Loop through xsd tag in BPEL

Question

I have a XSD with 10 line items and based on a condition I need to filter out the Line Items.. Once the line items are filtered out, then only it should go to the next level of logic.
Shall I use "While" process activity? Will it go through all the line items and then go to the next node or it will check just one line item, check the condition and go to the next node.
Please suggest asap.

Answer 1

Hi Anne,
Thanks for the response. I have actaully built the XPATH, please verify it ..
This is the XML I have:
<?xml version="1.0" encoding="UTF-8"?>
<PO>
<doc_type>New</doc_type>
<order_no>12345</order_no>
<PODetaill>
<item>String</item>
<physical_location_type>A</physical_location_type>
<physical_location>1234567899</physical_location>
<unit_cost>3</unit_cost>
<origin_country_id>01</origin_country_id>
<latest_ship_date>
<ribdate:year>0</ribdate:year>
<ribdate:month>0</ribdate:month>
<ribdate:day>0</ribdate:day>
<ribdate:hour>0</ribdate:hour>
<ribdate:minute>0</ribdate:minute>
<ribdate:second>0</ribdate:second>
</latest_ship_date>
<pickup_loc>NC</pickup_loc>
<pickup_no>123</pickup_no>
<cost_source>S</cost_source>
</PODetail>
</PO>
Filtering Condition:
Items with PODetail.Physical_location_type ='A' should be processed further, others should be filtered out.
Remove operation with modified XPATH :
<bpelx:remove>
<bpelx:target variable="inputvariable" part="payload"
query="/ns1:PO/ns1:physical_location_type !='A'" />
</bpelx:remove>
Please let me know if I am doing the right thing..
Thanks..