Losing Line-feed in XML parsing (XMLTRANSFORM) or File output (clob2file)?

Question

Hi all, need some help please!
I'm using a xslt file to transferm a XML file into a txt format file. Within the XSLT file, there is a carriage-return (<xsl:text>
</xsl:text>) (it disappeared already, here is what i'm using "#xD" or "#xA", have to take the '&' and ';' away), but the final output txt file seems to lose this carriage-return/line-feed information. The output data became one-line.
Here are the steps I've used:
1. lv_xml_data = XMLTRANSFORM (a.xml_data, b.f_xslt)
=> output data into XMLTYPE;
2. using XMLTYPE.getclobval to get the output data into CLOB format.
lv_output_clob := XMLTYPE.getclobval (lv_xml_data);
3. using encoding:
lv_output_clob :=
DBMS_XMLGEN.CONVERT (lv_output_clob, DBMS_XMLGEN.entity_decode);
4. using clob2file write to a file with txt format.
DBMS_XSLPROCESSOR.clob2file (lv_output_clob,
lv_output_dir,
lv_filename,
NLS_CHARSET_ID ('UTF8')
Been struggling with these a few days already. Any help is appreciated. I would really like to get some input to see what might cause the carriage-return/line-feed characters lost.
Thanks in advance!
-Jane
Edited by: user9084567 on Feb 1, 2010 1:45 PM
Edited by: user9084567 on Feb 1, 2010 1:47 PM
Edited by: user9084567 on Feb 1, 2010 1:48 PM

Answer 1

A_non,
After a few testing, I can identify the CRLF was lost in XMLTRANSFORM. I had read your other thread related to this, and try to run this sample code:
/* Formatted on 2010/02/03 15:32 (Formatter Plus v4.8.8) */
DECLARE --Local variables here
v_xml XMLTYPE
:= XMLTYPE
('<
offers xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="xsd.xsd"><
submit type="DAM" date="2007-03-28" name="MKTPART1" mode="NORMAL"/><
offer name="Jamestown" flag="true" version_no="1.0"><
standing date="2007-03-29" type="WED"/><
identifier external_id="523736560"/><
/offer><
/offers>'
v_xslt XMLTYPE
:= XMLTYPE
('<
xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <
xsl:output method="text"/> <
xsl:variable name="new_line" select="''&#xA;''" /> <
xsl:template match="/"> <
xsl:value-of select="/offers/offer/...name"/><
xsl:value-of select="$new_line" /><
xsl:value-of select="/offers/submit/...date"/><
xsl:value-of select="$new_line" /><
xsl:value-of select="/offers/offer/standing/...date"/><
xsl:value-of select="$new_line" /><
xsl:value-of select="/offers/offer/standing/...type"/><
xsl:value-of select="$new_line" /><
/xsl:template><
/xsl:stylesheet>'
BEGIN -- Test statements here
DBMS_OUTPUT.put_line (XMLTYPE.transform (v_xml, v_xslt).getstringval ());
END;
But come out these error:
Error at line 2
ORA-31011: XML parsing failed
ORA-19202: Error occurred in XML processing
LPX-00230: invalid character 10 (U+000A) found in a Name or Nmtoken
Error at line 4
ORA-06512: at "SYS.XMLTYPE", line 310
ORA-06512: at line 2
Can not figure out why. Try to use this <xsl:variable name="new_line" select="''& # x A ;''" /> inside my style sheet, but it seems not taking it. Not too sure what's exactly should be the quotes for "''& # x A ;''" (w/o space). If I used doub quote + two single quotes, it returns error, LPX-00601: Invalid token in: ' '; if I used single quote + double quote, it did not bring in CRLF at all.
Any input?
Thanks in advance.