Methods to do increasing in java coding

Question

may i know how to do a selective code to do increasing in java code?
like :
i got numbers 20, 30, 20 ,20
IT IS BEFORE I ENTERED ANY NUMBERS IN !!
uniqueNumber 0
numberOfuniqueNumbers 0
occurrences 0
IF i enter 20 into the system
THEN
uniqueNumber will become 1
numberOfuniqueNumbers will become 1
occurences will become 1
when i enter 20 again
uniqueNumber will become 1
numberOfuniqueNumbers will become 1
BUT
occurrences will become 2
and i dont know how to use if/else method to do the increment of occurences.
is it like this?
IF uniqueNumber ++
occurences +1
or is there any way out for it?

Answer 1

ok, let's pretend that a user can only enter numbers from 1 to 5. And he's decided to input 5 numbers. We declare an integer input array of size 5 and an integer counter array of size 6.
Input array = [1,3,4,1,3]
Counter array = [0,0,0,0,0,0]
uniqueNumbers = 0
Loop through input array:
     1st input array value = 1
     set counter[1]++     
     now counter array = [0,1,0,0,0,0]
     2nd input array value = 3
     set counter[3]++
     now counter array = [0,1,0,1,0,0]
     3rd input array value = 4
     set counter[4]++
     now counter array = [0,1,0,1,1,0]
     4th input array value=1
     set counter[1]++
     now counter array = [0,2,0,1,1,0]
     5th input array value = 3
     set counter[3]++
     now counter array = [0,2,0,2,1,0]
Loop through counter array
     1st counter array value (index 0) = 0, do nothing
     2nd counter array value (index 1) = 2,
          print "1 has 2 occurances"
          uniqueNumbers++ (now it equals 1)
     3rd counter array value (index 2) = 0, do nothing
     4th counter array value (index 3) = 2,
          print "3 has 2 occurances"
          uniqueNumbers++ (now it equals 2)
     5th counter array value (index 4) = 1,
          print "4 has 1 occurances"
          uniqueNumbers++ (now it equals 3)
     6th counter array value (index 5) = 0, do nothing
Print out unique numbers (which equals 3)Now your turn. You can do it! :)