Menu Item to exit a JavaFX application

Question

Hi. I'm very new to JavaFX so please forgive what may be an obvious question.
Can anyone provide an example of the code to create a menu entry eg File->Exit that will exit a JavaFX app?
I can create the menus but I don't know how to perform the actual exit.
Do I use the setOnAction method? What code performs the actual closing of the app?
Thankyou.
Tony

Answer 1

Hi. Here is an example:
import javafx.application.Application;
import javafx.application.Platform;
import javafx.event.ActionEvent;
import javafx.event.EventHandler;
import javafx.scene.Group;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.stage.Stage;
import javafx.scene.control.*;
public class MenuIt extends Application {
    public static void main(String[] args) {
        Application.launch(args);
    @Override
    public void start(Stage primaryStage) {
        MenuItem menuItem = new MenuItem("Exit");
        final Menu menu = new Menu("File");
        menu.getItems().add(menuItem);
        MenuBar menuBar = new MenuBar();
        menuBar.getMenus().add(menu);
        menuItem.setOnAction(new EventHandler<ActionEvent>() {
            @Override
            public void handle(ActionEvent e) {
                Platform.exit();
        primaryStage.setTitle("Menu sample");
        Group root = new Group();
        Scene scene = new Scene(root, 300, 250);
        root.getChildren().add(menuBar);
        primaryStage.setScene(scene);
        primaryStage.show();
}