My URI

Hello.
I'd like to protect my video (flv/progressive) by assuring
it's requested by a 'valid' swf. Valid means hosted in a valid web
page. In other words, if someone copies the HTML code
(<object/embed>
, and paste it in another web page, the swf will be
loaded but w/o the FLV. Instead an error will be displayed: "you
are not authorized to play video".
What technique can I use (w/o FMS or Flash remoting) to
communicate from swf to non-Flash servers (let's say web server or
servlet)? Based on the response (valid/not valid) I'll jump to the
relevant scene in the swf. I do not want to refresh the web page or
open additional windows/browsers.
I know how to identify the client location (webpage) when
requesting the video - I can rely on one of the URL query
parameters. This parameter is always exist in a valid web page. I
can pass its value for validation, I just don't know how.
Any help would be appreciated.

reem_artsi wrote:
> Hello.
>
> I'd like to protect my video (flv/progressive) by
assuring it's requested
> by a
> 'valid' swf. Valid means hosted in a valid web page. In
other words, if
> someone copies the HTML code (<object/embed>
, and paste it in another web
> page, the swf will be loaded but w/o the FLV. Instead an
error will be
> displayed: "you are not authorized to play video".
>
> What technique can I use (w/o FMS or Flash remoting) to
communicate from
> swf
> to non-Flash servers (let's say web server or servlet)?
Based on the
> response (valid/not valid) I'll jump to the relevant
scene in the swf. I
> do not want to refresh the web page or open additional
windows/browsers.
>
> I know how to identify the client location (webpage)
when requesting the
> video
> - I can rely on one of the URL query parameters. This
parameter is always
> exist in a valid web page. I can pass its value for
validation, I just
> don't know how.
>
> Any help would be appreciated.
You could modify your .htaccess on your server to prevent
hotlinking. See
http://en.wikipedia.org/wiki/.htaccess#Prevent_hotlinking_of_images
for details. However you need to experiment on that because
I'm not sure
Flash sends referrer information when requesting for a flv
file.
Alternatively, you can do it by code in your swf. Check the
_url property
of _level0 and only load your flv is that url is indeed the
url from your
server, otherwise, display an error message. Note that this
second solution
is weak. Anyone knowledgeable in Flash could build their own
swf to load
your flv or even modify your own swf to disable the check
(using a
decompiler for example).
Good luck,
Tim.

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public void processRequest(OAPageContext pageContext, OAWebBean webBean)
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* Initializes the detail employee query.
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Thanks Guaravv,
I'm unable to get this to compile. Here's the errors I'm getting, followed by my controller code. Thanks again!
Project: LANLSupplementalDocs.jpr
C:\oracle\jDeveloper\jdevhome\jdev\myprojects\lanl\oracle\apps\icx\por\req\webui\LANLSupplementalDocsSummaryCO.java
Error(16,46): cannot access class oracle.apps.fnd.framework.webui.beans.OAButtonBean; file oracle\apps\fnd\framework\webui\beans\OAButtonBean.class not found
Error(124,9): class OAButtonBean not found in class lanl.oracle.apps.icx.por.req.webui.LANLSupplementalDocsSummaryCO
Error(124,26): class OAButtonBean not found in class lanl.oracle.apps.icx.por.req.webui.LANLSupplementalDocsSummaryCO
Error(125,9): class OADataBoundValueViewObject not found in class lanl.oracle.apps.icx.por.req.webui.LANLSupplementalDocsSummaryCO
Error(125,47): class OADataBoundValueViewObject not found in class lanl.oracle.apps.icx.por.req.webui.LANLSupplementalDocsSummaryCO
Controller:
/*===========================================================================+
| Copyright (c) 2001, 2005 Oracle Corporation, Redwood Shores, CA, USA |
| All rights reserved. |
+===========================================================================+
| HISTORY |
+===========================================================================*/
package lanl.oracle.apps.icx.por.req.webui;
import oracle.apps.fnd.common.VersionInfo;
import oracle.apps.fnd.framework.webui.OAControllerImpl;
import oracle.apps.fnd.framework.webui.OAPageContext;
import oracle.apps.fnd.framework.webui.beans.OAWebBean;
import oracle.cabo.ui.data.DictionaryData;
import oracle.cabo.ui.data.DataObjectList;
import oracle.apps.fnd.framework.webui.beans.table.OATableBean;
import oracle.apps.fnd.framework.webui.beans.OAButtonBean;
import oracle.apps.fnd.framework.webui.OAWebBeanConstants;
import oracle.apps.fnd.framework.OAViewObject;
import oracle.apps.fnd.framework.OAException;
import oracle.jbo.domain.Number;
import oracle.apps.fnd.framework.OAApplicationModule;
//import oracle.apps.fnd.framework.webui.beans.form.OASubmitButtonBean;
//import oracle.apps.fnd.framework.webui.beans.layout.OASpacerBean;
//import oracle.apps.fnd.framework.webui.beans.layout.OAPageLayoutBean;
* Controller for ...
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public static final String RCS_ID="$Header$";
public static final boolean RCS_ID_RECORDED =
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* @param webBean the web bean corresponding to the region
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super.processRequest(pageContext, webBean);
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try
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I am getting the URI scheme is not file error when I am uploadin a .PDF file
I am using the following piece of code
String lPathPrefix = "gopher://muceap10.muc.amadeus.net/User Step Folders/BPS_Files/Outlooksoft CPM/01 - Production Environment/01 - Documentation Library/01 - Documents/Daily_Checks/";String lPath = (lPathPrefix + doccolvalue).replace(" ", "%20");
URI lURI = new URI(lPath);String lPathPrefix = "file://muceap10.muc.amadeus.net/User Step Folders/BPS_Files/Outlooksoft CPM/01 - Production Environment/01 - Documentation Library/01 - Documents/Daily_Checks/";
String lPath = (lPathPrefix + doccolvalue).replace(" ", "%20");
URI lURI = new URI(lPath);
Can anyone please help me in solving this problem
I will be very much greatful to you,
Thankx.

Did you get to resolve this error? We are also getting the same error and not able to figure out.
Edited by: Joe A on Nov 10, 2008 5:09 PM

Error in using taglib uri in jsp

When i write the following code in my jsp to use the tags, i got the error -
JSP Parsing Error:The absolute uri: http://java.sun.com/jsf/html cannot be resolved in either web.xml or the jar files deployed with this application
And when i used the tld (html_basic.tld & jsf_core.tld), it gave me the error
JSP Parsing Error:Failed to load or instantiate TagLibraryValidator class: com.sun.faces.taglib.html_basic.HtmlBasicValidator

you can use
<taglib>
<taglib-uri>/WEB-INF/html-basic.tld</taglib-uri>
<taglib-location>
/WEB-INF/html-basic.tld
</taglib-location>
</taglib>
<taglib>
<taglib-uri>/WEB-INF/jsf-core.tld</taglib-uri>
<taglib-location>
/WEB-INF/jsf-core.tld
</taglib-location>
</taglib>
in your web.xml

Assigning a URI to a jsp client

Hi
I am trying to proxy a message from my OC client to a jsp client. My proxy servlet registers the URI I am supposed to fwd my message to.
I am not sure if I can assign a URI to my jsp client, and if yes, how?
If not, is there any other way for me to proxy it? I have been able to proxy stuff to an OC client, based on the sip addess, eg. sip:[email protected]:5064; by configuring the sip.xml and using "proxy.proxyTo(xxxxx)"
Some of my code is as follows...
***************ProxyServlet code***********************
package oracle.sdp.proxy;
import java.io.IOException;
import javax.servlet.ServletConfig;
import javax.servlet.ServletException;
import javax.servlet.sip.Proxy;
import javax.servlet.sip.SipFactory;
import javax.servlet.sip.SipServlet;
import javax.servlet.sip.SipServletRequest;
import javax.servlet.sip.SipServletResponse;
import javax.servlet.sip.URI;
@SuppressWarnings("serial")
public class ProxyServlet extends SipServlet
     private URI mForwardUri;
     private URI mForwardUri1;
     private URI mForwardUri2;
     private SipFactory getSipFactory() {
     return (SipFactory) getServletContext()
     .getAttribute(SipServlet.SIP_FACTORY);
     protected void doMessage(SipServletRequest request) throws ServletException,IOException
     log("Received: " + request.getMethod() + " Content: "+ request.getContent());
     try
          ServletConfig config = getServletConfig();
          String forwardUri = config.getInitParameter("forwardAddress");
          mForwardUri = getSipFactory().createURI(forwardUri);
          String forwardUri1 = config.getInitParameter("forwardAddress1");
          mForwardUri1 = getSipFactory().createURI(forwardUri1);
          String forwardUri2 = config.getInitParameter("forwardAddress2");
          mForwardUri2 = getSipFactory().createURI(forwardUri2);
     catch (NumberFormatException e)
     try
     Proxy proxy = request.getProxy();
     proxy.cancel();
     SipServletResponse resp = proxy.getOriginalRequest().createResponse(SipServletResponse.SC_CALL_BEING_FORWARDED, "Forward message to " + mForwardUri);
     resp.send();
     proxy.proxyTo(mForwardUri);//this forwards to OC1 client
     proxy.proxyTo(mForwardUri1);//this forwards to OC2 client
     proxy.proxyTo(mForwardUri2);//this forwards to FinalMessage.java, which is a Recepient servlet
          request.getSession().getApplicationSession().invalidate();
     catch (java.io.IOException ioe)
     log("Failed to send response", ioe);
********sip.xml for proxyservlet*********************
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE sip-app
PUBLIC "-//Java Community Process//DTD SIP Application 1.0//EN"
"http://www.jcp.org/dtd/sip-app_1_0.dtd">
<sip-app>
     <display-name>SIP Servlet Application</display-name>
<servlet>
<servlet-name>ProxyServlet</servlet-name>
<servlet-class>
oracle.sdp.proxy.ProxyServlet
</servlet-class>
<init-param>
<param-name>forwardAddress</param-name>
<param-value>sip:[email protected]:5064</param-value>
</init-param>
<init-param>
<param-name>forwardAddress1</param-name>
<param-value>sip:[email protected]:5062</param-value>
</init-param>
<init-param>
<param-name>forwardAddress2</param-name>
<param-value>sip:@127.0.0.1:5060;transport=tcp;appId=FinalMessage</param-value>
</init-param>
<load-on-startup/>
</servlet>
<servlet-mapping>
<servlet-name>ProxyServlet</servlet-name>
<pattern>
<equal>
<var>request.method</var>
<value>MESSAGE</value>
</equal>
</pattern>
</servlet-mapping>
</sip-app>
Please guide me.
Thanks,
A

The URI has to be of the form
sip:127.0.0.1;transport=xxxx;appId=xxx;
This solved the issue.

My URI

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