Leave transaction

Question

Hello everyone
I have problem like this: From transaction TR1 I call another transaction TR2.I don' t want to call transaction TR2 with her first screen ,but with hers third screen. This is the code:
DATA: BDCDATA TYPE TABLE OF BDCDATA.
      DATA: PROGRAM LIKE SY-REPID,
      WA_BDCDATA TYPE BDCDATA,
      WA_BDCDATA1 TYPE BDCDATA.
      CLEAR WA_BDCDATA.
      WA_bdcdata-program = 'ZREKLAMACJE'.
      WA_bdcdata-dynpro = '0100'.
      WA_bdcdata-dynbegin = 'X'.
      APPEND WA_BDCDATA TO BDCDATA.
      CLEAR WA_BDCDATA.
      WA_BDCDATA-FNAM = 'BDC_CURSOR'.
      WA_BDCDATA-FVAL = 'T1'.
      APPEND WA_BDCDATA TO BDCDATA.
      CLEAR WA_BDCDATA.
      WA_BDCDATA-FNAM = 'BDC_OKCODE'.
      WA_BDCDATA-FVAL = 'ANALIZA'.
      APPEND WA_BDCDATA TO BDCDATA.
      set parameter id 'num_wew' field NUMER_ZNAKOWY-ROWTYPE.
      set parameter id 'kod_transakcji' field sy-tcode.
      call transaction 'ZREKLAMACJA_ZEW' USING BDCDATA MODE 'E'.
The transacton TR2 is working, but how can I end transaction TR1. When I'm using leave program, when second transaction ends, everything goes back to the first transaction TR1.
Please help .
Thank you.

Answer 1

Hi
It depends on how the second transaction is called, you should consider a batchinput simulation ends when a commit is triggered, a statament like CALL TRANSACTION triggers automatically the commit.
So you should change the program in ordert to change the way to call the transaction TR2:
- try to use LEAVE TRANSACTION instead of CALL TRANSACTION;
- or create a dialog for TR2
Max