Message statement is not working?

I would like to place a message in the following method:
It's defined like this:
Position & cannot be delimited because the position is occupied until &
This is in the program:
MESSAGE: s029(zpom_001) WITH st_hrp1001-objid(8) st_hrp1001-endda(8), display like 'E'.
I inserted the (display like 'E' ) in so I can get the RED 'X' error message. If I take out the display like 'E', it works.
I get the following error:
Three-digit error number XXX required in the "MESSAGE EXXX..." statement.
Thanks for any help you can give?
Jeff

Satish,
That did not work...
If I remove the part of the message ( Display like 'E' ) it works...... But if I want to get a RED X error message, what would I do?
JeffG

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Hi,
One of my thread is already resolved on the following URL : unable to insert rows into the table
DROP TABLE TEMP;
CREATE TABLE TEMP AS SELECT * FROM CASE_101 WHERE 1=2;
DECLARE
S VARCHAR2(200);
STMT VARCHAR2(500);
begin
for C in (select TABLE_NAME INTO S from USER_TABLES where TABLE_NAME like 'CASE%' TABLE_NAME NOT like '%OLD' and Num_ROWS > 0 order by TABLE_NAME) loop
STMT := 'INSERT INTO TEMP SELECT * FROM ';
STMT:=STMT || C.TABLE_NAME;
EXECUTE IMMEDIATE STMT;
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end;
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Please let me know , how can i execute proper way.
Thanks.
Best Regards
Arshad

user13360241 wrote:
Hi,
One of my thread is already resolved on the following URL : unable to insert rows into the table
DROP TABLE TEMP;
CREATE TABLE TEMP AS SELECT * FROM CASE_101 WHERE 1=2;
DECLARE
S VARCHAR2(200);
STMT VARCHAR2(500);
begin
for C in (select TABLE_NAME INTO S from USER_TABLES where TABLE_NAME like 'CASE%' TABLE_NAME NOT like '%OLD' and Num_ROWS > 0 order by TABLE_NAME) loop
STMT := 'INSERT INTO TEMP SELECT * FROM ';
STMT:=STMT || C.TABLE_NAME;
EXECUTE IMMEDIATE STMT;
dbms_output.put_line(c.table_name);
end loop;
end;
i am facing now some different; almost all the tables have same number of columns except in few of tables have some additional columns. As above i am creating a table "TEMP" who has highest column temp(by doing some manual process). The table who has less columns than "TEMP" table : Insert statement will not work. 'INSERT INTO TEMP SELECT * FROM less_columns_table_name'.
Please let me know , how can i execute proper way.
Thanks.
Best Regards
Arshadmore often than not "TEMP" tables are NOT required & are highly inefficient in Oracle.
Either only specify explicit column in TEMP to get data,
or provide value for "extra" column in TEMP

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Hi All,
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It looks like SQL Server or Sybase given that you're using getdate().
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Looking at your statement again, I've noticed the following:
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you haven't given x.market a name - use x.market as market instead
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I have used follwing code to update z table .
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> this
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>
> It does sometimes when you are trying to see the
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Hello,
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----delete row from category if there is not infrastructure to support------
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Hi,
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Delete statement is not working.

Hi,
find the code. Here the delete statement is not working and i am getting sy-subrc = 4. although ,
xe1edp10-idnkd = 34596 and dint_edidd -sdata = 34596.
please help me ...
loop at dekek_x.
loop at dint_edidd where segnam = 'E1EDP10'.
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MOVE dint_edidd-sdata TO xe1edp10.
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1st thing..
i tried this :
tables: edidd, e1edp10.
edidd-sdata = '315934 EA 017'.
WRITE edidd-sdata.
move edidd-sdata to e1edp10.
IF edidd-sdata = e1edp10-idnkd.
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output
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>315934 EA 017
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your loop inside loop doesnt make any sense as they are not related any where.
3rd thing:
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TABLES: edidd, e1edp10.
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MOVE it-sdata TO e1edp10.
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ENDLOOP.
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Message statement is not working?

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