Looking for a formula to calculate difference between two values

So, heres my problem...
I have a set of incremental values which act as thresholds, 100, 200, 300, so on. Another number is independent and correlates to that set of values, say 148.
I want another cell which calculates the difference between 148 and 200, but then recognises that when 148 goes over 200 that the next threshold has been met, so then resets and starts calculating the difference between that new number and the next threshold,
300.
Is it possible to do this all in the same cell?
Thanks in advance.

Re: variable number difference
With the independent number in cell F8, maybe...
=IF(MOD(F8,100)=0,0,100-MOD(F8,100))
Jim Cone
free & commercial excel programs (n/a xl2013)
https://jumpshare.com/b/O5FC6LaBQ6U3UPXjOmX2

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Calculate difference between two dates/times

Hi all,
Is there any function module to calculate difference between two dates/times which are in TIMESTAMPL format.
I need to know how many millisconde(second,minutes, hours... )there is between these two times.
Please, It is urgent
Thank you all.
Karim

hi,
try the following function
CALL FUNCTION 'CCU_TIMESTAMP_DIFFERENCE'
      EXPORTING
           timestamp1 = timestamp1
           timestamp2 = timestamp2
      IMPORTING
           difference = diff
      EXCEPTIONS
           OTHERS     = 1.
the above function gives the difference in seconds...
try the following code to set the resolution to milliseconds..
SET RUN TIME CLOCK RESOLUTION LOW
check the thread for details:
SET RUN TIME CLOCK RESOLUTION?
all the best!!!
Regards,
Aparna

Problem with calculate difference between two dates on monday to saturday

Hello,
I need some help to edit a function tu return number of hours between to dates, including saturdays (09:00 - 14:00) and monday to friday (09:00-21:00);
This is my code;
CREATE OR REPLACE
FUNCTION TEST2( FECHA_INICIO DATE, FECHA_FIN DATE)
    RETURN NUMBER IS HORASTOTALES NUMBER;
    fecha date;
    BEGIN
    if(
      SELECT fecha, to_char(fecha, 'DY', 'NLS_DATE_LANGUAGE=ENGLISH') Dia
    FROM (SELECT to_date('FECHA_INICIO') + LEVEL - 1 fecha
           FROM DUAL
        CONNECT BY LEVEL <= (FECHA_FIN - FECHA_INICIO))
WHERE TO_CHAR(FECHA, 'DY', 'NLS_DATE_LANGUAGE=ENGLISH') not IN ('SAT') THEN
        with t as (
        SELECT CASE LEVEL
                             when 1 then greatest(fecha_inicio,trunc(fecha_inicio) + 9 / 24)
                             else trunc(fecha_inicio) + level - 15 / 24
                           end fecha_inicio,
                           case connect_by_isleaf
                             when 1 then least(fecha_fin,trunc(fecha_fin) + 21 / 24)
                             else trunc(fecha_inicio) + level - 3 / 24
                           end fecha_fin
                     from dual
                     connect by level <= trunc(fecha_fin) - trunc(fecha_inicio) + 1 )
        select sum(greatest(fecha_fin - fecha_inicio,0)) * 24 horas
          into horastotales
          FROM T
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END;
regards

Ok, let's try this one then. it works as a function, and if you extract the query, it can work as a single cursor too.
create or replace function test2( p_start_date date, p_end_date date) return number
is
   t_result number;
begin
   with firstday as ( select case to_char(p_start_date,'fmdy','NLS_DATE_LANGUAGE=ENGLISH')
                            when 'sun' then 0
                            when 'sat' then 9-least(14,to_char(p_start_date,'hh24'))
                            else 9-least(21,to_char(p_start_date,'hh24'))
                         end day
                    from dual ),
        alldays as (select sum(case to_number(to_char(p_start_date+level-1,'d'))
                                   when 1 then 0
                                   when 7 then 5
                                   else 12
                                end) days
                       from dual
                     connect by level <= p_end_date - p_start_date + 1),
         lastday as ( select case to_char(p_end_date,'fmdy','NLS_DATE_LANGUAGE=ENGLISH')
                            when 'sun' then 0
                            when 'sat' then -14+least(14,to_char(p_end_date,'hh24'))
                            else -21+least(21,to_char(p_end_date,'hh24'))
                         end day
                    from dual )
   select sum(t1.day+t2.days+t3.day)
     into t_result
     from firstday t1
        , alldays t2
        , lastday t3;
   return t_result;
end;

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rome berlin true
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toronto chicago true
florence
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You should be able to use COUNTIF where the range is th first column and the condition is the word in the second column. If the result is greater than zero then the word is in both columns.

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I have two questions need to be clarified.
Question 1: I have KPI named Revenue growth and the formula to calculate is (current year revenue - previous year revenue).I am using data entry& approval.Is that technically possible to calculate the revenue difference between two periods in SSM?
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Bala

Hi:
Question 1:
We have same problem, and what we did is to create:
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Question 2:
I don't know.
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Hi,
We need to calculate the difference between the two dates by excluding the Local public holidays (It is global and varies across countries) and weekends should not be included in calculation for a business day in OBIEE.
We have two dates: Open date and close date when ever close date is null we are calculating age based on taking the current timestamp and need to exclude the weekends and Holidays when ever the close date is null.
Ex:
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Thanks
Edited by: user10441472 on Nov 22, 2010 3:14 PM

You already asked this question and I answered it...
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Need Help to calculate difference between times

Hello everyone,
I have two fields which just stores the time in 24 hour format ex: 08:00 and 20:00 now I want to calculate difference between the two times
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Thanks
Ravi

Are your fields of varchar2 datatype or...?
Is 08:00 the start time or 20:00?
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See:
http://asktom.oracle.com/pls/asktom/ASKTOM.download_file?p_file=6551242712657900129
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2 select '08:00' btime, '20:00' etime from dual
3 )
4 --
5 -- actual query:
6 --
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1 row selected.
SQL>

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Denes,
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p_date_1   VARCHAR2,
p_date_2   VARCHAR2
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v_difference   NUMBER;
v_sql_err      VARCHAR2 (4000);
BEGIN
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CEPTION
WHEN OTHERS
THEN
v_sql_err := SQLERRM || CHR (10) || CHR (10) ||
SQLCODE;
ND calc_date_difference;and
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2    FROM DUAL;
DIFF
3
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Interval dif;
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My first time here and really new to programming. I would like to get the difference between 2 columns that are inside
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PeriodNumber
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Dim Shared Num1 As Integer
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Public Function GetAmount(Amount as Integer, Type as String)
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If you have any questions, please feel free to ask.
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Katherine Xiong
Katherine Xiong
TechNet Community Support

Looking for a formula to calculate difference between two values

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