in LAT/LONG format.
Is there an easy way to extract data in LAT/LONG format otehr than parsing the gml and then switching the Lat and long.

Hi,
I think it would have to do how you store your geometries, you might need a transformation before, notice the srsName from the resulting query:
SELECT TO_CHAR(SDO_UTIL.TO_GMLGEOMETRY(MDSYS.SDO_GEOMETRY(2001, 8307, NULL, MDSYS.SDO_ELEM_INFO_ARRAY(1,1,1), MDSYS.SDO_ORDINATE_ARRAY(170.5,-43.5))))
from dual
-- Result:
<gml:Point srsName="SDO:8307" xmlns:gml="http://www.opengis.net/gml"><gml:coordinates decimal="." cs="," ts=" ">170.5,-43.5 </gml:coordinates></gml:Point>
So without a transformation I would say it would be hard to get:
http://trac.osgeo.org/gdal/wiki/rfc20_srs_axes
If I come across a simple solution (without some fancy manipulation of the ordinates on a custom function/package) I will post it.
Cheers

Help needed to write algorithm to find Direction given lat/lon

Hello, i need an algorithm to find out the direction being traveled given the starting and ending lat/lon decimal coordinates. Anybody have any clues how to do it? or where i can find one to just plug into my program? thanks for your help
public String getDirection(double prevLat, double prevLon, double newLat, double newLon) {
    String direction;
    return direction;
}

Perhaps this helps:
http://www.cssd.ab.ca/tech/social/latitude/index.html
It will help you learn the meaning of lat/long-coords. I think you will end up with somthing like this:
if ( prevLat < newLat) {
   //we are travelling north
else {
   // we are travelling south
if (prevLong < newLong) {
   //we are travelling east?
else {
   //we are travelling west
}This could be wrong, since there is a west-long and an east-long..
Anyhow, hope this gets you on your way.
ps: is this a class-assignment??

Viewing actual lat/lon data in iPhoto

I want to view the actual lat/lon GPS data inclosed in a photo shot on my iPhone ?

HoughDah Geo can read the iPhoto database and display the Lat/Long - it also can automatically copy it to other photos based on time or add it from other sources including GPS trackers
LN

Any way to set picture locations to a specific lat/lon?

I've got a bunch of pictures in my iPhoto library that were taken at interesting places that aren't listed in the little database of landmarks that is pre-loaded into iPhoto '09. (For example: at the top of a mountain, or on a particular bridge, etc.) It's easy to find these places in Google Earth, so I know the exact latitude/longitude... but how can I tell iPhoto this information if the mountain/bridge/etc. isn't famous enough to be listed? Is there any way to just type in a latitude and longitude?
Thanks!

(However, that's a really cumbersome task if I'm going through a large roll of photos.
Select all photos taken at the same location and enter the location for all of them at once.
It would be great if there were a way to just type in a lat/lon if I know it
I don't see a difference in assigning a name to a lat/long entry or assigning a name to a "pin" location on a map.
because it's written in the picture file's EXIF header!
My understanding is that these photos will have to be re-imported if you want iPhoto '09 to "scan" the data and add it to the iPhoto '09 database if the photos where originally imported under iMovie '08.

Converting large amounts of points - 76 million lat/lon's to spatial object...

Hello, I need help.
Platform - Oracle 11g 64bit on Windows Enterprise server 2008 64bit. 64 GB of ram with 2 CPUs totalling 24 cores
Does any one know of a fast way to convert large amounts of points to a spatial object? I need to convert 76 million lat/lon's to ESRI st_geometry or Oracle sdo_geometry.
Currently, I have setup code using pipelined parallel functions and multiple jobs that run concurrently. It still takes over 2.5 hours to process all of the points.
Any pointers would be GREATLY appreciated!
Thanks
John

Hi,
Where is the lat/lon data at the moment? In an external text file or in an existing database table as number attributes?
If they're in an external text file, then I'd probably use an external table to load them in as quickly as possible.
If they're in an existing database table, then you can just update the sdo_geometry column using:
update <table> set <geometry column> = sdo_geometry(2001, <your srid>, sdo_point_type(<lon column>, <lat column>, null), null, null)
where <lon column> is not null
and <lat column> is not null;
That should run very quick for you. If you want to avoid the overhead of creating redo, you could use "create table .... as select...". This example of creating 1,000,000 points runs in 9 seconds for me.
create table sample_points (geometry) nologging as
(select sdo_geometry(2001, null,
sdo_point_type(
trunc(100000 * dbms_random.value()),
trunc(100000 * dbms_random.value()),
null), null, null)
from dual connect by level <= 1000000);
I have setup code using pipelined parallel functions and multiple jobs that run concurrently
You shouldn't need to use pl/sql for this task. If you find you do, then provide some sample code and we'll take a look.
Regards,
John O'Toole

Excel formula to calculate the distance between multiple points using lat/lon coordinates

I'm currently drawing up a mock database schema with two tables: Booking and Waypoint.
Booking stores the taxi booking information.
Waypoint stores the pickup and drop off points during the journey, along with the lat lon position. Each sequence is a stop in the journey.
How would I calculate the distance between the different stops in each journey (using the lat/lon data) in Excel?
Is there a way to programmatically define this in Excel, i.e. so that a formula can be placed into the mileagecolumn
(Booking table),
lookup the matching sequence (via bookingId)
for that journey in the Waypointtable
and return a result?
Example 1:
A journey with 2 stops:
1 1 1 MK4 4FL, 2, Levens Hall Drive, Westcroft, Milton Keynes 52.002529 -0.797623
2 1 2 MK2 2RD, 55, Westfield Road, Bletchley, Milton Keynes 51.992571 -0.72753
4.1 miles according to Google, entry made in mileage column
in Booking table
where id
= 1
Example 2:
A journey with 3 stops:
6 3 1 MK7 7DT, 2, Spearmint Close, Walnut Tree, Milton Keynes 52.017486 -0.690113
7 3 2 MK18 1JL, H S B C, Market Hill, Buckingham 52.000674 -0.987062
8 3 1 MK17 0FE, 1, Maids Close, Mursley, Milton Keynes 52.040622 -0.759417
27.7 miles according to Google, entry made in mileage column
in Booking table
where id
= 3
I understand that 100% accuracy is not possible, so it will not be an issue.

http://www.cpearson.com/excel/LatLong.aspx
and
http://www.contextures.com/excellatitudelongitude.html

Lat & lon in a JTable

I need to be able to show lat and lon in columns of a table. We want to be able to edit the field in either deg:min:sec or float forms and render in deg:min:sec. Does anyone know of a widget for that, or some hints as to how to approach it?
I have built a class to contain a value, along with constructors for the two forms of input, but am hung up on how to build a cell editor for it.
Thanks for your help.

I'd break it down into three steps
1) write a java.text.Format class that can correctly parse/format values to some data value. You probably want a Longitude and Latatude class to server as the the value, or you might want a Longitude:Latitude pair.
2) Write a cell renderer that takes an object of your value class and formats it appropriately for dispay, using the format you've written
3) Write a cell editor that accepts strings of the proper format and parses them using your custom format.
You can use either the java.text package, or the javax.swing.text package: the first leads to standard cell renderers/editors, and the second leads to JFormattedText (at least for editing). I'd try to stay with the first unless the user's absolutely had to have the colons preinserted (meaning that I then have to do the cursor tracking and document handling that JFormattedText gives you).

How to convert the x/y pixel into Lat/Lon?

Does anyone know how to covert the X/Y coord into Lat?lon coord system? What is the formular?
Thanks!!!
Ming

Depends on the projection your map is using.

Lat/Long Format

This should be easy but I've looked all over and I can't find how to change the format for the Lat/Long information. Currently the data shows as a decimal rather than the degrees, minutes, & seconds. For example, the Longitude currently shows 95.439777 and I'd like it to show 95 26.23. Any idea how to change the format?

No answers, so apparently can't be done.

GPS (Lat Lng) Format Problem

Hi,
I'm having a problem with GPS coordinates being rounded. I'm working on an application that receives a set off lat lng coordinates and then uses the MkMapView control to display the placemark. Most of the time everything seemed ok, however I noticed some unwanted rounding - for example:
54.6084566 is received from the webservice, but is rounded to 54.608457.
The code I;m using is
CLLocationCoordinate2D location;
location.latitude = [[m objectForKey:@"Latitude"] doubleValue];
location.longitude = [[m objectForKey:@"Longitude "] doubleValue];
The Lat Lng corrdinates are return from the webservice as a string, are there any other options that will preserve the accuracy?
Mark
Message was edited by: markpirvine

markpirvine wrote:
CLLocationCoordinate2D location;
location.latitude = [NSDecimalNumber decimalNumbeWithString [m objectForKey:@"Latitude"]];
location.longitude = [NSDecimalNumber decimalNumbeWithString [m objectForKey:@"Longitude "]];
The latitude and longitude fields of CLLocationCoordinate2D are doubles, so they're incompatible with NSDecimalNumber objects:
typedef double CLLocationDegrees;
typedef struct {
CLLocationDegrees latitude;
CLLocationDegrees longitude;
} CLLocationCoordinate2D;
Of course if you convert the very-high precision NSDecimalNumber values to the lower precision double type you'll be right back where you started from. The iPhone core location services use double precision in every data structure--presumably because the hardware isn't capable of higher precision.
I would have made this point previously (note it's the first point KT addressed), but since you were importing a higher precision value and simply asked what data type would support that precision, that's the only question I answered (I've been trying to cure myself of a tendency to attempt a book on computer science when someone only wants a one line answer; it takes lots of extra effort at my end and only succeeds in annoying the OP).
If you intend to do some calculations with the high precision coordinates you're getting from outside the iPhone, you'll need to write your own code which uses NSDecimalNumber at every step. If you use any of the CL support in the SDK, you'll lose the precision you obtained from the web site.
Hope that helps!
- Ray

Lat & Lon in Places - Aperture 3

I have numerous photos taken in the high Arctic about 20 years ago. How do I get Places to accept the latitude and longitude so I can locate them reasonably close to where they were taken on the map? When I expand the map there are no place names or geographical highlights to use as a visual reference. The photos were taken with a film camera and the locations were determined the old fashioned way.

TJK,
I'm not experiencing the same thing that you are. Here's what I did. Please follow the same actions and let us know what you find.
1. Select 1 photo
2. Go to Places view with the toolbar button
3. enter "74, -42" into the "Search the map" text box
4. Click on the only selection available ("72.000000, -42.000000 Tuvu")
5. Zoom out until I can see Greenland
6. Drag the 1 photo to the coast (so I can tell it's not at (72, -42), which is a lot of snow and ice)
7. Click the "done" button
8. Select 1 more photo
9. Drag the 1 photo to a different place
10. Click the "done" button
11. Select a different project
12. Reselect the project with the newly tagged photos
In my case, both photos are right where I dropped them.
nathan

Error creating a simple polygon with lat/lon

Hello,
When I validate the result of the following code used to insert a polygon, I get oracle error 13050 - Contact Oracle. If I change the order of the points, I get error 13349 - Polygon crosses itself, so I feel I have the points in the correct order. Any ideas why this polygon won't validate to true?
insert into tblname values(
(mdsys.sdo_geometry(2003,null,null,
mdsys.sdo_elem_info_array(1,1003,1),
mdsys.sdo_ordinate_array
(-89.228298,42.916663,
-89.344087,43.247025,
-89.016191,43.33739,
-88.912663,43.079601,
-89.02033,43.008463,
-89.228298,42.916663))
), field 2, 'field3')
Thanks for any thoughts,
David

Bruce,
I was attempting solve a business/spatial problem the wrong way, based on limited experinece with Oracle spatial.
I need to create a convex hull polygon from a splatering of points. (for sake of arguement, lets say the points are salesmans locations and there will be approx 2,000 salesmans locations. I need to create a convex hull of these 2000 points).
My initial thought was to use the points as input to making a polygon. I was then going to use this polygon as input to making the convex hull. In order to make a valid polygon to feed into the generation of the convex hull, the points have to be in such an order so there are no crossing lines and the polygon closes itself, when creating a polygon.
I have since been given the suggestion of using my ponits as input to making a linestring geometry, and then using this linestring geometry as input to creating a convex hull.
Hope this explains my thought process. Thanks for your input.
David
null

GeoRaster in the Enterprise - tips?

Next week I will start a pilot project loading mid to high resolution (0.5M to 0.1M) orthophotos for about 200 sites around 13000 hectares (50 Sq Mi) each. The sites are for the most part not contiguous, but the data is global. The source format is mostly MrSID, although for about 20% of the sites, Tiff or PNG formats are available, with a few ecw's as well. I plan to unproject and store the photo data in 8307 (lat/lon) format, as that is what our application uses for our native format, and to allow global coverage.
The data will be used in three ways:
First, it will be retrieved in defined tile sizes and scales for a home-gown Java rich-client application so that tiles can be saved to the client's disk to minimize repetitive bandwidth requirements. For areas not covered by these orthos, MS VE tiles will be used.
Second, it will be exposed for others to use as a WMS service.
Third, as a source for "export" into other formats on an on-demand process.
We are using 64-bit Oracle 10gR2 on Solaris x86 with NetApp filers on the db end, and 64-bit Windows servers on the app end, all on a GBE network. I have both FME 2007 and Manifold v8 available for data conversion functions. For data serving, GeoServer and FME (for option three) are planned as we already use GeoServer successfully for WFS duties.
I am looking for suggestions / tips from anyone on how best to load and store the imagery, and then optimize the retrieval of it. I've read the GeoRaster user guide (and starting reading the 11g one) and the book.
I am particularity interested in what to do when you do have overlapping images (two sites that overlap). Also, how to best load a site when the site is not one image, but made up of tiles.
For software, say, if Mapviewer has proven faster for WMS than GeoServer for you, I'm willing to listen.
Thanks in advance,
Bryan

1. yes, (256,256,1) or (256,256,3) shall work fine. in this case, your focus is on displaying or retrieval, it's better to make sure (1) the images are stored using the same block size, ie, (256,256,1) or (256,256,3) and (2) when you retrieve the tiles control your query window to cover exactly the area of the tiles (ie, avoiding internal mosaicking and cropping).
2. yes, in a regular tablespace, if you have a LOT of image data and concurrent multi-users, the more data files the better. you can make tens of them. when dealing with geoimages, ten data files is probably minimum. but you might also want to consider Oracle BIG TABLESPACE, in which only one data file (could be in terabytes) is allowed. we didn't do much tests on it. but seems the performance is very good.
3. i think it all depends. seems your major purpose is to quickly retrieve and display the images, pan thru and zoom in/out smoothly across many images and around the globe. if so, i agree you'd better do some preprocessing so that the data have the same resolution and pyramids. to do this, scaleCopy can be considered.
hope this helps a bit.
jeffrey

Select data with SDO_RELATE in lat long coordinate system(8307) in 10gR2

Hi all,
I have problem with selecting data from table.
Data are in lat lon coordinate system 8307.
These requests don't return any data:
SELECT ISSUE_ID FROM MAP_ISSUES WHERE SDO_FILTER(GEOMETRY, sdo_geometry (2003, 8307, null, sdo_elem_info_array (1,1003,1),sdo_ordinate_array(-180,-90, 180,-90, 180,90, -180,90, -180,-90)) ) = 'TRUE';
SELECT ISSUE_ID FROM MAP_ISSUES WHERE SDO_RELATE(GEOMETRY, sdo_geometry (2003, 8307, null, sdo_elem_info_array (1,1003,1),sdo_ordinate_array(-180,-90, 180,-90, 180,90, -180,90, -180,-90)), 'MASK=ANYINTERACT' ) = 'TRUE'
Optimized polygon does return all data correctly:
SELECT ISSUE_ID FROM MAP_ISSUES WHERE SDO_FILTER(GEOMETRY, sdo_geometry (2003, 8307, null, sdo_elem_info_array (1,1003,3),sdo_ordinate_array (-180,-90,180,90)) ) = 'TRUE'
Smaller polygon select data correctly too.
SELECT ISSUE_ID FROM MAP_ISSUES WHERE SDO_FILTER(GEOMETRY, sdo_geometry (2003, 8307, null, sdo_elem_info_array (1,1003,1),sdo_ordinate_array (52,-7, 54,-7 , 54,-5 , 52,-5, 52,-7)) ) = 'TRUE'
I have tried changed polygon to be clockwise, counter clockwise, make the area a bit smaller( 160 instead of 180, 89 instead of 90) nothing has helped.
My explanation than was, that Earth is sphere and each defined polygon defines TWO polygons in the sphere and there is convention that the smaller is chosen to select data. It would make sense along the previous results, but than I found one post which says that this is bug http://www.frontoracle.com/oracle-database/703/180703-size-of-are-of-interest-smaller-equals.html
I have found in other thread that max only 1/2 of Earth could be selected Different results using SDO_RELATE with polygon and rectangle type but it seems not true, because optimized bounding box works fine!
What is right? Is there anything in official documentation?
Is it bug.
Max 1/2 of Earth could be selected in one request.
Each polygon defines two areas in the Earth and the smaller one is used to do spatial SDO_RELATE operation?
Thanks!
Regards,
Zdenek

Zdenek,
A bug, or limititation, whichever you choose. IMHO if you ask for something, and don't get what you expect, it is a bug that could be fixed.
But for 10g anywho, the following applies, which is why I choose 120 degree breaks for my code as it is less than 180...
The following size limits apply with geodetic data:
■ No polygon element can have an area larger than one-half the surface of the Earth.
■ In a line, the distance between two adjacent coordinates cannot be greater than or
equal to one-half the perimeter (a great circle) of the Earth.
If you need to work with larger elements, first break these elements into multiple
smaller elements and work with them. For example, you cannot create a geometry
representing the entire ocean surface of the Earth; however, you can create multiple
geometries, each representing part of the overall ocean surface. To work with a line
string that is greater than or equal to one-half the perimeter of the Earth, you can add
one or more intermediate points on the line so that all adjacent coordinates are less
than one-half the perimeter of the Earth.
Bryan

Lat/Lon Format

Similar Messages

Maybe you are looking for