Max users for a chatroom seems to be 30?

Running 10.5.8, iChat Server. I have a chatroom that seems to max out at 28-30 users. I tried creating a "persistent room" using a jabber script, but it still seems to max out at 30 users even though I specified 100. Is there any way to modify this? Surfing config data for jabberd2 seems to be pretty sparse on info for this, same with the documents for muc.

My searches behave a little differently. Maybe this will be helpful.
I have some messages from numeric sources. Say one of them is 12345678. I find that if I search for "1234", I can find the message, even though 12345678 never appears in the body of the text. But if I search for some string not at the beginning of the message, like "4567" or "5678", I cannot find it.
So the conclusion seems to be search for a string at the start of the name.

Similar Messages

Max users for a AIR-LAP1142-A-K9

I work at a small University where are are moving from a hitspot infrastructure (just provide wireless access) to dense user support model in order to use wireless during classrrom instruction. It have a request to provide wirless coverage in a classroom for up to 30 users. I have installed a Lap-1142 in the hall just overisde of the classroom last semister which provided wireless access for about 12 students. The class enrollment has grown and now will need to support up to 30 users. I just install a C3560G-POE to provide 1GB uplink for the switch. The instructed stated she will require students to download pdf files and some streaming media during class and I was asked if the wireless will be able to support this requirement.
I am not sure how many concurrent users a LAP-1142 can support and if it can can it support streaming media for 30 users. How would I go about testing this senairio? How can one test AP throughput? How do I ensure it will work during class with having to place another AP within the classroom?
Thank you for your help.
Mike

Where could I located Cisco's 25 user limit recommendation
If you have an autonomous AP, then there's no need to worry. It's just a rule-of-thumb. If it's controller-based then it's:
Wireless > 802.11a/n (or 802.11b/g/n) > General and look at "Clients (1 to 75)".

Changed Ulimits values for the Oracle user and getting error -bash: ulimit: max user processes: cannot modify limit: Operation not permitted when logging in.

I'm trying to increate the ulimits for max user processes and open files for the oracle user. I've set the values in limits.conf, /etc/profile and in oracle's environment scripts. Now when I log in as oracle I get the below errors. If I change the ulimits back to the original values errors go away but ulimits aren't changed.
login as: oracle
[email protected]'s password:
Last login: Fri Mar 6 09:56:02 2015 from mtkadmin12
You are logging onto an Oracle system.
Kickstarted on: 2014-06-05
-bash: ulimit: max user processes: cannot modify limit: Operation not permitted
-bash: ulimit: max user processes: cannot modify limit: Operation not permitted
[oracle@servername ~]$

Thanks for the update.
I modified the /etc/security/limits.d/90-nproc.conf and added a line for oracle and also modifed the oracle.sh file. The ulimits are setting correctly when I su - oracle but they are still wrong when sshing in as oracle.
[root@mtkdevorap11d-1 ~]# su - oracle
[oracle@mtkdevorap11d-1 ~]$ ulimit -Ha
core file size          (blocks, -c) unlimited
data seg size           (kbytes, -d) unlimited
scheduling priority             (-e) 0
file size               (blocks, -f) unlimited
pending signals                 (-i) 1030982
max locked memory       (kbytes, -l) 94371840
max memory size         (kbytes, -m) unlimited
open files                      (-n) 65536
pipe size            (512 bytes, -p) 8
POSIX message queues     (bytes, -q) 819200
real-time priority              (-r) 0
stack size              (kbytes, -s) unlimited
cpu time               (seconds, -t) unlimited
max user processes              (-u) 16384
virtual memory          (kbytes, -v) unlimited
file locks                      (-x) unlimited
[oracle@mtkdevorap11d-1 ~]$
[oracle@mtkdevorap11d-2 ~]$ ssh mtkdevorap11d-1
Last login: Mon Mar 16 13:04:16 2015 from mtkdevorap11d-2.conveydev.com
You are logging onto an Oracle system.
Kickstarted on: 2014-06-05
[oracle@mtkdevorap11d-1 ~]$ ulimit -Ha
core file size          (blocks, -c) unlimited
data seg size           (kbytes, -d) unlimited
scheduling priority             (-e) 0
file size               (blocks, -f) unlimited
pending signals                 (-i) 1030982
max locked memory       (kbytes, -l) 64
max memory size         (kbytes, -m) unlimited
open files                      (-n) 4096
pipe size            (512 bytes, -p) 8
POSIX message queues     (bytes, -q) 819200
real-time priority              (-r) 0
stack size              (kbytes, -s) unlimited
cpu time               (seconds, -t) unlimited
max user processes              (-u) 16384
virtual memory          (kbytes, -v) unlimited
file locks                      (-x) unlimited
[oracle@mtkdevorap11d-1 ~]$

Implementing max user sessions settings for TACACS with ACS 5.3

I'm a little confused about the configuration of max user sessions for device administration with TACACS.
When I've changed the configutration of unlimited sessions for a value in Access Policies > Max User Session Policy > Max Session User Settings
I think this value could limit the maximum number of sessions for each user, but instead this value limit in a global meaning all of my sessions.
For example: I need to limit the session for my users in 2.
user1 = Max 2 sessions
user2 = Max 2 sessions
user3 = Max 2 sessions
Whe i Put the value of 2 in Max Session User Settings
user1 + user2 + user3 = Max 2 sessions
This is a limitation of ACS 5.3 or my configuration needs something aditional.

Luis,
Are you saying that when you authenticate with user1 and user 2 that user3 isnt able to get access?
Do you have tacacs accounting enabled on the network access device?
Also what do you have configured for the group settings? If there is a maximum group setting and all the users are a member of the same group then the lesser of the two will be enforced. So if the group max sessions is set to 1 then the all users in that group will have a max session of 1.
Here is some reference material.
http://www.cisco.com/en/US/docs/net_mgmt/cisco_secure_access_control_system/5.3/user/guide/access_policies.html#wp1162177
Thanks,
Tarik Admani

Selecting max date for specific 'operation' code

I have the following scenario: a history table that keeps track of the 'operation' and the date of the operation. For example, the operation field can have a code of U (for update), C (for closed), O (for re-opened), A (for approved), etc.
The goal of this history table is to keep track of all of the modifications made. Hence, a particular record of interest can have more than one 'U' operation documented, C operation, etc.
How can I choose the max date for each operation.
I was diong the following in my PL/SQL:
BEGIN
SELECT operation_code, o_date, user INTO lv_operation_code, lv_date, lv_user FROM table1 WHERE unique_id = pv_id AND operation_code = U' AND o_date = (SELECT max(o_date) FROM table1 WHERE unique_code = pv_id);
EXCEPTION
WHEN NO_DATA_FOUND THEN NULL;
END;
I then have another begin statement for the 'C' operation, etc.

Hi,
OraclePolzovatel wrote:
... I was diong the following in my PL/SQL:
BEGIN
SELECT operation_code, o_date, user INTO lv_operation_code, lv_date, lv_user FROM table1 WHERE unique_id = pv_id AND operation_code = U' AND o_date = (SELECT max(o_date) FROM table1 WHERE unique_code = pv_id);
EXCEPTION
WHEN NO_DATA_FOUND THEN NULL;
END;
I then have another begin statement for the 'C' operation, etc.Are you sure that's what you're doing? There seem to be errors, such as unmatched quotes.
Instead of doing a single SELECT with something like "operation_code = 'U'" in the WHERE-clause, you could write a cursor with "GROUP BY operation_code".

Query to find out the time used by an user for an application

Hello All,
I want to know the query to find out the whole time used by the user for an application. Please view the below data
Employee:
SNO EMP_ID EMP_NAME EMP_DATE LOGIN_TIME LOGOUT_TIME
1 10 Visu 21-Nov-2010 06:30:00 07:30:00
2 10 Visu 21-Nov-2010 06:40:00 07:20:00
3 10 Visu 21-Nov-2010 06:50:00 07:50:00
4 10 Visu 21-Nov-2010 07:30:00 08:30:00
5 10 Visu 21-Nov-2010 09:30:00 10:30:00
By checking the above data we can say that the total time Visu used the application is
8.30 - 6.30 (From 1,2,3,4 records) = 2hrs
10.30 - 9.30 (Based on 5th rec) = 1hr
So the total time Visu used the application would be 3 hrs = 180 mins.
Could you please help me in getting the result from that data using a query?

odie_63 wrote:
I think it may be solved with analytics too.
with t1 as (
            select 1 sno,10 emp_id,'Visu' emp_name,'21-Nov-2010' emp_date,'06:30:00' login_time,'07:30:00' logout_time from dual union all
            select 2,10,'Visu','21-Nov-2010','06:40:00','07:20:00' from dual union all
            select 3,10,'Visu','21-Nov-2010','06:50:00','07:50:00' from dual union all
            select 4,10,'Visu','21-Nov-2010','07:30:00','08:30:00' from dual union all
            select 5,10,'Visu','21-Nov-2010','09:30:00','10:30:00' from dual
     t2 as (
            select emp_id,
                    emp_name,
                    emp_date,
                    to_date(emp_date || login_time,'DD-MON-YYYYHH24:MI:SS') login_time,
                    to_date(emp_date || logout_time,'DD-MON-YYYYHH24:MI:SS') logout_time
              from t1
     t3 as (
            select t2.*,
                    case
                      when login_time < max(logout_time) over(
                                                              partition by emp_id,emp_date
                                                              order by login_time
                                                              rows between unbounded preceding
                                                                       and 1 preceding
                        then 0
                      else 1
                    end start_of_group
              from t2
     t4 as (
            select t3.*,
                    sum(start_of_group) over(partition by emp_id,emp_date order by login_time) grp
              from t3
     t5 as (
            select emp_id,
                    emp_date,
                    min(login_time) login_time,
                    max(logout_time) logout_time
              from t4
              group by emp_id,
                       emp_date,
                       grp
select emp_id,
        numtodsinterval(sum(logout_time - login_time),'day') time_spent
from t5
group by emp_id
order by emp_id
    EMP_ID TIME_SPENT
        10 +000000000 03:00:00.000000000
SQL> SY.

What's the semantic of "max user processes" (ulimit)

Hello everyone,
I don't understand the behaviour of ulimit, have a look at this shell dump:
$ ps hax | wc -l
120
$ ps h -u myUsername | wc -l
35
$ ulimit -Su 78
$ ps h -u myUsername | wc -l
bash: fork: retry: No child processes
bash: fork: retry: No child processes
bash: fork: retry: No child processes
bash: fork: retry: No child processes
bash: fork: Resource temporarily unavailable
$ ulimit -Su 80
$ ps h -u myUsername | wc -l
35
$
If I am currently running 35 processes, one would assume that >35 more should be sufficient to start two more processes - but obviously it isn't.
In this case, I needed at least "ulimit -Su 80" to start ps and wc.
If I set the "max user processes" limit to 79, the first four error messages change from "bash: fork: retry: No child processes" to "bash: fork: retry: Resource temporarily unavailable"
Can somebody explain this bevahiour to me, please? Why am I not allowed to create new processes, although the limits should be sufficient?

Apologies for the necro-bump but I hope this will help others.
ulimit -u does not give you the max number of processes rather it displays the max number of threads. To list the number of threads a user is currently using:
ps -L -u myusername | wc -l
The output from the above two commands can now be compared and allow you to set the appropriate ulimit.

How to increas the max user process number in Solaris 11?

Hey
Could anyone told me how to increas the max user process number in Solaris 11? I tried below as described in https://blogs.oracle.com/hasham/entry/solaris_10_increasing_number_of , but it cannot work.
set pidmax=60000
set maxusers = 4096
set maxuprc = 50000
set max_nprocs = 50000
Thanks!
Edited by: 966272 on Oct 18, 2012 7:38 AM

Perhaps you should work your original forum post:
Oracle 11g installation fail on Solaris 11 64bit - ORA-00443
through to a resolution before you complicate things that likely don't apply.
You make an assumption in that other post about exceeding various maximums. That may be true or it may not be true. Since the installation of a database program seems to be your actual expectation, go work that forum thread instead.

Demo users for BPM in Oracle BPM Suite 11.1.1.4 (Patchset 3)

Hello,
In the previous release a utility was made available to insert demo users for BPM (demo-community.zip)
See also
http://blogs.oracle.com/middleware/2010/07/installing_seeded_users_for_bpm_11113_on_linux.html
Could I (re)use this utility in order to test BPM with an existing security schema? Or will a changed utility be made available for BPM 11.1.1.4 (PS3)?
Regards Léon

I used this on 11.1.1.4, running the ant script and using a customized input file ( -Dinput.file=... ) and it seemed to work fine.

Error: "The user for which we are checking a privilege should be in the same org as the context provided"

Hi All,
Recently, we've encountered some weird error for some users when trying to assign records to them through both the CRM UI and CRM SDK Call.
The error message saying: "The user for which we are checking a privilege should be in the same org as the context provided".
Here is the trace log for assigning a lead for one of those users (same error for other records):
[2010-08-09 13:58:06.0] Process: w3wp |Organization:d905ae4d-8d9f-df11-a1b0-00237df0351e |Thread: 22 |Category: Exception |User: fb56b107-949f-df11-a1b0-00237df0351e |Level: Error | CrmArgumentException..ctor
at CrmArgumentException..ctor(String message)
at SecurityLibrary.TryCheckPrivilege(Guid user, Guid privilege, ExecutionContext context)
at SecurityLibrary.CheckPrivilege(Guid user, Guid privilege, ExecutionContext context)
at SecurityLibrary.CheckPrivilege(Guid user, EntityMetadata metadata, PrivilegeType type, ExecutionContext context)
at CascadeEngine.AssignDB(BusinessEntityMoniker moniker, SecurityPrincipal assignee, ExecutionContext context)
at RuntimeMethodHandle._InvokeMethodFast(Object target, Object[] arguments, SignatureStruct& sig, MethodAttributes methodAttributes, RuntimeTypeHandle typeOwner)
at RuntimeMethodInfo.Invoke(Object obj, BindingFlags invokeAttr, Binder binder, Object[] parameters, CultureInfo culture, Boolean skipVisibilityChecks)
at RuntimeMethodInfo.Invoke(Object obj, BindingFlags invokeAttr, Binder binder, Object[] parameters, CultureInfo culture)
at LogicalMethodInfo.Invoke(Object target, Object[] values)
at InternalOperationPlugin.Execute(IPluginExecutionContext context)
at PluginStep.Execute(PipelineExecutionContext context)
at Pipeline.Execute(PipelineExecutionContext context)
at MessageProcessor.Execute(PipelineExecutionContext context)
at InternalMessageDispatcher.Execute(PipelineExecutionContext context)
at ExternalMessageDispatcher.Execute(String messageName, Int32 primaryObjectTypeCode, Int32 secondaryObjectTypeCode, PropertyBag fields, CorrelationToken correlationToken, CallerOriginToken originToken, UserAuth userAuth, Guid callerId)
at RequestBase.Process(Int32 primaryObjectTypeCode, Int32 secondaryObjectTypeCode, CorrelationToken correlationToken, CallerOriginToken originToken, UserAuth userAuth, Guid callerId)
at RequestBase.Process(CorrelationToken correlationToken, CallerOriginToken originToken, UserAuth userAuth, Guid callerId)
at CrmServiceInternal.Execute(RequestBase request, CorrelationToken correlationToken, CallerOriginToken originToken, UserAuth userAuth, Guid callerId)
at InProcessCrmService.Execute(Object request)
at PlatformCommand.ExecuteInternal()
at AssignRouteOnCreateUpdateListener.AssignEntity(Entity entity, LookupValue owner)
at CommunicationListener.HandlePostEvent(PlatformCommand command, Response response)
at PlatformCommand.ExecuteInternal()
at UpdateCommand.Execute()
at EntityProxy.Update(Boolean performDuplicateCheck)
at AppForm.HandleFormEventAssign(Boolean gridRefreshCallbackAdded)
at AppForm.RaiseDataEvent(FormEventId eventId)
at EndUserForm.Initialize(Entity entity)
at CustomizableForm.Execute(Entity entity, String formType)
at LeadDetailPage.ConfigureForm()
at AppUIPage.OnPreRender(EventArgs e)
at Control.PreRenderRecursiveInternal()
at Page.ProcessRequestMain(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint)
at Page.ProcessRequest(Boolean includeStagesBeforeAsyncPoint, Boolean includeStagesAfterAsyncPoint)
at Page.ProcessRequest()
at Page.ProcessRequest(HttpContext context)
at sfa_leads_edit_aspx.ProcessRequest(HttpContext context)
at CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute()
at HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously)
at ApplicationStepManager.ResumeSteps(Exception error)
at HttpApplication.System.Web.IHttpAsyncHandler.BeginProcessRequest(HttpContext context, AsyncCallback cb, Object extraData)
at HttpRuntime.ProcessRequestInternal(HttpWorkerRequest wr)
at HttpRuntime.ProcessRequestNoDemand(HttpWorkerRequest wr)
at ISAPIRuntime.ProcessRequest(IntPtr ecb, Int32 iWRType)
>Crm Exception: Message: The user for which we are checking a privilege should be in the same org as the context provided, ErrorCode: -2147220989, InnerException: System.ArgumentException: The user for which we are checking a privilege should be in the same
org as the context provided
I checked the user id and the organization id, and there are both correct (in the database). The user id "fb56b107-949f-df11-a1b0-00237df0351e " is actually the internal CRM System User.
What could the issue be?
Can anyone help, please. Thanks

Are you sure, the User which you are assigning is in the same organisaion. It seems that the Orgname which you are specifying is not correct. and the web service is pointing to other user which is not the current ms crm organisaion.
Could you please paste your code here for more details.?
Thanks, Ranjitsingh R | http://mscrm-developer.blogspot.com/ | MS CRM Consultant

I have been a Quicken user for many years but have heard that the move to Yosemite is a Quicken nightmare - so I'm trying to research new software. I'm overwhelmed by the number of available programs, all the things that each program can do and perp

I have been a Quicken user for many years but have heard that the move to Yosemite is a Quicken nightmare - so I'm trying to research new software. I'm overwhelmed by the number of available programs, all the things that each program can do and perplexed by the arguments for and against each feature in each program.
My needs are relatively simple for my small business: 1) I need to be able to import years worth of Quicken data into the new program 2) I need to easily print checks 3) I need to easily reconcile my checking account each month and 4) I need to generate basic reports for my accountant (e.g. P & L statements, category summaries).
I have been a FileMaker user since 1.0 so I don't need (or want) A/R, A/P, inventory management, invoicing, etc.
I just need a solid, dependable electronic checkbook per above.
Suggestions?

Bobreba wrote:
I am using Quicken Essentials 1.7.4 on a [Mac Pro, 2.8 Ghz Quad Core Intel Xeon with 16 Gb of memory], running 10.7.5. I am in the process of upgrading everything to work on Yosemite and Quicken seems to be the most difficult problem to overcome.
Thanks for your response and feedback.
I would recommend you continue with Quicken Essentials. As noted by others, it performs well on Yosemite.
My personal experience is Quicken 2007 for Mac also on 10.7.5 (with many reports of it both updated and successfully running on Yosemite) and I personally would not touch Quicken Essentials with a 10 foot pole -- BUT, if it ain't broke for you, don't fix it!

Forms max user session 11gR2

Hi,
I have three simple questions, can anyone help me to find out the answers.
What is the max user session for oracle forms 11.1.2.1 version?
If the max user sessions limit reached how can we handle it?
How can i get max user session for forms 11.1.2.1 version through sql code?
Thank You!
Dilli Babu. S

What is the max user session for oracle forms 11.1.2.1 version?
How can i get max user session for forms 11.1.2.1 version through sql code?
Not sure what you mean by "max user session", but since you mention sql code, then I have to think that you mean database sessions. If so, you can check out SESSIONS parameter :
SQL> sho parameter sessions
If you mean something different, please clarify.

OK, I'm perplexed. I've been a mac user for almost 30 years. My entire ecosystem is Mac and I remained with mac through the dark 90s. What apple has does in the past 2 years is unbelieveable. I just upgraded to 10.86, then 10.9, no end of problems

OK, I'm perplexed. I've been a mac user for almost 30 years. My entire ecosystem is Mac and I remained with mac through the dark 90s. What apple has does in the past 2 years is unbelieveable. I just upgraded to 10.86, then 10.9, no end of problems.
I can no longer mirror and of my monitors VGA or HDMI, my itunes which supplies iphone and ipad has disabled podcast app so that I can't listen to my favorite programs and I find out after the fact that Office software is not compatible with OSX 8.6.
Forget about the fact that itunes looks like it was developed by a 1980s MS-DOS programmer. Its kludgy, limited and generally does not work.
What does one do? Frankly, I used to use macs because they were like info appliances that just worked. Now the time to manage tech glitches from the company has become way too costly. Sadly, Apple has become Microsoft and Microsoft seems to become Apple.

"... as do the users who are downloading recent OSXs in record numbers."
USUALLY YOU DO NOT KNOW WHAT YOU DOWNLOAD UNTIL YOU HAVE IT !!!
APPLE USED TO HAVE GREAT STUFF BUT OBVIOUSLY TRIES TO INVENT FOR THE SAKE OF INVENTING !!!
THIS IS ACTUALLY A STEP BACKWARDS (TO MS).
CALENDAR & CONTACTS SYNC VIA ICLOUD ONLY IS AN ABSOLUTE NO GO !!!
@APPLE: FIX THIS ASAP !!!

How to set physical min/max values for a scale in xy graph?

Hello,
I have troubles with the way LabView handles physical units in xy graphs. In particular, I use a time scale for the x axis.
The values are timestamps and have the unit [s]. Now I want to read write the min max values for this scale via
property nodes. It seems that the properties for min max do not support the use of the unit I use for the data for
that same axis. This is very inconvenient and I am not even sure which kind of data to use at all for this properties.
Is it simply converting to/from [s] using the unit converter?
(I am using LabView 7.1 for the programm in question).
Thanks,
Olaf

Hi Olaf
"It seems that the properties for min max do not support the use of the unit I use for the data for that same axis."
What are the units you are using? can you make it a littlebit clear.
You can change the units also using Property node.
Just check the attachment once. If that is what you are looking for, then the problem is solved.
Regards
Anil
Message Edited by reddy on 05-23-2006 05:25 AM
Message Edited by reddy on 05-23-2006 05:27 AM
Attachments:
X-Scale.jpg ‏8 KB

Max.value for a sales order

Hi Gurus,
A min.order value can be maintained in Sales order by the condition type AMIW but can any one tell how to maintain max.value for a sales order???
Awaiting your early answers..........
Sunanda.P

hi
in OVA8, there maintain the maximum document value as required.
If not then you need to take help of ABAPer
With the help of ABAper you need to prepare a logic for this maximum order value.
Then Go to sales order user exit userexit_save_document_prepare there u insert logic with the help of abaper.
Based on logic created by ABAPer, while saving the sales order it will check this logic and throw out the error if it exceeds max value
Regards
Edited by: WISH on Aug 4, 2008 6:19 AM

Max users for a chatroom seems to be 30?

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