Multiple order sort in xsl

Question

Hi all,
Does anyone know how I would go about doing a multiple order sort through my xsl? For example, sort by name first, then sort those results by date, thanks in advance.

Answer 1

okay, that would work, but i think i have a problem, i have an xml that looks like this:
<?xml version="1.0" encoding="UTF-8" ?>
<report>
- <column_headers>
<heading>Heading1</heading>
<heading >Heading2</heading>
</column_headers>
- <results>
- <row>
<attr1>value1</attr1>
<attr2>value2</attr2>
</row>
- <row>
<attr1>value3</attr1>
<attr2>value4</attr2>
</row>
- <row>
<attr1>consulting agreement</attr1>
<attr2>yesterday</attr2>
</row>
</results>
- <sort default="attr1">
- <order-by id="attr2">
<clause>attr2</clause>
<clause>attr1</clause>
</order-by>
</sort>
</report>
I need to sort the row nodes by attr2 first, then attr1, and i have something like this in my xsl:
<xsl:if test="$sortField != 'default'">
<xsl:for-each select="/report/sort/order-by">
<xsl:variable name="idField" select="@id"/>
<xsl:if test="$idField=$sortField">
<xsl:for-each select="/report/results/row">
<xsl:sort select="*[name()=$newSort]"/> --> i need the sort statements here for both attr2 and attr1, but how do i get them out of the xml whenI don't know beforehand how many clause nodes there will be, or what they will contain
<tr>
<xsl:for-each select="*">
<td class="report">
<xsl:value-of select="."/>
</td>
</xsl:for-each>
</tr>
</xsl:for-each>