Link of table ANLC with ANLA

Question

Hello experts,
I am trying to get the latest values from anlc where its ANLN1, ANLN2 and BUKRS is equal to ANLA of the same fields and ANLA-DEAKT IS INITIAL.
Here is a scenario(when I checked in SE16):
Table ANLA - one entry found
BUKRS = 'ABC'
ANLN1 = 651825
ANLN2 = 0
DEAKT = 00/00/0000
Table ANLC - multiple entries found
BUKRS = 'ABC'
ANLN1 = 651825
ANLN2 = 0
GJAHR = from year 1999 to 2006
Now, This has been bugging me for the longest time. How can I get the latest record in ANLC(so in this case, it is the record with a gjahr of 2006) based from ANLA where its DEAKT is '00/00/0000'?

Answer 1

assuming you've read the anla already.......
select * from anlc up to 1 rows
where bukrs = anla-bukrs    
and anln1 = anla-anln1      
and anln2 = anla-anln2      
order by gjahr descending   
endselect.
But you could change the anla select to a join,
select * from anla
join anlc on anlcbukrs = anlabukrs
and anlcanln1 = anlaanln1
and anlcanln2 = anlaanln2 up to 1 rows
into corresponding fields of table your_table
order by gjahr descending   
endselect.
delete adjacent duplicates FROM YOUR_TABLE comparing bukrs anln1 anln2.
or you could just read anlc entries into a table,
select * from anlc
INTO CORRRESPONDING FIELDS OF TABLE OF T_ANLC
where bukrs = anla-bukrs
and anln1 = anla-anln1
and anln2 = anla-anln2
SORT T_ANLC BY GJAHR DESCENDING.
delete adjacent duplicates FROM T_ANLC comparing bukrs anln1 anln2.